- 147 Views
- Uploaded on
- Presentation posted in: General

Basic Limit Laws

Download Policy: Content on the Website is provided to you AS IS for your information and personal use and may not be sold / licensed / shared on other websites without getting consent from its author.While downloading, if for some reason you are not able to download a presentation, the publisher may have deleted the file from their server.

- - - - - - - - - - - - - - - - - - - - - - - - - - E N D - - - - - - - - - - - - - - - - - - - - - - - - - -

Basic Limit Laws

2.3

If lim x→c f(x) and lim x→c g(x) exist, then

- Sum Law: lim x→c (f(x) + g(x)) exists and lim x→c (f(x) + g(x)) = lim x→c f(x) + lim x→c g(x).
- Constant Multiple Law: For any number k, lim x→c kf(x) exists and lim x→c kf(x) = k lim x→c f(x).
- Product Law: lim x→c f(x)g(x) exists and lim x→c f(x)g(x) = (lim x→c f(x))(lim x→c g(x)).

- Quotient Law: If lim x→c g(x) ≠ 0, then lim x→c f(x)/g(x) exists and lim x→c f(x)/g(x) = lim x→c f(x)
lim x→c g(x).

- Powers & Roots: if p, q are integers with q ≠ 0, then limx→c exists and it equals . Assume that lim x→c f(x) ≥ 0 if q is even, and that lim x→c ≠ 0 if p/q < 0. In particular for n a positive integer, limx→c [f(x)]n = (lim x→c f(x))n and

- lim x→4 x2 + 2x – 7
- lim x→-1

Substitution can be used to evaluate limits when the function is continuous.