1 / 48

Xiaowei Yang xwy@cs.duke

CompSci 356: Computer Network Architectures Lecture 4: Link layer: Encoding, Framing, and Error Detection. Xiaowei Yang xwy@cs.duke.edu. Overview. Review Physical links Link/network performance metrics Bandwidth / throughput Latency / delay Bandwidth * delay product Link layer functions

nora
Download Presentation

Xiaowei Yang xwy@cs.duke

An Image/Link below is provided (as is) to download presentation Download Policy: Content on the Website is provided to you AS IS for your information and personal use and may not be sold / licensed / shared on other websites without getting consent from its author. Content is provided to you AS IS for your information and personal use only. Download presentation by click this link. While downloading, if for some reason you are not able to download a presentation, the publisher may have deleted the file from their server. During download, if you can't get a presentation, the file might be deleted by the publisher.

E N D

Presentation Transcript


  1. CompSci 356: Computer Network ArchitecturesLecture 4: Link layer: Encoding, Framing, and Error Detection Xiaowei Yang xwy@cs.duke.edu

  2. Overview • Review • Physical links • Link/network performance metrics • Bandwidth / throughput • Latency / delay • Bandwidth * delay product • Link layer functions • Encoding • Framing • Error detection • Reliable transmission (if have time)

  3. The simplest network is one link plus two nodes Hi Alice… ?

  4. Each node (e.g. a PC) connects to a network via a network adaptor. The adaptor delivers data between a node’s memory and the network. A device driver is the program running inside the node that manages the above task. Recap: Put bits on the wire • At one end, a network adaptor encodes and modulates a bit into signals on a physical link. • At the other end, a network adaptor reads the signals on a physical link and converts it back to a bit.

  5. Different types of physical links • Wired links • Copper • Fiber optics • Wireless links • Wifi, WiMax, Bluetooth, ZigBee, …

  6. Commonly Used Physical Links • Different links have different transmission ranges • Signal attenuation • Cables • Connect computers in the same building • Leased lines • Lease a dedicated line to connect far-away nodes from telephone companies

  7. Cables • CAT-5: twisted pair • Coaxial: thick and thin • Fiber CAT-5 10BASE2 cable, thin-net 200m 10Base4, thick-net 500m

  8. Leased lines • Tx series speed: multiple of 64Kpbs • Copper-based transmission • DS-1 (T1): 1,544, 24*64kpbs • DS-2 (T2): 6,312, 96*64kps • DS-3 (T3): 44,736, 672*64kps • OC-N series speed: multiple of OC-1 • Optical fiber based transmission • OC-1: 51.840 Mbps • OC-3: 155.250 Mbps • OC-12: 622.080 Mbps

  9. Last mile links • Wired links • POTS: 28.8-56Kbps (Plain old telephone service) • ISDN: 64-128Kbps (Integrated Services Digital Network) • xDSL: 128Kbps-100Mbps (over telephone lines) • Digital Subscriber Line • CATV: 1-40Mpbs (shared, over TV cables) • Wireless links • Wifi, WiMax, Bluetooth, …

  10. xDSL wiring 1.5-8.4Mpbs Central Office Subscriber premises 16-640Kpbs Local loop Runs on existing copper 18,000 feet at 1.544Mbps 9,000 at 8.448 Mbps ADSL 13-55Mpbs OC links Central office Nbrhood optical Network unit Subscriber premises 1000-4500 feet of copper Must install VDSL transmission hardware VDSL (Very high) Symmetric

  11. Wireless links • Wireless links transmit electromagnetic signals through space • Used also by cellular networks, TV networks, satellite networks etc. • Shared media • Divided by frequency and space • FCC determines who can use a spectrum in a geographic area, ie, “licensing” • Auction is used to determine the allocation • Expensive to become a cellular carrier • Unlicensed spectrum • WiFi, Bluetooth, Infrared

  12. Link Performance Metrics Propagation delay How long it takes for one bit to travel from one end of a link to the other end Bandwidth How many bits a link can transmit in a unit time Each bit is a pulse on the wire Must have certain width for the receiver to decode it

  13. Latency and Throughput • Latency of a message = Propagation + Transmit + Queue • Propagation = Distance/SpeedOfWave • Transmit = Size/Bandwidth • Throughput = Size / Latency

  14. Example • 1Mbps, 100ms, 1MB data • Latency = 1MB/1Mbps + 100ms = 8.1s • Throughput = 1MB/8.1s ≈ 1Mbps • 1Gbps, 100ms, 1MB data • Latency = 1MB/1Gbps + 100ms = 108ms • Throughput = 1MB/108ms = 74.1Mbps < 1Gbps • Why?

