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Stoichiometry. The Study of Quantitative Relationships. What is Stoichiometry?.

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stoichiometry

Stoichiometry

The Study of Quantitative Relationships

what is stoichiometry
What is Stoichiometry?
  • Stoichiometry is the study of quantitative relationships between the amounts of reactants used and the amounts of products produced in a chemical reaction. Stoichiometry is based on the law of conservation of mass.
using stoichiometry
Using Stoichiometry
  • Start with a balanced equation for the chemical reaction!
  • Lead (II) sulfide reacts with oxygen gas to produce lead (II) oxide and sulfur dioxide.
1 st step balanced equation
1st Step: Balanced Equation
  • 2PbS + 3O2 2PbO + 2SO2
analyzing the problem
Analyzing the Problem
  • QUESTION: If 0.60 mole of oxygen were consumed during a chemical reaction between oxygen and lead II sulfide how many GRAMSof lead (II) oxide would be produced?
analyzing the problem1
Analyzing the Problem
  • PROBLEM: Determine the mass of one of the products when the moles of one reactant in a chemical reaction is known.
  • Use a BCA table to make this calculation easier.
using stoichiometry1
Using Stoichiometry
  • Start with the balanced equation for the reaction!
  • Solid lead (II) sulfide reacts with oxygen gas to produce solid lead (II) oxide and sulfur dioxide gas.
  • 2PbS + 3O2 2PbO + 2SO2
the bca table
The BCA Table
  • Equation: 2PbS + 3O2 2PbO + 2SO2Before: ? mol.60 mol0 mol0 molChange - ?mol -.60 mol+__mol__mol
  • _________________________________________________After 0mol0mol?mol?mol
  • The only information we are given is the amount of oxygen consumed.
mole relationships
Mole Relationships
  • From the mole ratios between PbS and O2, we determine we need 0.40 mol of PbSto react 0.60 mol O2.
  • 2PbS + 3O2 2PbO + 2SO2
  • 0.60 mol O2x 2 molPbS=0.40 molPbS

3 mol O2

completed bca table
Completed BCA Table
  • Equation: 2PbS + 3O2 2PbO + 2SO2Before: .40 mol.60 mol0 mol0 molChange -.40mol- .60 mol+.40mol+.40 mol___________________________________________After 0mol0mol.40 mol.40 mol
reality check
Reality Check
  • If we worked in industry, we would report the mass of PbO produced not the moles of PbO produced.
what mass of pbo was produced
What Mass of PbOWas Produced?
  • Using the molar mass of PbO convert 0.40 moles of PbO to grams of PbO.
  • Pb (207.2 g/mol) x 1 = 207.2 g/mol
  • O (16.00 g/mol) x 1 = 16.00 g/mol
  • 207.2 g/mol + 16.00 g/mol = 223.2 g/molPbO
  • 0.40 molPbOx 223.2 g PbO= 89.28 g PbO

1 molPbO

  • 89.28 g PbOis produced in the reaction.
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