1 / 54

EC941 - Game Theory

EC941 - Game Theory. Lecture 1. Francesco Squintani Email: f.squintani@warwick.ac.uk. Syllabus. 1. Games in Strategic F orm Definition and Solution Concepts Applications Readings: Chapter 2, 3, 12 2. M ixed S trategies Nash Equilibrium and Rationalizability

olathe
Download Presentation

EC941 - Game Theory

An Image/Link below is provided (as is) to download presentation Download Policy: Content on the Website is provided to you AS IS for your information and personal use and may not be sold / licensed / shared on other websites without getting consent from its author. Content is provided to you AS IS for your information and personal use only. Download presentation by click this link. While downloading, if for some reason you are not able to download a presentation, the publisher may have deleted the file from their server. During download, if you can't get a presentation, the file might be deleted by the publisher.

E N D

Presentation Transcript


  1. EC941 - Game Theory Lecture 1 Francesco Squintani Email: f.squintani@warwick.ac.uk

  2. Syllabus 1. Games in Strategic Form Definition and Solution Concepts Applications Readings: Chapter 2, 3, 12 2. Mixed Strategies Nash Equilibrium and Rationalizability Correlated Equilibrium Readings: Chapter 4

  3. 3. Bayesian Games Definition Information and Bayesian Games Cournot Duopoly and Public Good Provision Readings: Sections 9.1 to 9.6 4. Bayesian Game Applications Juries and Information Aggregation Auctions with Private Information Readings: Sections 9.7 to 9.8

  4. 5. Extensive-Form Games Definition SubgamePerfection and Backward Induction Applications Readings: Chapters 5, 6 and 7 6. Extensive-Form Games with Imperfect Information Definition Spence Signalling Game Crawford and Sobel Cheap Talk Readings: Chapter 10

  5. 7. Repeated Games Infinitely Repeated Games Nash and Subgame-Perfect Equilibrium Finitely Repeated Games Readings: Chapter 14 and 15 8.Coalitional Games and the Core Ownership and the Distribution of Wealth Horse Trading and House Exchanges Voting and Matching Readings: Chapter 8

  6. 9. Bargaining Ultimatum Game and Hold Up Problem Rubinstein Alternating Offer Bargaining Nash Axiomatic Bargaining Readings: Section 6.2 and Chapter 16 Reference: An Introduction to Game Theory Martin J. Osborne, Oxford University Press, 2003. Assessment: Final Exam (100% of the grade) Office Hours: Wednesday 9:00-11:00 – Room 1.123

  7. Structure of the Lecture • Definition of Games in Strategic Form. • Solution Concepts Nash Equilibrium, Dominance and Rationalizability. • Applications Cournot Oligopoly, Bertrand Duopoly, Downsian Electoral Competition, Vickrey Second Price Auction.

  8. What is Game Theory? • Game Theory is the formal study of strategic interactions. • A strategic interaction involves two or more agents. They maximize their payoffs and are aware that their opponents maximize payoffs. • Applications range from economics to politics, to biology and computer science.

  9. Games in Strategic Form A game in strategic form is • a set of players: {1, 2, …, I} • for each player i, a set Si of strategies si • for each player i, preferences over the set of strategy profiles S={(s1 , …, sI)}, represented by u : S RI (a strategy profile includes one strategy for each player).

  10. Solution Concepts • A solution concept is a mathematical rule to find the solution of a game. • It allows the modeler to formulate a prediction on the play of the interaction she modeled as a game. • Today, we will study 3 solution concepts: • Nash Equilibrium • Dominance • Rationalizability

  11. Nash Equilibrium A (pure-strategy) Nash equilibrium is a strategy profile s∗with the property that no player ican do better by choosing a strategy different from si∗, given that every other player j adheres to sj∗. Definition The strategy profile s∗ is a Nash equilibrium if, for every player i, ui(s∗) ≥ ui(s’i, s−i∗) for every strategy s’i of player i.

  12. There are two main justifications for Nash Equilibrium: • Self-Enforcing Contract. • The players meet and agree before playing on the course of actions s∗. The contract s∗is self-enforcing if no player has reasons to deviate if the others do not. • Learning Equilibrium Play. • The play s∗ is in equilibrium if no player iwould deviate, were she to learn the opponents’ play s-i∗, because of communication, observation, or repetition.

