Circles and parabolas review
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Circles and Parabolas Review. Equations of the Curves centered at the origin (0,0). Circle Parabola or. Equations for Curves not centered at the origin. Circle Centered at (h, k) Parabola or. Circles.

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Circles and Parabolas Review

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Circles and parabolas review

Circles and ParabolasReview


Equations of the curves centered at the origin 0 0

Equations of the Curves centered at the origin (0,0)

  • Circle

  • Parabola

    or


Equations for curves not centered at the origin

Equations for Curves not centered at the origin

  • Circle

    Centered at (h, k)

  • Parabola

    or


Circles and parabolas review

Circles

Circles are a special type of ellipses. There is a center that is the same distance from every point on the diameter. In the equation the center is at (h, k). The distance from the center to any point on the line is called the radius of the circle. From the equation to find the radius you take the square root of r2.


Parabolas

Parabolas

A parabola is a curve that is oriented either up, down, left, or right. The vertex of the parabola is at (h, k). In the equation the h value added or subtracted to x moves the parabola left and right. If you subtract the value of h the parabola moves to the right. If you add the value of h the parabola moves to the left. Parabolas are symmetrical across the line through the vertex of the parabola.


Problem 1 circle

Problem 1Circle

  • Graph the following equation of a circle

  • (x- 3)2 + (y- 3)2 = 16

  • *Find first before graphing

  • the center for the circle

  • the radius for the circle.


Solution to problem 1

Solution to Problem 1

Center: (3,3)

Radius: 4


Problem 2 parabola

Problem 2Parabola

  • Graph the following equation of the parabola.

  • (x + 2)2 = ½ (y – 1)

  • Determine the following before graphing the equation:

  • Which way does the parabola open?

  • The vertex of the parabola.

  • The focus and the directrix


Solution to problem 2

Solution to Problem 2

Opens up

Vertex: (-2, 1)

To get the Focus:

½ ÷ 4 = ½ ∙ ¼ = 1/8, so

from the vertex (-2, 1)

we stay at -2 and add 1/8

to the y coordinate (1).

Focus: (-2, 9/8)

To get the Directrix:

From the vertex we subtract 1/8 from the y coordinate (1).

Directrix: y = 7/8

(-2, 9/8)

y = 7/8


Problem 3

Problem 3

Click on the correct answer to move to the next problem.

What type of object/ curve is given by the equation below? What is the center of the equation?

A. Circle Center (-2,-10)

B. Circle Center (2,10)

C. Parabola Center (2,10)

D. Parabola Center (-2,-10)


Problem 4

Problem 4

Click the correct answer to continue.

What is the center and the radius of the following circle equation?

A. Center (-1,0) Radius = 10

B. Center (0,1) Radius = 100

C. Center (0,1) Radius = 10

D. Center (-1,0) Radius = 100


Begin homework

Begin Homework

Pages 89-90

(Math Mate 7 is due next class)


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