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瑞安中学 缪蓓蕾 PowerPoint PPT Presentation


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高考一轮复习. 光合作用 ( 一 ). 瑞安中学 缪蓓蕾. 说明:装置下面部分安装有 LED 灯,上面部分装了大半瓶水,水里种满了海藻。. 猜一猜. 它是什么?. 最为奇特的节能装置 —— 海藻灯. 它的工作原理是什么?. 利用海藻的光合作用。. 光. CO 2 + 12H 2 O C 6 H 12 O 6 +6O 2 +6H 2 O. 叶绿体. 请写出光合作用的总反应式。. 光. H 2 O H + + 1/2O 2 + 2e - ADP + Pi + 能 ATP

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瑞安中学 缪蓓蕾

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7067457

()


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LED


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CO2 +12H2O C6H12O6+6O2+6H2O


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H2O H+ + 1/2O2 + 2e-

ADP + Pi + ATP

NADP+ + H+ + 2e- NADPH

ATP

NADPH


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NADP+ ADP

NADPH ATP

CO2

RUBP RUBP

CO2CO2+


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1CO2


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CO2NADPHATP

ATP NADPH

CO2 CO2 RUBP

ATPNADPH

ATPNADPHADPPiNADP+


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,CO21%CO20.003%,RUBP

1A

ARUBP2


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2CO21%0.003%AB

CO2RUBPRUBP


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3CO20.003%RUBPAB

RUBPRUBP2


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efRUBPRUBP

RUBP

f

CO2

RUBP


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fgf(RUBP(

fCO2RUBP


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NaHSO3ATP(A-D

ABD


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pi

pi

pi

,Pi


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RUBP

oa

ATPNADPH

ac

CO2

ce

fh

ATPNADPH

ef

CO2

h


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691618cbRUBPbaRUBP


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2ADA_________DATP__________


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1.

2.

H2O H+ + 1/2O2 + 2e-

ADP + Pi + ATP + H2O

NADP+ + H+ + 2e- NADPH

ATP

NADPH


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3.CO2CO21CO2


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4.500luxCO20.3%

800luxCO2

CO21%


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(2)

800lux

500lux

5.5000lux?

CO2

5000luxCO21%

1CO2

CO2ATPNADPH

CO21%

CO20.3%


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6. 2

t1 5

t2 5

1

t1

t2

(2)12t15

1.CO21%

800lux

2.CO20.3%

500lux


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CO2M

CO220

c

a

d

b

O

M

O

20 40 /

Aa

BbCc

Dd


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20136 6

At1t2O2

Bt2t3 t2

Ct3t4

Dt4 ADP Pi C3


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t3 t4

,

1.t1

2.t2t2

CO2


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t2

t3

3. t2-t3,RUBP

1A

RUBPRUBP2

2t3ABB

AB

CO2C5C5


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(3)t3CO2C3C5AB

ARUBP2:1

4t3t2

CO2ATPNADPH


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.

1ABC

BCO2

C


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.

1ABC


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2.

1

3.


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2

85

AB

1

2


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3CO2

CO2BCD

CO2BCD

4Mg

B

CD


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CO2

b

a

CO2

(2008)25303025 CO2abc

C

c

A. B.

C. D.


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3

CO2

O2/


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.CO2

A

B

CO2

2

1.AB

ACO2

A

B

B:CO2

CO2

CO2

1

CO2(CO2)

ACO2


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A

B

CO2

1

2.CO2

(1)

(2)

NADPHATPCO2

(3)CO2

(4)CO2

1ACO21B


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CO2330mg/L1000mg/L

CO2

A

BCO2

CCO2

DNaHCO3PHCO2

CO2CO2


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4


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NPMg

NATPNADPH

P ATPNADPH

Mg


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. ABC60kghm-2255kghm-260kghm-2+255kghm-2, 10:00-11:00CO2 CO2/molm-2s-1 /mgg-1 A 10.66 3.07 B 13.04 3.02 C 15.91 3.05 1 ; 2 CO2 CO2 CO2 CO2


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[]

13

23CO2ATP[H]

123

CO2CO2CO2CO2


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[]1

2

3 CO2CO2 O2


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11.118 CO2N2 CO2N215_____________________2______32______________________________24___ __________________47________ 1904 ATP[H] 1016CO2


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210 3


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201126. 83ABCABCBBaOH2AC1__________________________________________________________________________________.2BC_______()_______________________________________________AC___________ ()______________________________


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4.

P P


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()

A.

B.

C.

D.


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[][H]ATP


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1.CO2O2

=+


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1.20136 6

At1t2O2

Bt2t3 t2

Ct3t4

Dt4 ADP Pi C3


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2.20138PEPC

1


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2 CO2

3 8102mols-1 10~14102mols-1

4 PEPC


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3.201329103CO2


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1ATP___,____CO2

21_____CO2___.

32___________

4_____

5___________


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1

CO2

2PEPCRubisco

PEPCRubiscoCO2

3

CO2CO2

4

5


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1

1234RubiscoPEPCFBPSBP

1102

C48lx1500m-2s-1C33lx550molm-2s-110lx1900molm-2s-1

CO2CO2

3-5lx1lx15molm-2s-1lux


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24h24h

2

2

C4-5750603545C3-240502030-3-140451525-5-335421025

12NADPATP345CO2

12NADPATP345


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3CO2

CO2CO2CO2CO21000ppmCO2

CO2CO2CO2CO2CO2CO2CO2

CO2C4CO210ppmC3CO23070ppmlL-1

CO2CO2

CO2

1CO2CO2

2RubiscoRubisco

3


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4O2

O2C3C4

O21O2Rubisco2O2NADP+NADPH3O21O24O2O2-O2-H2O2HO.O21O2O2-H2O2HO.

5

H2O1%

1CO223

6

1NMg2FeMnCuZn3MnClCa4FeCytFe-SCu(PC)S(Fe-S-)5Mg2+H+RubisCO6PiK+


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23.201331 CO CO CO CO CO


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ABC B C CO

ABAB


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12.201326

(l)________

(2)________

(3)________

(4)____


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311d


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1

2B 0.1 mg/L 0.5 mg/L

3B A

4

5ab

6A B AB


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4CO2C5ATP


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16.201333NaCl CO2


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1

2 CO2C6H12O6 C6H12O6

3NaCl 200~250 mmol/L

4


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19.201330

1________________________ CO2 ________________________

2________________

3_______


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NADPHATPCO2Anon

ADPPiNADP+CO2ATPNADPHCO2ATPNADPHATPNADPHCO2ATPNADPHATPNADPHCO2

ATPNADPH+H+ATPNADPHCO2CO2

ATPNADPHCO2


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ATP


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2.

1NaHCO3NaHCO3CO2

2

3

4NaHCO3NaOH


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[2]

A B

Ca/b D90%


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[]a/b0-1010-1010-302a/b3CO2O2a/ba/b=-90%

AC


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1 C3C3C5CO2C3CO21%CO2CO2C5CO22C3CO2C5C321CO21%0.003%BCO2C3C5CO2C53CO2C3CO2C3C3C5C5C3C5CO22C3C3C54CO2CO2C3C3C3[H]ATP


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(1)CO 2 (2)pH (3) pH10.0 (4)(NP) (5)


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[]ACO2CO2CO2BCO2

2ACO2C6H12O6 ,ACO2

1A

31000CO2ABC3

4AA


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CO2CO2C5C3[H]ATPCO2B

CO2ACO2

AACO2CO2CO2C5

1CO2ACO2

2C3C3C6H12O6CO2ACO2

310CO2ACO2C3BCO2C3

4A


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1 2ATP[H] 3AB 4


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