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# 反比例函数与几何面积问题 - PowerPoint PPT Presentation

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## PowerPoint Slideshow about ' 反比例函数与几何面积问题' - pabla

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Presentation Transcript

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y

P

O

A

x

∴k=

∴ = ·OA·PA= | |= |k|=6

∵k>0

∴k=12

y

P

O

A

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（k>0）图象上任意一点，过点P作PA⊥x 轴于A，

y

P

B

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A

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Q

∴OA-OB=0，即OA=OB

∴ △OBQ≌△OAP，∴OP=OQ

y

P

B

O

A

x

Q

①求△BQD和△BDE的面积。

② 试探索QE与BD是什么位置关系？为什么？

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P

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C

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∴OB=CD

∴ = ·BQ·CD= ·BQ·OB= = 6 连接OE

∴ CD∥OB

∴ = = |K|= ×12=6

y

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B

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∴QM∥EN

∴ QM=EN

∴四边形 ENMQ为平行四边形

∴ QE∥BD

B，AC⊥y轴于C，分别交双曲线 y=

(k≠0)于点D、E，则有DE∥BC。

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B

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C