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Strengths of Acids & Bases

Strengths of Acids & Bases. HCN (aq) + H 2 O (l) H 3 O + (aq) + CN - (aq). Acids:. Strong acids dissociate completely in solution. eg:. HCl (aq)  H + (aq) + Cl - (aq). or. HCl (aq) + H 2 O (l)  H 3 O + (aq) + Cl - (aq).

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Strengths of Acids & Bases

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  1. Strengths of Acids & Bases HCN(aq) + H2O(l) H3O+(aq)+ CN-(aq) Acids: • Strong acids dissociate completely in solution. eg: HCl(aq)  H+(aq)+ Cl-(aq) or HCl(aq) + H2O(l)  H3O+(aq)+ Cl-(aq) [HCl]=[H+]=[H3O+] • Weak acids do not dissociate completely (they reach equilibrium.) eg: [HCN] ≠[H3O+] [HCN] ≠[H3O+] eg: A 1.0M solution of HCl has a [H3O+] of 1.0M, however a 1.0M solution of HCN will have a [H3O+] < 1.0M.

  2. NH3(aq) + H2O(l) NH4+(aq)+ OH-(aq) Bases: • Strong bases dissociate or react completely. eg: NaOH(aq)  Na+(aq)+ OH-(aq) • The concentration of NaOH dissolved equals [OH-]. Note:all of the alkali metal hydroxides are strong bases. (NaOH, KOH, LiOH, etc) • Weak bases do not dissociate or react completely. eg: • Not all of the NH3 will react, therefore the amount of NH4+ produced is not the same as the amount of NH3 initially: [NH4+] <[NH3]

  3. Weak Acid Equilibrium [H+][CN-] [H3O+][CN-] [HCN] [HCN] HCN(aq) H+(aq)+ CN-(aq) HCN(aq) + H2O(l) H3O+(aq)+ CN-(aq) eg: HCN is a weak acid: KA= or: KA= • The greater the KA the stronger the acid (ie: the higher the [H3O+]) • KA values are measured at 25C (see data booklet.) • Changing temperature will change KA.

  4. HCN(aq) H+(aq)+ CN-(aq) (x)(x) [H+][CN-] x2 [HCN] 0.25 0.25 - x eg: What is the pH of 0.25 mol of hydrocyanic acid (HCN) dissolved in 1.0L of solution? KA for HCN is 6.2 x 10-10 I 0.25 M 0 0 C - x + x + x E 0.25 - x x x Assuming x is negligible compared to 0.25 KA= 6.2 x 10-10 = = x = 1.2 x 10-5 M = [H+] pH = -log (1.2x10-5) pH = 4.90 (if this had been HCl the pH would have been 0.60)

  5. H2CO3(aq) H+(aq)+ HCO3-(aq) (3.2x10-4)2 [H+][HCO3-] 0.24 [H2CO3] eg: Calculate KA for carbonic acid (H2CO3) if a 0.24M solution of the acid has a pH of 3.49. pH = 3.49 [H+]= 3.2 x 10-4 M I 0.24 M 0 0 C - 3.2x10-4 + 3.2x10-4 + 3.2x10-4 E 0.24 3.2x10-4 3.2x10-4 KA= KA= =4.3 x 10-7

  6. H3PO4(aq) H+(aq)+ H2PO4-(aq) H2PO4-(aq) H+(aq)+ HPO42-(aq) HPO42-(aq) H+(aq)+ PO43-(aq) Note:Polyprotic acids have a different KA for each H+. eg: KA1 KA2 KA3 And: KA1 >> KA2 >> KA3

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