# Algebra - PowerPoint PPT Presentation

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Algebra. Upward Bound Math and Science Rahul Raghunathan. Problem 1. You are walking up a 500. meter high hill. The trail has an incline of 12 degrees. How far will you walk to get to the top?. Solution 1.

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Algebra

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## Algebra

Upward Bound Math and Science

RahulRaghunathan

### Problem 1

You are walking up a 500. meter high hill. The trail has an incline of 12 degrees. How far will you walk to get to the top?

### Solution 1

• We know angle A (12 degrees) and the length of the opposite side (500. m). We want to know the length of the hypotenuse (H), so we will use the formula

• Sine =

• Substituting in the appropriate values,

Sine 12 = 0.21

### Problem 3

• A member on speak series allows people to join for 11\$ then pay 1\$ for every event attended. What is the maximum events one can attend for a total of 46\$?

### Solution 3

• We write the equation that shows the cost of speaker series related to number of events attended ( a)

46 = 1. a + 11

46 = a + 11

35 = a

### Problem 4

• Find the Discriminant of

V + 4V + 9 = 0

### Solution 4

• Discriminant formula is b2 – 4 (a)(c)

Where a = 1, b = 4 and C = 9

Substituting we get

= 42-4(1)(9)

= 16-36

= -20

### Solution 5

• Add the like terms from the quantities above

• (4j+8) + (8j+3)

= ( 4j+8j) + ( 8+3)

= 12j+ 11

### Problem 6

• The population of an industrial town is increasing by 5% every year. If the present population is 1 million, estimate the population five years hence.

• C. I = A-P

=

### Solution 6

• Present population, P = 1 million, rate of increase = 5% per annumHence population after 5 years = = 1000000 (1·05)5                   = 1276280

### Problem 7

• What is the center of the circle

x2 + y2 -144 = 0 ?

### Solution 7

• The standard equation of a circle is

( x-h)2 + (y-k)2 = r2

Now comparing with given equation we get

( x-0)2 + (y-0)2 = (12)2

The Center of the circle is (0,0)

### Problem 8

• A wedding planner placed orders with a florist five times in the last year . What is the standard deviaton of the number of flowers needed

• 70 Flowers , 90 Flowers , 21 Flowers , 63 Flowers , 91 Flowers

### Solution 8

• Mean =

= 67.12

Variance = (70-67.12)2 + (91-67.12)2+ (21-67.12)2+ (63-67.12)2+ (91-67.12)2

=3292.8

Varience =

### Solution 8

• Variance = 658.56

• Standard Deviation =