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F1 = 500 lb

Rb. Ya. A. B. Xa. 5’. 5’. 5’. 5’. D. E. F. 5’. F2= 500 lb. G. 5’. F1 = 500 lb. C. ∑X = 0 Xa + Xc = 0 Xa = -Xc Xa = 500 lb ∑Y = 0 -Ya + 500+Rb = 0 Ya = Rb + 500 ∑Ma = 0 Rb.10-500.5-500.15 = 0 10 Rb.= 2500 + 7500 Rb = 1000 lb Ya = 1500 lb. Ya. Rb. A.

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F1 = 500 lb

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  1. Rb Ya A B Xa 5’ 5’ 5’ 5’ D E F 5’ F2= 500 lb G 5’ F1 = 500 lb C

  2. ∑X = 0 • Xa + Xc = 0 • Xa = -Xc • Xa = 500 lb • ∑Y = 0 • -Ya + 500+Rb = 0 • Ya = Rb + 500 • ∑Ma = 0 • Rb.10-500.5-500.15 = 0 • 10 Rb.= 2500 + 7500 • Rb = 1000 lb • Ya = 1500 lb Ya Rb A B Xa 5’ 5’ 5’ 5’ D E F 5’ F2= 500 lb G 5’ F1 = 500 lb C

  3. MENETUKAN GAYA PADA AEGC DALAM KESETIMBNGAN ∑Mg =0 -Xa.10 - Xc.5 + Xe.5 = 0 -500.10 – 500.5 =- 5 Xe Xe = (5000+2500)/5 Xe = 1500 lb ∑Me =0 -Xa.5 - Xc.10 + Xg.5 = 0 -500.5 – 500.10 = -5 Xg Xg = (5000+2500)/5 Xg = 1500 lb Ya Ya Rb A B A Xa Xa 5’ 5’ 5’ 5’ Ye E D E F Xe 5’ F2= 500 lb G G Xg Yg 5’ F1 = 500 lb C C Xc

  4. MENENTUKAN GAYA DI DEF DALAM KEADAAN SETIMBANG ∑X = 0 +Xf- Xe = 0 Xf – 1500 = 0 Xf = 1500 lb ∑Y = 0 -Ye + Yf + 500 = 0 Yf = Ye – 500 1) ∑Mf = 0 -F2.10 + Ye.5 = 0 5.Ye = 500.10 Ye = 5000/5 Ye = 1000 LB 2) SUMBITUSIKAN 2 PADA 1 Yf = 500 lb BESARNYA Yg DIHITUNG DENGAN Ya – Ye – Yg = 0 Yg = 1500 – 100 Yg = 500 lb Ya Rb A B Xa 5’ 5’ 5’ 5’ D E F Yf Ye 5’ E F F2= 500 lb D G 1500 lb 500 lb 5’ F1 = 500 lb C

  5. MENETUKAN GAYA Yg ∑Y = 0 Ya – Ye – Yg = 0 Yg = Ya – Ye Yg = 1500 – 1000 Yg = 500 lb y Ya Ya Rb A B A Xa Xa 5’ 5’ 5’ 5’ E D E F Xe Ye 5’ F2= 500 lb G G Xg Yg 5’ F1 = 500 lb C C Xc

  6. Ya Rb Xa A B 500 lb 5’ 5’ 5’ 5’ B 500 lb D E F 5’ 1500 lb F2= 500 lb E G 500 lb 5’ 500 lb G F1 = 500 lb C

  7. β ∑ ∑ β √

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