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Chapter 22: The Electric Field II: Continuous Charge Distributions

Chapter 22: The Electric Field II: Continuous Charge Distributions . Section 22-1: Calculating E from Coulomb’s Law.

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Chapter 22: The Electric Field II: Continuous Charge Distributions

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  1. Chapter 22: The Electric Field II: Continuous Charge Distributions Section 22-1: Calculating E from Coulomb’s Law

  2. A conducting circular disk has a uniform positive surface charge density. Which of the following diagrams best represents the electric field lines from the disk? (The disk is drawn as a cross–section.) • 1 • 2 • 3 • 4 • None of the diagrams.

  3. A conducting circular disk has a uniform positive surface charge density. Which of the following diagrams best represents the electric field lines from the disk? (The disk is drawn as a cross–section.) • 1 • 2 • 3 • 4 • None of the diagrams.

  4. An infinite plane lies in the yzplane and it has a uniform surface charge density. The electric field at a distance x from the plane • decreases linearly with x. • decreases as 1/x2. • is constant and does not depend on x. • increases linearly with x. • is undetermined.

  5. An infinite plane lies in the yzplane and it has a uniform surface charge density. The electric field at a distance x from the plane • decreases linearly with x. • decreases as 1/x2. • is constant and does not depend on x. • increases linearly with x. • is undetermined.

  6. A uniform circular ring has charge Q and radius r. A uniformly charged disk also has charge Q and radius r. Calculate the electric field due to the ring at a distance of r along the axis of the ring divided by the electric field due to the disk at a distance of r along the axis of the disk. • 1.0 • 0.60 • 1.7 • 0.50 • 0.85

  7. A uniform circular ring has charge Q and radius r. A uniformly charged disk also has charge Q and radius r. Calculate the electric field due to the ring at a distance of r along the axis of the ring divided by the electric field due to the disk at a distance of r along the axis of the disk. • 1.0 • 0.60 • 1.7 • 0.50 • 0.85

  8. Chapter 22: The Electric Field II: Continuous Charge Distributions Section 22-2: Gauss’s Law

  9. A cubical surface with no charge enclosed and with sides 2.0 m long is oriented with right and left faces perpendicular to a uniform electric field E of (1.6 ´ 105 N/C)in the +x direction. The net electric flux fE through this surface is approximately • zero • 6.4 ´ 105 N · m2/C • 13 ´ 105 N · m2/C • 25 ´ 105 N · m2/C • 38 ´ 105 N · m2/C

  10. A cubical surface with no charge enclosed and with sides 2.0 m long is oriented with right and left faces perpendicular to a uniform electric field E of (1.6 ´ 105 N/C)in the +x direction. The net electric flux fE through this surface is approximately • zero • 6.4 ´ 105 N · m2/C • 13 ´ 105 N · m2/C • 25 ´ 105 N · m2/C • 38 ´ 105 N · m2/C

  11. A surface is so constructed that, at all points on the surface, the E vector points inward. Therefore, it can be said that • the surface encloses a net positive charge. • the surface encloses a net negative charge. • the surface encloses no net charge.

  12. A surface is so constructed that, at all points on the surface, the E vector points inward. Therefore, it can be said that • the surface encloses a net positive charge. • the surface encloses a net negative charge. • the surface encloses no net charge.

  13. A surface is so constructed that, at all points on the surface, the E vector points outward. Therefore, it can be said that • the surface encloses a net positive charge. • the surface encloses a net negative charge. • the surface encloses no net charge.

  14. A surface is so constructed that, at all points on the surface, the E vector points outward. Therefore, it can be said that • the surface encloses a net positive charge. • the surface encloses a net negative charge. • the surface encloses no net charge.

