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Bell work 1. Find the measure of the inscribed angles , R, given that their common intercepted TU = 92º. T. •. TU = 92 º. R. •. •. U. Bell work 1 Answer. Angles R = ½ the intercepted arc TU since their intercepted Arc TU = 92º, then Angle R = 46º. T. •. TU = 92 º. R. •. •.

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Bell work 1

Bell work 1

Find the measure of the inscribed angles , R,

given that their common intercepted TU = 92º

T

TU = 92º

R

U


Bell work 1 answer

Bell work 1 Answer

Angles R = ½ the intercepted arc TU since their

intercepted Arc TU = 92º, then Angle R = 46º

T

TU = 92º

R

U


Bell work 2

Bell work 2

A quadrilateral WXYZ is inscribed in circle P, if

∕_ X = 130º and ∕_ Y = 106º , Find the measures of

∕_ W = ? and ∕_ Z = ?

The Quadrilateral WXYZ is inscribed in the circle iff

/ X + / Z = 180º, and

/ W + / Y = 180º

X

Y

130º

106º

P

W

Z


Bellwork 2 answer

Bellwork 2 Answer

From Theorem 10.11

∕_ W = 180º – 106º = 74º and

∕_ Z = 180º – 130º = 50º

The Quadrilteral WXYZ is inscribed in the circle iff

/ X + / Z = 180º, and

/ W + / Y = 180º

X

Y

130º

106º

P

W

Z


Unit 3 circles 10 4 other angle relationships in circles

Unit 3 : Circles: 10.4 Other Angle Relationships in Circles

Objectives: Students will:

1.Use angles formed by tangents and chords to solve problems related to circles

2.Use angles formed by lines intersecting on the interior or exterior of a circle to solve problems related to circles


P 621 theorem 10 12

(p. 621) Theorem 10.12

If a tangent and a chord intersect at a point on a circle, then

the measure of each angle formed is ½ the measure of

its intercepted arc

A

m∕_ 1

= ½ m minor AC

P

m∕_ 2

= ½ m Major ABC

B

Angle 1

Angle 2

C

m


P 621 theorem 10 12 example 1

(p. 621) Theorem 10.12 Example 1

Find the measure of Angle 1 and Angle 2, if

the measure of the minor Arc AC is 130º

A

m minor AC = 130º

P

B

Angle 1

Angle 2

C

m


P 621 theorem 10 12 example 1 answer

(p. 621) Theorem 10.12 Example 1 Answer

The measure of Angle 1 = 65º and

Angle 2 = 115º

A

m minor AC = 130º

P

B

65º = Angle 1

Angle 2 = 115º

C

m


P 621 theorem 10 12 example 2

(p. 621) Theorem 10.12 Example 2

Find the measure of Angle 1, if Angle 1 = 6xº, and

the measure of the minor Arc AC is (10x + 16)º

m minor AC = (10x + 16)º

A

Angle 1= 6xº

P

C

B

m


P 621 theorem 10 12 example 2 answer

(p. 621) Theorem 10.12 Example 2 Answer

Angle 1 = 6xº = ½ Arc AC = ½ (10x + 16)º

6xº = ½ (10x + 16)º

6xº = 5x + 8

x = 8º thus,

Angle 1 = 48º

A

m minor AC = (10x + 16)º

P

Angle 1= 6xº

C

B

m


Intersections of lines with respect to a circle

Intersections of lines with respect to a circle

There are three places two lines can

intersect with respect to a circle.

Outside the cirlce

On the circle

In the circle


P 622 theorem 10 13

(p. 622) Theorem 10.13

If two chords intersect in the interior of a circle , then the

measure of each angle is ½ the sum of the measures of

the arcs intercepted by the angle and its vertical angle.

D

Angle 1

m∕_ 1

= ½ (m AB + m CD)

C

P

Angle 2

A

m∕_ 2

= ½ (mBC + mAD)

B


P 622 theorem 10 13 example

(p. 622) Theorem 10.13Example

Find the value of x.

m CD = 16º

D

C

P

Angle 1

A

m AB = 40º

B


P 622 theorem 10 13 example answer

(p. 622) Theorem 10.13Example Answer

x = ½ (m AB + m CD) = ½ (40º + 16º)

x = ½ (56º)

x = 28 º

m CD = 16º

D

C

P

Angle 1

A

m AB = 40º

B


P 622 theorem 10 14

(p. 622) Theorem 10.14

If a tangent and a secant, two tangents, or two secants

intersect in the exterior of a circle, then the measure of the

angle formed is ½ the difference of the intercepted arcs.

1 Tangent

and 1 Secant

2 Tangents

2 Secants

P

X

B

W

A

2

3

1

Q

Z

R

Y

C

m∕_ 1

= ½ (m BC – m AC)

m∕_ 2

= ½ (m PQR – m PR)

m∕_ 3

= ½ (m XY – m WZ)

B


P 622 theorem 10 14 example 1

(p. 622) Theorem 10.14Example 1

Find the value of x

P

Major Arc PQR

= 266º

Q

R

m∕_ x

= ½ (m PQR - mPR)


P 622 theorem 10 14 example 1 answer

(p. 622) Theorem 10.14Example 1 Answer

m PR = (360º - m PQR) = (360º - 266º) = 94º

x = ½ (m PQR - m PR) = ½ (266º - 94º) = ½ (172º)

x = 86 º

P

Major Arc PQR

= 266º

Q

R

m∕_ x

= ½ (m PQR - mPR)


P 622 theorem 10 14 example 2

(p. 622) Theorem 10.14Example 2

Find the value of x, GF. The m EDG = 210º

The m angle EHG = 68º

E

F

Major Arc EDG

= 210º

D

68º

H

G

m∕_ EHG = 68º

= ½ (m EDG – m GF)


P 622 theorem 10 14 example 2 answer

(p. 622) Theorem 10.14Example 2 Answer

m∕_ EHG = 68º = ½ (m EDG – m GF)

68º = ½ ( 210º - xº )

136º = 210º - xº

xº = 210º - 136º

xº = 74º

E

F

Major Arc EDG

= 210º

D

68º

H

G

m∕_ EHG = 68º

= ½ (m EDG – m GF)


Home work

Home work

PWS 10.4 A

P. 624 (8 -34) even


Journal

Journal

Write two things about “the

intersections of chords, secants, and/or

tangents” related to circles from this lesson.


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