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Newton’s First & Second LawPowerPoint Presentation

Newton’s First & Second Law

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### Newton’s First & Second Law

AP Physics C

Facts about FORCE

- Unit is the NEWTON(N)
- Is by definition a push or a pull
- Can exist during physical contact(Tension, Friction, Applied Force)
- Can exist with NO physical contact, called FIELD FORCES ( gravitational, electric, etc)

Newton’s First Law – The Law of Inertia

NOTE:MASS and WEIGHT are NOT the same thing. MASS never changes

When an object moves to a different planet.

What is the weight of an 85.3-kg person on earth? On Mars=3.2 m/s/s)?

INERTIA – a quantity of matter, also called MASS. Italian for “LAZY”. Unit for MASS = kilogram.

Weight or Force due to Gravity is how your MASS is effected by gravity.

Example Problem

- Sam weighs 270 N on Mercury, and Andy weighs 530 N on Venus. Who has a larger mass? The acceleration due to gravity on Mercury is 3.59 m/s2 and the acceleration due to gravity for Venus is 8.87 m/s2.

Newton’s First Law

There are TWO conditions here and one constraint.

Condition #1– The object CAN move but must be at a CONSTANT SPEED

Condition #2– The object is at REST

Constraint – As long as the forces are BALANCED!!!!! And if all the forces

are balanced the SUM of all the forces is ZERO.

The bottom line: There is NO ACCELERATION in this case AND the object

must be at EQILIBRIUM ( All the forces cancel out).

An object in motion remains in motion in a straight line and at a constant speed OR an object at rest remains at rest, UNLESS acted upon by an EXTERNAL (unbalanced) Force.

Explain Inertia in each of the following situations:

- Crash Dummy http://www.cleanvideosearch.com/media/action/yt/watch?videoId=d7iYZPp2zYY
- Football /Ref
- http://www.youtube.com/watch?v=qLp6qH1Izxw
- Cat
- http://www.youtube.com/watch?v=xlcL-n-6U-o
- Cheetah
- http://www.youtube.com/watch?v=pWWtngjd4oI
- Working in Space and Inertia
- http://www.sciencewithmrnoon.com/physics/unit03.htm
- Straw in Plywood
- http://www.physics.umd.edu/lecdem/services/demos/demosc3/c3-12.htm
- Masses on String
- http://www.physics.umd.edu/lecdem/services/demos/demosc3/c3-03.htm

Free Body Diagrams

FN

- Weight(mg)– Always drawn from the center, straight down
- Force Normal(FN)– A surface force always drawn perpendicular to a surface.
- Tension(T or FT)– force in ropes and always drawn AWAY from object.
- Friction(Ff)-Always drawn opposing the motion.

T

Ff

T

W1,Fg1 or m1g

m2g

A pictorial representation of forces complete with labels.

Normal force

- The force that keeps one object from invading another object is called the normal force
- “Normal” means “perpendicular”
- You can determine the normal force by considering all forces that have components perpendicular to a surface

Example

FN

Fa

Ff

mg

A 10-kg box is being pulled across the table to the right at a constant speed with a force of 50N.

Calculate the Force of Friction

Calculate the Force Normal

Example

FN

Fa

Fay

Ff

30

Fax

mg

Suppose the same box is now pulled at an angle of 30 degrees above the horizontal.

Calculate the Force of Friction

Calculate the Force Normal

Tension

- A pulling force.
- Generally exists in a rope, string, or cable.
- Arises at the molecular level, when a rope, string, or cable resists being pulled apart.

Tension (static 2D)

The sum of the horizontal and vertical components of the tension are equal to zero if the system is not accelerating.

30o

45o

1

2

3

15 kg

30o

45o

1

2

3

15 kg

T1 = 131 N

T2 = 107 N

T3 = 147 N

Problem: Determine the tension in all three ropes.