  15. Delay ×Bandwidth Product • Measures the volume of a pipe • The maximum number of bits can be in transit through the pipe at any given instant • To achieve high throughput, one should keep the pipe full

  16. High speed versus low speed links

  17. Link-layer functions • Most functions are completed by adapters • Encoding • Framing • Error detection • Reliable transmission (if have time)

  18. Overview • Review • Physical links • Link/network performance metrics • Bandwidth / throughput • Latency / delay • Bandwidth * delay product • Link layer functions • Encoding • Framing • Error detection • Reliable transmission (if have time)

  19. Encoding • Encoding is the process to turn binary data (bits, 0s and 1s) into physical signals sent over a physical link • Done by a piece of hardware on a network adaptor • High and low signals, ignore modulation • Simplest one: 1 to high, 0 to low

  20. Non-return to zero • 1 to high, 0 to low • Not good for decoding • Baseline wander • Consecutive 1s or 0s cause the average signal level to drift • Receiver uses it to distinguish high/low signals • Clock recovery • Receiver uses transition to 1s or 0s as clock boundaries to synchronize clock

  21. Solution 1: Nonreturn to zero inverted (NRZI) • A transition from current signal encodes 1 • No transition encodes 0 • Does it solve all problems? • Not for consecutive 0s NRZI

  22. Solution 2: Manchester encoding • Clock XOR NRZ • 1: high  low; 0: low  high • Drawback: doubles the rate at which signals are sent • Baud rate: signal change rate • Bit rate = half of baud rate. 50% efficient

  23. Final solution: 4B/5B • Key idea: insert extra bits to break up long sequences of 0s or 1s • 4-bit of data are encoded in a 5-bit code word • 16 data symbols, 32 code words  choose the good codes that do not have long sequence of 0s • At most one leading 0, two trailing 0s • For every pair of codes, no more than three consecutive 0s • 5-bit codes are sent using NRZI

  24. Exercise: • 00101101 • What’s the high/low signal sequence?

  25. Overview • Link layer functions • Encoding • Framing • Error detection

  26. Framing • Now we’ve seen how to transmit bitstreams • But nodes send blocks of data (frames) • A’s memory  adaptor  adaptor  B’s memory • An adaptor must determine the boundary of frames Block of data

  27. Variety of Framing Protocols • Framing: determining where the frame begins and ends • Why is it an important task of an adaptor? • Frames may belong to different apps • Need to decide when to deliver them • Design choices • Byte-oriented protocols: the smallest unit of data is a byte • Sentinel approach • Byte-counting approach • Bit-oriented protocols • Clock-based framing

  28. Byte-oriented protocols: the sentinel approach • View each frame as a collection of bytes (characters) • Use special characters SYN, ETX to detect frame start and end • What if special characters appear in a data stream? • Insert data link escape (DLE) characters • Character stuffing • Transmitted from the leftmost bit • Binary Synchronous Communication (BISYNC) by IBM in late 60s

  29. Point-to-Point Protocol (PPP) • A data link protocol used to establish a direction connection between two nodes • Internet dialup access • More recent, RFC 1661, 1994 • Flag: 01111110; Address & Control: default • Protocol: demultiplexing • IP, Link Control Protocol, …, • Checksum: two or four bytes • Link Control Protocol • Set up and terminate the link • Negotiate other parameters such as maximum receive unit

  30. Byte-oriented protocols: the byte counting approach • Use a byte count field to detect the end of a frame. • The corruption of the count field may cause back-to-back frame losses • A similar problem may occur in the sentinel approach. • Corrupted ETX • DDCMP by DECNET

  31. Bit-oriented protocols • View a frame as a collection of bits • 01111110 is the beginning and ending sequence • The sequence is also transmitted when the links are idle • Bit-stuffing for data • Sender: inserts a 0 after every five consecutive 1’s • Receiver: after five consecutive 1’s, • If the next bit is 0, removes it • If the next bit is 1 • If the next bit is 0 (i.e. the last 8 bits are 01111110), then frame ends • Else error; discard frame, wait for next 01111110 to receive • Frames are of variable length, dependent on the data • Mainly because of stuffing • High-level data link control (HDLC) protocol

  32. An exercise • Suppose a receiver receives the following bit sequence • 011010111110101001111111011001111110 • What’s the resulting frame after removing stuffed bits? Indicate any error.

