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# Quiz Show PowerPoint PPT Presentation

Polynomial Functions. Quiz Show. (11x 5 + 7x 4 – 5x 3 ) + (12x 6 + 6x 4 – 8x). 100A. (3x 2 + 7x – 4) – (10x 2 + 15x + 7). 100B. Multiply (3 x 2 + 2 x + 5) by (5 x + 6). 100C.

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Polynomial Functions

100A

100B

100C

100D

100E

200A

200B

200C

200D

200E

300A

300B

300C

300D

300E

400A

400B

400C

400D

400E

500A

500B

500C

500D

500E

## (11x 5 + 7x 4 – 5x 3) + (12x 6 + 6x 4 – 8x)

12x 6 + 11x 5 + 13x 4 – 5x 3 – 8x

100A

- 7x 2 – 8x – 11

100B

## Multiply (3 x 2 + 2 x + 5) by (5 x + 6)

12x 6 + 11x 5 + 13x 4 – 5x 3 – 8x

100C

## Divide (2x 4 – 15x 2 – 10x + 5) by (x – 3) using long division

Q: 2x 3 + 6x 2 + 3x – 1R: 2

100D

## Divide (x 3 + 5x 2 – 8x + 28) by (5 x – 1) using synthetic division

Q: x 2 + 3x – 1R: 0

100E

- 2 – 10i

200A

- 4

200B

17

200C

- 183

200D

3

200E

## Factorx 3 – 1000

(x2-10)(x+10x+100x2)

300A

(x2-8)(x2+1)

300B

## Factor64 – 125x3

(4 – 5x) (16 + 20x + 25x2)

300C

## Solve3x4 + 12x2 – 15= 0

x = 1; x = - 1; x =

300D

## Solvex3 – 5x2 + 4x– 20 = 0

x = 2; x = - 2; x = 5

300E

## A rectangle has a perimeter of 80 cm. If its width is x, express its area in terms of x. What is the maximum area of the rectangle?

x(40 – x); 400 cm 2

400A

## The volume of a box is given by V(x) = x(10 – x)(10 – 2x). Find the approx. max. volume.

x = 1.67; 9.26 ft 3

400B

## An open box is to be formed by cutting squares from a square sheet of 10 cm on each side. Find the value of x that maximizes the volume.

x = 1.7; 74.1 cm 3

400C

and 5 –

400D

7i and 3 – 7i

400E

500A

## Determine the max. number of zeros and vertices of the polynomial P(x) = 12x 6 + 6x 4 – 8x

6 zeros; 5 vertices

500B

## Given the polynomial P(x) = (x – 5) (x + 6) 4, where is the graph tangent and where does it cross the x-axis?

Tangent @ - 6; crosses @ 5

500C

## Given the polynomial P(x) = – 5x 2 + 7x– 9, describe the behavior of the graph on the right and left

Rises to the left & falls to the right

500D

## Sketch the graph of f(x) = (x + 1)(x – 1)(x – 2)

x = -1; x = 1; x = 2(1.5, -.625); (0, 2); (-2, -12)

500E