  13. Dominance A player’s strategy strictly dominates another one if it gives a higher payoff, no matter of what other players do. Definition Player i’s strategy si strictly dominates strategy s’i if ui(si, s−i) > ui(s’i, s−i) for every profile s−iof opponents’ strategies. Theorem A strictly dominated strategy si is never part of any Nash equilibrium s∗.

  14. A player’s strategy weakly dominates another strategy if it is always at least as good, and sometimes better. • Definition Player i’s strategy si weakly dominates her strategy s’iif • ui(si, s−i) ≥ ui(s’i, s−i) for every profile s−iof opponents’ strategies • ui(si, s−i) > ui(s’i, s−i) for some profile s−iof opponents’ strategies. • Note There exist games with Nash Equilibria s∗ that include weakly dominated strategies si for some player i.

  15. Player 2 C D Player 1 A B 1, 1 0, 0 0, 0 0, 0 There are two Nash Equilibria: (A,C) and (B,D). The Nash Equilibrium (B,D) is weakly dominated.

  16. Rationalizability Rationalizability is defined via iterated deletion of strictly dominated strategies. Consider a finite game G = (I, S, u). For each player i,and round t = 1, . . . , T, iteratively define the set Xitof strategies of player i as follows. • Xi1 = Si(start with the set of all possible strategies).

  17. For each t = 0, . . . , T − 1, Xit+1is a subset of Xit such that every strategy of player i in Xit that is not in Xit+1 is strictly dominated in the game where the set of strategy of each player j is reduced to Xjt (in each round, delete all strictly dominated strategies). • The final index T is such that no strategyin XiT is strictly dominated in the game where the set of strategies of each player j is reduced to XjT (proceed until no strategy is strictly dominated). The set XiTis the set of rationalizable strategies of player i.

  18. Rationalizability is justified by common knowledge of rationality. Each player is rational: She does not play strictly dominated strategies. Each player knows that every player is rational: She can reduce the game by deleting all players’ strictly dominated strategies from her model of the interaction (the game). Each player knows that every player knows that every player is rational: She deletes all strictly dominated strategies in the reduced game. The procedure is iterated until it stops.

  19. Best Response Correspondences The best response correspondence Biof player i assigns to each profile s-iof opponents’ strategies, the set of player i’s strategies that maximizes her payoff. DefinitionThe best response correspondenceBi of player i is: Bi (s−i) = {siin Si: ui(si, s−i) ≥ ui(s’i, s−i) for all s’iin Si}. PropositionThe strategy profile s∗ is a Nash equilibrium of a game G=(I, S, u) if and only if every player’s strategy is a best response to the other players’ strategies: s∗i belongs to Bi(s∗−i) for every player i.

  20. Prisoner’s Dilemma Two prisoners are separately interviewed. By accusing the other suspect, one’s prison term is reduced. But if they both stayed quiet, they would not be incarcerated. • Players: The two suspects. • Strategies: Each player’s set of strategy is {Quiet, Fink}. • Preferences: Suspect 1’s ordering of the strategy profiles, from best to worst is (F, Q), (Q, Q), (F,F), (Q, F). Suspect 2’s ordering is (Q, F), (Q, Q), (F, F), (F, Q).

  21. Suspect 2 Quiet Fink Suspect 1 Quiet Fink 2, 2 0, 3 3, 0 1, 1

  22. Solutions of Prisoner’s Dilemma Quiet Fink Quiet Fink 0, 3 2, 2 3, 0 1, 1 Fink is the best response of each player, regardless of what the other player does. Fink is the strictly dominant and rationalizable strategy. (Fink, Fink) is the Nash Equilibrium.

  23. Bach or Stravinsky Two daters would rather be together than separate, but dater 1 prefers Bach and dater 2 prefers Stravinsky. • Players: The two daters. • Strategies: Each dater’s strategy set is {Bach, Stravinsky}. • Preferences: Dater 1’s ordering of the strategy profiles, from best to worst is (B, B), (S, S) = (B, S), (S, B). Dater 2’s ordering is (S, S), (B, B) = (S, B), (B, S).

  24. Dater 2 Bach Stravinsky Dater 1 Bach Stravinsky 0, 0 2, 1 0, 0 1, 2 If they can coordinate, either the two daters go to Bach’s concert or to Stravinsky’s concert.

  25. Solutions of Bach or Stravinsky Bach Stravinsky Bach Stravinsky 0, 0 2, 1 0, 0 1, 2 For each player, B is the best response to B, and S is the best response to S. There are two Nash Equilibria, (B, B) and (S, S). All strategies are rationalizable, and none is dominated.