  33. Clock-based Framing • STS-1/OC-1 frame • 51.840Mbps • The slowest SONET link • Synchronous Optical Network (SONET) • A complex protocol • Each frame is 125 us long, 810bytes = 125 us * 51.84Mbps • 9 rows of 90 bytes each • First 3 bytes are overhead • First two bytes of each frame has a special pattern marking the start of a frame • When the special pattern turns up in the right place enough times (every 810B), a receive concludes it’s in sync.

  34. Synchronized timeslots as placeholder • Real frame data may float inside

  35. Overview • Link layer functions • Encoding • Framing • Error detection

  36. Error detection • Error detection code adds redundant information to detect errors • Analogy: sending two copies of the same message • Parity • Checksum • CRC • Error correcting code: more sophisticated code that can correct errors

  37. Two-dimensional parity • Even parity bit • Make an even number of 1s in each row and column • Detect all 1,2,3-bit errors, and most 4-bit errors A sample frame of six bytes

  38. Internet checksum algorithm • Basic idea • Add all the words transmitted and then send the sum. • Receiver does the same computation and compares the sums • IP checksum • Adding 16-bit short integers using 1’s complement arithmetic • Take 1’s complement of the result • Used by lab 1 and lab 2 to detect bit errors

  39. 1’s complement • -x is each bit of x inverted • If there is a carry bit, add 1 to the sum • Example: 4-bit integer • -3: 1100 (invert of 0011) • -4: 1011 (invert of 0100) • -3 + -4 = 0111 + 1 = 1000 (invert of 0111 (8))

  40. IP checksum implementation • uint16_t cksum (const void *_data, int len) { const uint8_t *data = _data; uint32_t sum; for (sum = 0;len >= 2; data += 2, len -= 2)   sum += data[0] << 8 | data[1]; if (len > 0)   sum += data[0] << 8; while (sum > 0xffff)   sum = (sum >> 16) + (sum & 0xffff); sum = htons (~sum); return sum ? sum : 0xffff;}

  41. Remarks • Can detect 1 bit error • But not all two-bits • One increases the sum, and one decreases it • Efficient for software implementation • Needs to be done for every packet inside a router!

  42. Cyclic Redundancy Check A branch of finite fields High-level idea: Represent an n+1-bit message with an n degree polynomial M(x) Divide the polynomial by a k-bit divisor C(x) k-bit CRC: remainder after divided by a degree-k divisor polynomial Send Message + CRC that is dividable by C(x)

  43. Polynomial arithmetic modulo 2 • B(x) can be divided by C(x) if B(x) has higher degree • B(x) can be divided once by C(x) if of same degree • Remainder of B(x)/C(x) = B(x) – C(x) • Substraction is done by XOR each pair of matching coefficients

  44. CRC algorithm • Multiply M(x) by x^k. Add k zeros to Message. Call it T(x) • Divide T(x) by C(x) and find the remainder • Send P(x) = T(x) – remainder • Append remainder to T(x) • P(x) dividable by C(x)

  45. An example 8-bit msg 10011010 Divisor (3bit CRC) 1101

  46. How to choose a divisor Complicated Intuition: unlikely to be divided evenly by an error Corrupted msg is P(x) + E(x) If E(x) is single bit, then E(x) = xi If C(x) has the first and last term nonzero, then detects all single bit errors Find C(x) by looking it up in a book

  47. Hardware implementation Very efficient: XOR operations 0 to k-1 registers (k-bit shift registers) If nth (n < k) term is not zero, places an XOR gate x3 + x2 + 1

  48. Summary • Link performance metrics reviewed • Link layer functions • Encoding • Framing • Error detection • Parity, Checksum, CRC • Next lecture • Reliable transmission • Multi-access link

More Related