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## PowerPoint Slideshow about ' Algebra ' - risa-caldwell

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Problem 1

You are walking up a 500. meter high hill. The trail has an incline of 12 degrees. How far will you walk to get to the top?

Solution 1

- We know angle A (12 degrees) and the length of the opposite side (500. m). We want to know the length of the hypotenuse (H), so we will use the formula
- Sine =
- Substituting in the appropriate values,

Solution 1

Sine 12 = 0.21

Problem 3

- A member on speak series allows people to join for 11$ then pay 1$ for every event attended. What is the maximum events one can attend for a total of 46$?

Solution 3

- We write the equation that shows the cost of speaker series related to number of events attended ( a)
46 = 1. a + 11

46 = a + 11

35 = a

Problem 4

- Find the Discriminant of
V + 4V + 9 = 0

Solution 4

- Discriminant formula is b2 – 4 (a)(c)
Where a = 1, b = 4 and C = 9

Substituting we get

= 42-4(1)(9)

= 16-36

= -20

Problem 5

- Add (4j+8) and (8j+3)

Solution 5

- Add the like terms from the quantities above
- (4j+8) + (8j+3)
= ( 4j+8j) + ( 8+3)

= 12j+ 11

Problem 6

- The population of an industrial town is increasing by 5% every year. If the present population is 1 million, estimate the population five years hence.

Solution 6

- C. I = A-P
=

Solution 6

- Present population, P = 1 million, rate of increase = 5% per annumHence population after 5 years = = 1000000 (1·05)5 = 1276280

Problem 7

- What is the center of the circle
x2 + y2 -144 = 0 ?

Solution 7

- The standard equation of a circle is
( x-h)2 + (y-k)2 = r2

Now comparing with given equation we get

( x-0)2 + (y-0)2 = (12)2

The Center of the circle is (0,0)

Problem 8

- A wedding planner placed orders with a florist five times in the last year . What is the standard deviaton of the number of flowers needed
- 70 Flowers , 90 Flowers , 21 Flowers , 63 Flowers , 91 Flowers

Solution 8

- Mean =
= 67.12

Variance = (70-67.12)2 + (91-67.12)2+ (21-67.12)2+ (63-67.12)2+ (91-67.12)2

=3292.8

Varience =

Solution 8

- Variance = 658.56
- Standard Deviation =

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