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3 H 2 + N 2  2 N H 3 K c = 9.60 at 600  C

Reaction Quotient – Q Value of the equilibrium expression for a reaction that is not at equilibrium. 3 H 2 + N 2  2 N H 3 K c = 9.60 at 600  C. What is the value of the reaction quotient Q if you have the following mixture:

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3 H 2 + N 2  2 N H 3 K c = 9.60 at 600  C

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  1. Reaction Quotient – QValue of the equilibrium expression for a reaction that is not at equilibrium 3 H2 + N2  2 NH3 Kc = 9.60 at 600 C What is the value of the reaction quotient Q if you have the following mixture: [N2] = 0.50 M; [H2] = 0.80 M; [NH3] = 0.60 M Q = [NH3]2 = (0.60)2 = 3.60 [H2] 3 [N2] (0.50) 3 (0.80) The reaction is not at equilibrium. Q = K at equilibrium

  2. 3 H2 + N2  2 NH3 Kc = 9.60 at 600 C What is the value of the reaction quotient Q if you have the following mixture: [N2] = 0.50 M; [H2] = 0.80 M; [NH3] = 0.60 M Q = [NH3]2 = (0.60)2 = 3.60 [H2] 3 [N2] (0.50) 3 (0.80) Will the mixture described above produce more product? Since Q is less than K, more product will be produced until Q equals the K value.

  3. Given the following reaction: N2 + O2  2 NO Kc = 1.0 x 10 –5 at 1500 KAn evacuated 0.50 L chamber is filled with 0.400 moles of nitrogen and 0.100 moles of oxygen and heated to 1500 K. What would be the concentration of nitrogen monoxide at equilibrium ? N2 + O 2   2 NO Initial (M) 0.8 0.2 0 Change (M) - x - x + 2x Equil. (M) 0.8 – x  0.8 0.2 – x  0.2 2x 1.0 x 10 –5 = [2x] 2 (0.8) (0.2) x = 6.3 x 10 –4 NO = 2(6.3 x 10 –4) = 0.0013 M

  4. Given the following reaction: N2 + O2  2 NO Kc = 1.0 x 10 –5 at 1500 KA 0.50 L chamber contains 0.400 moles of nitrogen, 0.100 moles of oxygen, and 0.0500 moles of nitrogen monoxide at 1500 K. Is the mixture at equilibrium. If not, who will the mixture change? The mixture is at equilibrium if Q equals K. Q = [NO] 2 = [0.100] 2 = 0.0625 [N2] [O2] (0.8) (0.2) Q is larger than K so the mixture is not at equilibrium. More reactants will be formed as the mixture moves toward equilibrium.

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