  26. Matching Pennies Player 1 wins if the coins are matched. Player 2 wins if they are not matched. • Players: The two players. • Strategies: Each player’s set of actions is {Head, Tail}. • Preferences: Player 1’s ordering of the strategy profiles, from best to worst, is (H, T) = (T, H), (H, H) = (T, T). Player 2’s ordering is (H, H) = (T, T), (H, T) = (T, H).

  27. Player 2 Head Tail Player 1 Head Tail -1, 1 1, -1 -1, 1 1, -1 There is no sure way to win for either of the players.

  28. Solutions of Matching Pennies Head Tail Head Tail -1, 1 1, -1 -1, 1 1, -1 For player 1, H is the best response to T and viceversa, for player 2, H is the best response to H and T is the best response to T. All strategies are rationalizable and none is dominated. There are no Nash Equilibria.

  29. Cournot Oligopoly • A good is produced by n firms. • Firm i’s cost of producing qi units is Ci(qi). Ci is an increasing function. • The firms' total output is Q = q1 + … + qn. • The market price is P(Q). P is the inverse demand function, decreasing if positive.

  30. Linear Costs and Demand • Firm i’s revenue is qi P(q1 + … + qn). • Firm i’s profit is revenue minus cost: pi(q1 + … + qn) = qi P(q1 + … + qn) - Ci (qi). • Ci(qi) = cqi, i=1, …, n. • P (Q) = a - Q if a > Q, P(Q) = 0 if a < Q. • pi(q1 + … + qn) = qi [a – (q1 + … + qn)] - cqi.

  31. To find the Best Response Functions, differentiate pi with respect to qi, set it equal to zero, and obtain: dpi (q1 + … + qn)/dqi = a – qi – (q1 + … + qn) – c = 0. • Best Response functions: bi (qi) = [a – (q1 + … + qi-1 + qi+1 +…+ q n) – c]/2. • To find the Nash equilibria, we solve the system of best-response functions. • Because this system is linear and symmetric, we equalize qi* across i = 1,…,n: qi* = bi (qi*) = [a – (n-1) qi* – c]/2.

  32. Solving the above equation, we find that the Nash equilibrium quantity is: qi* = [a – c]/(n+1). • Substituting in the formula for the price, we find that the Nash equilibrium price is: pi (qi*) = a – Q* = a – n[a – c]/(n+1) = [a + nc]/(n+1). • The Nash equilibrium profits are: pi (qi*) = qi*[a – Q*] – cqi* = [a – c ]2/(n-1)2.

  33. q2 With n = 2, b1(q2) = [a – q2– c]/2. b2(q1) = [a – q1– c]/2. b1(q2) (q1*, q2*) qi* = [a – c]/3, i = 1,2. [a – c]/3 b2(q1) q1 [a – c]/3

  34. Bertrand Competition • Unlike Cournot competition, firms compete in prices. • The demand function is denoted by D, • if the good is available at the price p, then the total amount demanded is D(p). • The firm setting the lowest price sells to all the market.

  35. Linear Costs and Demand • Ci(qi) = cqi, i=1, …, n. • D(p) = a – p if a > p, D(p) = 0 if a < p. • Let pi = min {pj, j different from i}. • The profit is: pi(p1, …, pn) = (pi – c)(a - pi) if pi < pi, pi(p) = (pi – c)(a - pi)/|{k : pk= pi}| if pi = pi, pi(p) = 0 if pi > pi.

  36. Best-Response Correspondence Suppose that there only two firms, so that pi= pj. • If pj< c, then pi(p) < 0 for pi <pj, pi(p) = 0 for pi > pj: bi(p) = {pi : pi > pj}. pi pj c pi pm

  37. If pj= c, then pi(p) < 0 for pi < pj, pi(p) = 0 for pi >pj: bi(p) = {pi : pi>pj}. • If pj > pm, then bi(p) = {pm}. pi pi pj c c pm pm pj pi pi

  38. If c < pj< pm then pi(p) increases in pj, but discontinuously drops at pi = pj. So, bi(p) = f. The best response correspondence is empty. pi pj c pi

  39. In sum, the best-response correspondence is: • bi(p) = {pi : pi > pj}, if pj< c, • bi(p) = {pi : pi>pj}, if pj= c, • bi(p) = f, if c < pj< pm, • bi(p) = {pm}, if pj> pm. The Nash equilibrium is pi = c, for all i = 1,…,n. Intuitively, selling at any price pi < c yields negative profit. If the lowest industry price were pj> c, then firm i sells to the whole industry at any price pi with c < pi < pj. In equilibrium, pi = c, for all i.

