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Isospin Symmetry test on the semimagic 44 CrPowerPoint Presentation

Isospin Symmetry test on the semimagic 44 Cr

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## PowerPoint Slideshow about ' Isospin Symmetry test on the semimagic 44 Cr' - samuel-rivers

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T=1 and T=2 mirror nuclei

Shell evolution

Gaps Z=14 and N=14

No cross shell excitations

f7/2

f7/2

N,Z=20

N,Z=20

d3/2

d3/2

s1/2

s1/2

d5/2

d5/2

π

π

ν

ν

36Ca

36S

Cross conjugate nuclei

f7/2

f7/2

N,Z=20

N,Z=20

d3/2

d3/2

s1/2

s1/2

d5/2

d5/2

π

π

ν

ν

44Cr

44Ca

f7/2

f7/2

N,Z=20

N,Z=20

d3/2

d3/2

s1/2

s1/2

d5/2

d5/2

π

π

ν

ν

36Ca

36S

44Cr

f5/2

f5/2

p1/2

p1/2

p3/2

p3/2

f7/2

f7/2

N,Z=20

N,Z=20

π

π

ν

ν

44Cr

44Ca

1360

2+

1248

1157

2+

2+

0+

0+

0+

44Ca

Exp

kb3g

gxpf1a

104

9.8

10.3

B(E2)[e2fm4]

44Cr

p3/2

p3/2

f7/2

f7/2

N,Z=20

N,Z=20

d3/2

d3/2

s1/2

s1/2

π

π

ν

ν

44Cr

44Ca

1571

2+

1360

2+

1248

1157

2+

2+

0+

0+

0+

0+

44Ca

Exp

kb3g

gxpf1a

sdfp

104

9.8

10.3

105.6

B(E2)[e2fm4]

Particle-hole cross-shell excitations

1571

2+

1360

2+

1248

1157

2+

2+

0+

0+

0+

0+

44Ca

Exp

kb3g

gxpf1a

sdfp

104

9.8

10.3

105.6

B(E2)[e2fm4]

49

25Mn24

24Cr25

f7/2 shell and INC nuclear forcesVCm,

VCM

VB

From the MED

we extract information

of nuclear structure

properties

- How the nucleus generates its angular momentum
- Evolution of the deformation along a rotational band
- Isospin non-conserving terms in the nuclear interaction
- Learn about the configuration of the states

Feasibility: fragmentation + knock-out

- Comparison to 36Ca:
- Cross section: /50
- AGATA efficiency: x5
- AGATA resolution: x2
- Energy of the gamma (3.0→ 1.2 MeV): x3
- Beam current: x30 (3*108→1010)

- 44Cr now is a factor 20 easier!

P. Doornenbal et al. Physics Letters B 647 (2007) 237–242

Feasibility: fragmentation + coulex

- Directly produced 44Cr: 24 nbarn
- More than an order of magnitude lost

- Coulex on secondary target
- 2+ predicted collective (2p2h, 4p4h)
- Enhanced B(E2)
- Good excitation cross section (~200 mbarn)

- Factor of ~10 in statistics for the 2+

B(E1) in T=2

- Janecke:
EC (A,T,TZ)= EC0(A,T)- TzEC1(A,T)+ (3Tz2-T(T+1))EC2(A,T)

- Warburton
“Corresponding E1 transition in conjugate nuclei have equal strength”

- T=2 Tz=-2
EC = EC0 + 2 EC1(A,2)+ 6EC2(A,T)

- T=2 Tz=-1
EC = EC0 + 1 EC1(A,2)- 3EC2(A,T)

- T=2 Tz=0
EC = EC0 + - 6EC2(A,T)

- T=2 Tz=+1
EC = EC0 + 1 EC1(A,2)- 3EC2(A,T)

- T=2 Tz=+2
EC = EC0 - 2 EC1(A,2)+ 6EC2(A,T)

WILKINSON - ISOSPIN IN NUCLEAR PHYSICS

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