  15. The figure shows a surface enclosing the charges q and –q. The net flux through the surface surrounding the two charges is • q/0 • 2q/0 • –q/0 • zero • –2q/0

  16. The figure shows a surface enclosing the charges q and –q. The net flux through the surface surrounding the two charges is • q/0 • 2q/0 • –q/0 • zero • –2q/0

  17. The figure shows a surface enclosing the charges 2q and –q. The net flux through the surface surrounding the two charges is

  18. The figure shows a surface enclosing the charges 2q and –q. The net flux through the surface surrounding the two charges is

  19. The figure shows a surface, S, with two charges q and –2q. The net flux through the surface is

  20. The figure shows a surface, S, with two charges q and –2q. The net flux through the surface is

  21. A hollow spherical shell of radius 5.36 cm has a charge of 1.91 mC placed at its center. Calculate the electric flux through a portion of the shell with an area of 1.20 ´ 10–2 m2. • 6.48 ´ 105 N.m2/C • 2.16 ´ 105 N.m2/C • 7.20 ´ 104 N.m2/C • 2.16 ´ 101 N.m2/C • None of the above.

  22. A hollow spherical shell of radius 5.36 cm has a charge of 1.91 mC placed at its center. Calculate the electric flux through a portion of the shell with an area of 1.20 ´ 10–2 m2. • 6.48 ´ 105 N.m2/C • 2.16 ´ 105 N.m2/C • 7.20 ´ 104 N.m2/C • 2.16 ´ 101 N.m2/C • None of the above.

  23. A horizontal surface of area 0.321 m2 has an electric flux of 123 N.m2/C passing through it at an angle of 25° to the horizontal. If the flux is due to a uniform electric field, calculate the magnitude of the electric field. • 907 N/C • 423 N/C • 1.10 ´ 10–3 N/C • 2.36 ´ 10–3 N/C • 383 N/C

  24. A horizontal surface of area 0.321 m2 has an electric flux of 123 N.m2/C passing through it at an angle of 25° to the horizontal. If the flux is due to a uniform electric field, calculate the magnitude of the electric field. • 907 N/C • 423 N/C • 1.10 ´ 10–3 N/C • 2.36 ´ 10–3 N/C • 383 N/C

  25. Chapter 22: The Electric Field II: Continuous Charge Distributions Section 22-3: Using Symmetry to Calculate E with Guass’s Law, and Concept Check 22-1

  26. The electric field E in Gauss’s Law is • only that part of the electric field due to the charges inside the surface. • only that part of the electric field due to the charges outside the surface. • the total electric field due to all the charges both inside and outside the surface.

  27. The electric field E in Gauss’s Law is • only that part of the electric field due to the charges inside the surface. • only that part of the electric field due to the charges outside the surface. • the total electric field due to all the charges both inside and outside the surface.

  28. A rod of infinite length has a charge per unit length of l (= q/l). Gauss's Law makes it easy to determine that the electric field strength at a perpendicular distance r from the rod is, in terms of k = (40)–1,

  29. A rod of infinite length has a charge per unit length of l (= q/l). Gauss's Law makes it easy to determine that the electric field strength at a perpendicular distance r from the rod is, in terms of k = (40)–1,

  30. A solid sphere of radius a is concentric with a hollow sphere of radius b, where b > a. If the solid sphere has a uniform charge distribution totaling +Q and the hollow sphere a charge of –Q, the electric field magnitude at radius r, where r < a, is which of the following, in terms of k = (40)–1?

  31. A solid sphere of radius a is concentric with a hollow sphere of radius b, where b > a. If the solid sphere has a uniform charge distribution totaling +Q and the hollow sphere a charge of –Q, the electric field magnitude at radius r, where r < a, is which of the following, in terms of k = (40)–1?

  32. A solid sphere of radius a is concentric with a hollow sphere of radius b, where b > a. If the solid sphere has a uniform charge distribution totaling +Q and the hollow sphere a charge of –Q, the electric field magnitude at radius r, where a < r < b, is which of the following, in terms of k = (40)–1?

  33. A solid sphere of radius a is concentric with a hollow sphere of radius b, where b > a. If the solid sphere has a uniform charge distribution totaling +Q and the hollow sphere a charge of –Q, the electric field magnitude at radius r, where a < r < b, is which of the following, in terms of k = (40)–1?

  34. A solid sphere of radius a is concentric with a hollow sphere of radius b, where b > a. If the solid sphere has a uniform charge distribution totaling +Q and the hollow sphere a charge of –Q, the electric field magnitude at radius r, where r > b, is which of the following, in terms of k = (40)–1?

