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Building Java Programs

Building Java Programs. Chapter 9: Inheritance and Interfaces Lecture 9-2: Polymorphism reading: 9.2 self-check: #5-9. Polymorphism. polymorphism : Ability for the same code to be used with different types of objects and behave differently with each.

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Building Java Programs

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  1. Building Java Programs Chapter 9: Inheritance and Interfaces Lecture 9-2: Polymorphism reading: 9.2 self-check: #5-9

  2. Polymorphism • polymorphism: Ability for the same code to be used with different types of objects and behave differently with each. • System.out.println can print any type of object. • Each one displays in its own way on the console. • CritterMain can interact with any type of critter. • Each one moves, fights, etc. in its own way.

  3. Coding with polymorphism • A variable of type T can hold an object of any subclass of T. Character rob = new Robot(); • You can call any methods from Character on rob. • You can not call any methods specific to Robot (e.g. sayQuote). • When a method is called on sam, it behaves as a Robot. System.out.println(sam.getAttack()); // 20 System.out.println(sam.toString()); // HP: 100

  4. Polymorphism + parameters • Methods can accept superclass types as parameters. • You can pass any subtype of that superclass. public class TestCharacters { public static void main(String[] args) { KnightWhoSaysNi knight = new KnightWhoSaysNi(); Robot robRobot = new Robot(); basicAbilities(knight); basicAbilities(robRobot); } // prints the result of some of the methods in a Character public static void basicAbilities(Character player) { System.out.println("toString: " + player); System.out.println("getAttack: " + player.getAttack()); System.out.println("isAlive: " + player.isAlive()); System.out.println(); } } • OUTPUT: toString: HP: 100 getAttack: 10 isAlive: true toString: HP: 100 getAttack: 20 isAlive: true

  5. Polymorphism + arrays • Arrays of superclass types can store any subtype as elements. public class TestCharacters2 { public static void main(String[] args) { Character[] c = { new KnightWhoSaysNi(), new Robot(), new Sorcerer(), new Oracle() }; for (int i = 0; i < e.length; i++) { System.out.println("attack: " + c[i].getAttack()); System.out.println("toString: " + c[i].toString()); System.out.println(); } } }

  6. Polymorphism problems • ~4-5 classes with inheritance relationships are shown. • A client program calls methods on objects of each class. • You must read the code and determine the client's output.

  7. A polymorphism problem • Assume that the following four classes have been declared: public class Foo { public void method1() { System.out.println("foo 1"); } public void method2() { System.out.println("foo 2"); } public String toString() { return "foo"; } } public class Bar extends Foo { public void method2() { System.out.println("bar 2"); } }

  8. A polymorphism problem public class Baz extends Foo { public void method1() { System.out.println("baz 1"); } public String toString() { return "baz"; } } public class Mumble extends Baz { public void method2() { System.out.println("mumble 2"); } } • What would be the output of the following client code? Foo[] f = {new Baz(), new Bar(), new Mumble(), new Foo()}; for (int i = 0; i < f.length; i++) { System.out.println(f[i]); f[i].method1(); f[i].method2(); System.out.println(); }

  9. Diagramming the classes • Add classes from top (superclass) to bottom (subclass). • Include all inherited methods.

  10. Finding output with tables

  11. Polymorphism answer Foo[] f = {new Baz(), new Bar(), new Mumble(), new Foo()}; for (int i = 0; i < f.length; i++) { System.out.println(f[i]); f[i].method1(); f[i].method2(); System.out.println(); } • Output: baz baz 1 foo 2 foo foo 1 bar 2 baz baz 1 mumble 2 foo foo 1 foo 2

  12. Another problem • The order of the classes is jumbled up. • The methods sometimes call other methods (tricky!). public class Lamb extends Ham { public void b() { System.out.print("Lamb b "); } } public class Ham { public void a() { System.out.print("Ham a "); b(); } public void b() { System.out.print("Ham b "); } public String toString() { return "Ham"; } }

  13. Another problem 2 public class Spam extends Yam { public void b() { System.out.print("Spam b "); } } public class Yam extends Lamb { public void a() { System.out.print("Yam a "); super.a(); } public String toString() { return "Yam"; } } • What would be the output of the following client code? Ham[] food = {new Lamb(), new Ham(), new Spam(), new Yam()}; for (int i = 0; i < food.length; i++) { System.out.println(food[i]); food[i].a(); System.out.println(); // to end the line of output food[i].b(); System.out.println(); // to end the line of output System.out.println(); }

  14. Class diagram

  15. Polymorphism at work • Lamb inherits Ham's a. a calls b. But Lamb overrides b... public class Ham { public void a() { System.out.print("Ham a "); b(); } public void b() { System.out.print("Ham b "); } public String toString() { return "Ham"; } } public class Lamb extends Ham { public void b() { System.out.print("Lamb b "); } } • Lamb's output from a: Ham a Lamb b

  16. The table

  17. The answer Ham[] food = {new Lamb(), new Ham(), new Spam(), new Yam()}; for (int i = 0; i < food.length; i++) { System.out.println(food[i]); food[i].a(); food[i].b(); System.out.println(); } • Output: Ham Ham a Lamb b Lamb b Ham Ham a Ham b Ham b Yam Yam a Ham a Spam b Spam b Yam Yam a Ham a Lamb b Lamb b

  18. Inheritance Mystery Summary • Draw the inheritance hierarchy • Create the chart • Start from the top of the hierarchy downward • When you see super.something(), copy the contents of the superclasses’s something() method into the chart • When you see a (non-super) method call, copy the method call into the chart • Not the contents of the method call, since this may change depending on inheritance! • Use the chart to write the final output

  19. Building Java Programs Parameters and References Review

  20. Parameters - value semantics • Recall: • For primitives, parameters are initialized by copying the value • For objects, parameters are initialized by copying the reference • An “arrow” to the object is copied (not the array or object itself). • Consequence: • If you change the primitive variable inside the called method, it has no effect on the variable in the scope of the caller • If you change the array or object in the called method, it's the same array or object that the caller has, so the caller’s objects change too! • More practice in section

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