Hints for activity 10 and individual 5
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Hints for Activity 10 and Individual 5. LSP 121 hints!. Q #2 – at least once. Formula 1 – (Not A in one) n A = exposed to virus, the event P(A) = 1.5% = .015 P(not A) = 1 – P(A) = 1 - .015 = n = 10 for part a) and 20 for part b). Q #3. Expected value

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Hints for Activity 10 and Individual 5

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Hints for activity 10 and individual 5

Hints for Activity 10and Individual 5

LSP 121 hints!


Q 2 at least once

Q #2 – at least once

  • Formula

    1 – (Not A in one)n

    A = exposed to virus, the event

    P(A) = 1.5% = .015

    P(not A) = 1 – P(A) = 1 - .015 =

    n = 10 for part a) and 20 for part b)


Hints for activity 10 and individual 5

Q #3

  • Expected value

    • start with what you pay as (-1) * cost in $

    • then add the probability or probabilities of gaining back each amount of $


Hints for activity 10 and individual 5

Q #4

  • Expected value

  • In this example, start with the cost as 100% x $1, express as negative: -$1

  • To this add the other winnings x probabilities

  • -$1 x 1 + $20 x .012 + etc.

  • Expected value = …


Hints for activity 10 and individual 5

Q #5

  • Possible outcomes

  • Set this up with 10 ‘boxes’:

Area Codes Exchanges Extensions

In each box, write the number of possible #’s that can be found there.

Multiply these numbers to find possible outcomes for

particular event (set of phone numbers or area codes).


Individual assignment 5

individual assignment #5

  • #1: possible outcomes (ski shop packages) is simply the product of the different sets

  • #2: (# of ways to get a 5)/(total outcomes)

  • #5: Example of calculating ‘odds’, usually expressed as a ratio, such as 2:1 or 1:2, read ‘2 to 1’ or ‘1 to 2’. Note: if something has a probability of 50% (for 2 outcomes), then this event has 1:1 odds


Indiv 5 more

indiv #5, more

  • #6: this is an example of multiplication rule #1; the probability of multiple independent occurences is the product of the individual probabilities

  • #7: (total ways of getting 3, 4 or 5) / (total possible outcomes for 2 dice); be careful when calculating ODDs for this same situation.


Indiv 5 more1

indiv #5, more

  • #8:

    • a) empirical probability; do the math

    • b) apply the math and predict for next year

    • c) use ‘at least once’ formula: 1 – (not A)n

  • #9: Use addition of probabilities to calculate ‘expect value’. Note: since this is ‘for the company’, you start with $1000 x 100% + (-$20,000 … ) + (-$50,000 …) + …, since each claim is a ‘loss’ to the company.


Indiv 5 last part

indiv #5 last part

  • #10: This problem is slightly different in that two events are ‘non-mutually exclusive’; the occurrence of one event does not exclude nor is it excluded by another event. Simply work out the formula given:

  • P(A or B) = P(A)+P(B) – P(A and B),

  • = P(king) + P(heart) – P(king and heart)

  • = (# of kings/52) + (# of hearts/52) – (# of king of hearts/52) = …


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