  35. A solid sphere of radius a is concentric with a hollow sphere of radius b, where b > a. If the solid sphere has a uniform charge distribution totaling +Q and the hollow sphere a charge of –Q, the electric field magnitude at radius r, where r > b, is which of the following, in terms of k = (40)–1?

  36. A sphere of radius 8.0 cm carries a uniform volume charge density r = 500 nC/m3. What is the electric field magnitude at r = 8.1 cm? • 0.12 kN/C • 1.5 kN/C • 0.74 kN/C • 2.3 kN/C • 12 kN/C

  37. A sphere of radius 8.0 cm carries a uniform volume charge density r = 500 nC/m3. What is the electric field magnitude at r = 8.1 cm? • 0.12 kN/C • 1.5 kN/C • 0.74 kN/C • 2.3 kN/C • 12 kN/C

  38. A spherical shell of radius 9.0 cm carries a uniform surface charge density s = 9.0 nC/m2. The electric field magnitude at r = 4.0 cm is approximately • 0.13 kN/C • 1.0 kN/C • 0.32 kN/C • 0.75 kN/C • zero

  39. A spherical shell of radius 9.0 cm carries a uniform surface charge density s = 9.0 nC/m2. The electric field magnitude at r = 4.0 cm is approximately • 0.13 kN/C • 1.0 kN/C • 0.32 kN/C • 0.75 kN/C • zero

  40. A spherical shell of radius 9.0 cm carries a uniform surface charge density s = 9.0 nC/m2. The electric field magnitude at r = 9.1 cm is approximately • zero • 1.0 kN/C • 0.65 kN/C • 0.32 kN/C • 0.13 kN/C

  41. A spherical shell of radius 9.0 cm carries a uniform surface charge density s = 9.0 nC/m2. The electric field magnitude at r = 9.1 cm is approximately • zero • 1.0 kN/C • 0.65 kN/C • 0.32 kN/C • 0.13 kN/C

  42. An infinite plane of surface charge density s = +8.00 nC/m2 lies in the yz plane at the origin, and a second infinite plane of surface charge density s = –8.00 nC/m2 lies in a plane parallel to the yz plane at x = 4.00 m. The electric field magnitude at x = 3.50 m is approximately • 226 N/C • 339 N/C • 904 N/C • 452 N/C • zero

  43. An infinite plane of surface charge density s = +8.00 nC/m2 lies in the yz plane at the origin, and a second infinite plane of surface charge density s = –8.00 nC/m2 lies in a plane parallel to the yz plane at x = 4.00 m. The electric field magnitude at x = 3.50 m is approximately • 226 N/C • 339 N/C • 904 N/C • 452 N/C • zero

  44. An infinite plane of surface charge density s = +8.00 nC/m2 lies in the yz plane at the origin, and a second infinite plane of surface charge density s = –8.00 nC/m2 lies in a plane parallel to the yz plane at x =4.00 m. The electric field magnitude at x = 5.00 m is approximately • 226 N/C • 339 N/C • 904 N/C • 452 N/C • zero

  45. An infinite plane of surface charge density s = +8.00 nC/m2 lies in the yz plane at the origin, and a second infinite plane of surface charge density s = –8.00 nC/m2 lies in a plane parallel to the yz plane at x =4.00 m. The electric field magnitude at x = 5.00 m is approximately • 226 N/C • 339 N/C • 904 N/C • 452 N/C • zero

  46. An infinite slab of thickness 2d lies in the xz–plane. The slab has a uniform volume charge density r. The electric field magnitude at y = b where 0 < b < d is

  47. An infinite slab of thickness 2d lies in the xz–plane. The slab has a uniform volume charge density r. The electric field magnitude at y = b where 0 < b < d is

  48. An infinite slab of thickness 2d lies in the xz–plane. The slab has a uniform volume charge density r. The electric field magnitude at y = b where b > d is

  49. An infinite slab of thickness 2d lies in the xz–plane. The slab has a uniform volume charge density r. The electric field magnitude at y = b where b > d is

  50. An infinite slab of thickness 2d lies in the xz–plane. The slab has a uniform volume charge density r. Which diagram best represents the electric field along the y–axis? E. None of the diagrams.

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