Friction

Friction is a force that exists between two surfaces that opposes a sliding motion

Fs: Static friction exists before sliding occurs, it prevents movement

Fk: Kinetic friction exists after sliding occurs, it opposes motion once objects are moving

- Ff is directly proportional to Fn(normal force):
- Coefficient of friction ():
- Determined by the nature of the two surfaces
- s is for static friction.
- k is for kinetic friction.
- s > k

μ

Typical Coefficients of Friction

- Values for have no units and are approximate

A block pulled to the right on a rough horizontal surface

- Now Try These Phun Phree Body Diagrams

Fn

Fk

Fa

Fg

Fn

Fa

- A block pulled up a rough incline

Fk

Fg

- Two blocks in contact with each other, pushed to the right on a frictionless surface

Fn

Fn

P’

Fa

P

Fg

Fg

- Two blocks connected by a cord, one is on top of the table, the other is hanging off the side. The table surface is rough, the pulley is frictionless

Fn

T

Fk

T

Fg

Fg

What is the Frictional force in this situation? EXPLAIN

Classroom Practice Problem

- Mass of the block is 500 g
- Force applied is 3 N.
- = 0.75
- The Block is stationary

μs = .196

Sample problem: A 1.00 kg book is held against a wall by pressing it against the wall with a force of 50.00 N. What must be the minimum coefficient of friction between the book and the wall, such that the book does not slide down the wall?

N.F.L and Equilibrium

Since the Fnet = 0, a system moving at a constant speed or at rest MUST be at EQUILIBRIUM.

TIPS for solving problems

- Draw a FBD
- Resolve anything into COMPONENTS
- Write equations of equilibrium
- Solve for unknowns

What if it is NOT at Equilibrium?

If an object is NOT at rest or moving at a constant speed, that means the FORCES are UNBALANCED. One force(s) in a certain direction over power the others.

THE OBJECT WILL THEN ACCELERATE.

Newton’s Second Law

- Tips:
- Draw an FBD
- Resolve vectors into components
- Write equations of motion by adding and subtracting vectors to find the NET FORCE.
- Solve for any unknowns

The acceleration of an object is directly proportional to the NET FORCE and inversely proportional to the mass.

Newton’s 2nd Law

In which direction, is this object accelerating?

The X direction!

So N.S.L. is worked out using the forces in the “x” direction only

FN

Fa

Ff

mg

A 10-kg box is being pulled across the table to the right by a rope with an applied force of 50N. Calculate the acceleration of the box if a 12 N frictional force acts upon it.

Problem: A hockey puck has an initial velocity of 20 m/s. If the puck slide 115m before coming to a stop, what is the coefficient of kinetic friction between the puck and the ice?

μk = .196

Example

A mass, m1 = 3.00kg, is resting on a frictionless horizontal table is connected to a cable that passes over a pulley and then is fastened to a hanging mass, m2 = 11.0 kg as shown below. Find the acceleration of each mass and the tension in the cable.

FN

T

T

m1g

m2g

Non-constant Forces

- Up until this time, we have mainly dealt with forces that are constant. These produce a uniform, constant acceleration.
- Kinematic equations can be used with these forces.
- However, not all forces are constant.
- Forces can vary with time, velocity, and with position.

Calculus Concepts forForces That Vary With Time

- The Derivative
- The derivative yields tangent lines and slopes
- We use the derivative to go from
- position -> velocity -> acceleration

- The Integral
- The integral yields the area under a curve
- Use the integral to go from
- acceleration -> velocity -> position

- In these two approaches, F = ma, so methods for determining or using acceleration are also used to find force

Where does the calculus fit in?

There could be situations where you are given a displacement function or velocity function. The derivative will need to be taken once or twice in order to get the acceleration. Here is an example.

You are standing on a bathroom scale in an elevator in a tall building. Your mass is 72-kg. The elevator starts from rest and travels upward with a speed that varies with time according to:

When t = 4.0s , what is the reading on the bathroom scale (a.k.a. Force Normal)?

4.6 m/s/s

1036.8 N

- Consider a force that is a function of time:
- F(t) = (3.0 t – 0.5 t2)N

- If this force acts upon a 0.2 kg particle at rest for 3.0 seconds, what is the resulting velocity and position of the particle?

vf = 45 m/s

xf = 50.6 m

- Consider a force that is a function of time:
- F(t) = (16 t2 – 8 t + 4)N

- If this force acts upon a 4 kg particle at rest for 1.0 seconds, what is the resulting change in velocity of the particle?

Δv = 1.33 m/s

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