  40. Downsian Electoral Competition • The players are 2 candidatesin an election. • A strategy is a real number x, representing a policy on the left-right political ideology spectrum. • After the candidates choose policies, each citizen votes for the candidate with the policy she prefers. • The candidate who obtains the most votes wins. Candidates care only about winning.

  41. The voters are a continuum with diverse ideologies, with cumulative distribution F. • For any k, a voter with ideology y is indifferent between the policies y - k and y + k. • The median m is such that 1/2 of voters’ has ideologies y > m, and 1/2 has ideologies y < m. So, F (m) = 1/2.

  42. Best Response Functions • Fix the policy x2 of candidate 2 and consider 1’s choice. • Suppose that x2 < m, the case for x2 > m is symmetric. • If candidate 1 chooses x1 < x2 then she wins the votes of citizens with ideology y < ½ ( x1 + x2 ). • Because ½ ( x1 + x2 ) < x2 < m, it follows that F(½ ( x1 + x2 ) ) < ½, so that candidate 1 wins less than ½ of the votes, and loses the election.

  43. If x1 > x2, then candidate 1 wins the votes of citizens with ideology y > ½ ( x1 + x2 ). She wins more or less than ½ of the votes if and only if 1 – F(½ ( x1 + x2 )) > ½. In this case, she wins the election. • This is equivalent to ½ ( x1 + x2 ) < m, i.e. x1 < 2m - x2. • So, b1 (x2) = {x1 : x2 < x1 < 2m - x2 } for x2 < m.

  44. For x2 > m, b1 (x2) = {x1 : 2m - x2 < x1 < x2}. • If x2 = m, then player 1 loses the election unless she plays x1 = m. So b1 (m) = {m}. • By using the best response correspondences the unique Nash Equilibrium is (m, m). The candidates’ political platforms converge to the median policy.

  45. Intuitively, consider any pair of platforms (x1, x2) other than (m, m). One candidate can win the election by deviating and locating e closer to m than x2. Hence (x1, x2) is not a Nash Equilibrium. • If instead x1=m, then candidate 2 loses the election for sure unless she plays x2 = m. Hence (m, m) is a Nash Equilibrium.

  46. Vickrey Second­-Price Auctions • In an “English” auction, n bidders submit increasing bids for a good, until only one is left, who wins the auction. • The price paid by the last bidder is her last bid. • Suppose each bidder’s valuation of the good is independent of the other bidders’ values. For example, Vickrey’smodel applies when the good is a work of art, but not when it is a oil field.

  47. The English auction is equivalent to a sealed-bid auction, in which each bidder decides, before bidding begins, the most she is willing to bid. To win, the bidder with the highest valuation needs to bid slightly more than the second highest maximal bid. If the bidding increment is small, the price the winner pays equals the second highest maximal bid.

  48. Second-Price Auction Game Players: n bidders. Bidder i’s valuation is vi, we order v1> … > vn> 0, without loss of generality. Strategies: bidder i’s maximal bid is bi. Let bi = max {bj: j different from i}. Payoffs: ui(b1, … ,bn) = vi - bi if bi > bi 0 if bi < bi

  49. Nash Equilibria 1. (b*1,… , b*n) = (v1, …, vn). Bidder 1 wins the object, payoff: v1 – b*2 = v1 – v2 > 0. If bidding b1 < v2, she loses the object, the payoff is 0. If bidding b1 > v2, her payoff is v1 – v2 > 0. The payoff of bidders i = 2, …, n is 0. If bidding bi > v1, the payoff is vi – b1 = vi – v1 < 0. If bidding bi < v1, she loses the object, the payoff is 0.

  50. 2. (b*1,… , b*n) = (v1, 0,… , 0) Bidder 1 wins the object, her payoff is v1. The payoff of bidders i = 2, …, n is 0. If bidding bi > v1, the payoff is vi – b1 = vi – v1 < 0. If bidding bi < v1, she loses the object, the payoff is 0. 3. (b*1,… , b*n) = (v2, v1 , 0,… , 0) Bidder 2 wins the object, payoff v2 – b1 = v2 – v2 = 0. To win, bidder i = 1, 3, …, n must bid bi > b2 = v1, so the payoff is vi – b1 < vi – v1 < 0. Any of these bidders’ payoff is at least as good if losing the good.

More Related