Tm 661 engineering economics
This presentation is the property of its rightful owner.
Sponsored Links
1 / 57

TM 661 Engineering Economics PowerPoint PPT Presentation


  • 78 Views
  • Uploaded on
  • Presentation posted in: General

TM 661 Engineering Economics. Depreciation & Taxes. Taxable Income. + Gross Income - Depreciation Allowance - Interest on Borrowed Money - Other Tax Exemptions = Taxable Income. Corporate Tax Rate. Corporate Tax.

Download Presentation

TM 661 Engineering Economics

An Image/Link below is provided (as is) to download presentation

Download Policy: Content on the Website is provided to you AS IS for your information and personal use and may not be sold / licensed / shared on other websites without getting consent from its author.While downloading, if for some reason you are not able to download a presentation, the publisher may have deleted the file from their server.


- - - - - - - - - - - - - - - - - - - - - - - - - - E N D - - - - - - - - - - - - - - - - - - - - - - - - - -

Presentation Transcript


Tm 661 engineering economics

TM 661 Engineering Economics

Depreciation

&

Taxes


Taxable income

Taxable Income

+ Gross Income

- Depreciation Allowance

- Interest on Borrowed Money

- Other Tax Exemptions

= Taxable Income


Corporate tax rate

Corporate Tax Rate


Corporate tax

Corporate Tax

Ex: Suppose K-Corp earns $5,000,000 in revenue above manufacturing and operations cost. Suppose further that depreciation costs total $800,000 and interest paid on short and long term debt totals $1,500,000. Compute the tax paid.


After tax cash flow

After Tax Cash Flow

+ Gross Income

- Interest

= Before Tax Cash Flow

- Tax

= After Tax Cash Flow


After tax cash flow1

After Tax Cash Flow

Ex: Suppose K-Corp earns $5,000,000 in revenue above manufacturing and operations cost. Suppose further that depreciation costs total $800,000 and interest paid on short and long term debt totals $1,500,000. Compute the after tax cash flow.


After tax cash flow2

After Tax Cash Flow

Gross Income $ 5,000,000

Depreciation- 800,000

Interest - 1,500,000

Before Tax Cash Flow $ 2,700,000


Methods of depreciation

Methods of Depreciation

  • Straight Line (SL)

  • Sum-of-Years Digits (SYD)

  • Declining Balance (DB)

    • Prior to 1981

  • Accelerated Cost Recovery System (ACRS)

    • 1981-86

  • Modified Accelerated Cost Recovery (MACRS)

    • 1986 on


Straight line sld

Straight Line (SLD)

Let

P = Initial Cost

n = Useful Life

s = Salvage Value year n

Dt = Depreciation Allowance in year t

Bt = Unrecovered Investment (Book Value) in year t

Then

Dt = (P - S) / n

Bt = P - [ (P - S) / n ]t


Ex straight line depr

Ex: Straight Line Depr.

Let

P = $100,000

n = 5 years

s = $ 20,000

Then

Dt = (P - S) / n

= $ 16,000

B5 = P - [ (P - S) / n ] 5

= $ 20,000


Declining balance

Declining Balance

In declining balance, we write off a constant

% , p, of remaining book value

D1 = pP ,P = initial cost

B1 = P - D1 = P - pP

= P(1-p)

D2 = pB1

= pP(1-p)


Declining balance1

Declining Balance

In declining balance, we write off a constant

% , p, of remaining book value

B2 = B1 - D2 = P(1-p) - pB1

= P(1-p) - pP(1-p)

= P(1-p)[1 - p]

= P(1-p)2


Ex declining balance

Ex: Declining Balance

P = $100,000 n = 5 years S = $20,000

p = 2/5 (200% declining balance)

Then

D1 = (2/5)(100,000) = $ 40,000

B1 = 100,000 - 40,000 = $ 60,000

D2 = (2/5)(60,000) = $ 24,000

D5 = ? ,B5 = ?


Time value of tax savings tax rate 40

Time Value of Tax Savings(Tax Rate = 40%)


Ddb sl conversion salvage 0

DDB/SL Conversion(Salvage = $0)


Class problem

Class Problem

Ex: Suppose K-Corp is interested in purchasing a new conveyor system. The cost of the conveyor is $180,000 and may be depreciated over a 5 year period. K-Corp uses 150% declining balance method with a conversion to straight line. Compute the depreciation schedule over the 5 year period.


Class problem1

Class Problem


Ddb sl conversion half year convention

DDB/SL Conversion(Half-Year Convention)


Class problem2

Class Problem

A $180,000 piece of machinery is installed and is to be depreciated over 5 years. You may assume that the salvage value at the end of 5 years is $ 0. The method of depreciation is to be double declining balance with conversion to straight line using the half-year convention (you may only deduct 1/2 year of depreciation in year 1). Establish a table showing the depreciation and the end of year book value for each year.


Class problem3

Class Problem


Macrs tables

MACRS Tables


Modified accelerated cost

Modified Accelerated Cost

Property Classes

3 yr. - useful life < 4 yrs.

autos, tools

5 yr. - 4 yrs. < useful life < 10 yrs.

office epuipment, computers, machinery

7 yr. - 10 < UL < 16

office furniture, fixtures, exploration

10 yr. - 16 < UL < 20

vessels, tugs, elevators (grain)

15 yr. - 20 < UL < 25

data communication, sewers, bridges, fencing


Macrs cont

MACRS (Cont.)

20 yr. - UL > 25

farm buildings, electric generation

27.5 - residential rental property

31.5 - non-residential real property

Depreciation

class (3, 5, 7, 10 yr.) uses 200% declining balance switching to straight-line @ optimal year

class (15, 20) 150% DB switch to SLD

class (27.5, 31.5) use straight-line


After tax cash flow3

After Tax Cash Flow

Formulas

BTCF = Before Tax Cash Flow

= Revenues - Expenses

TI = Taxable Income

= Cash Flow - Interest - Depreciation

Tax = TI * Tax Rate

ATCF = After Tax Cash Flow

= BTCF - Tax


Ex after tax cash flow

Ex: After Tax Cash Flow


Borrowed money

Borrowed Money


Class problem4

Class Problem

A company plans to invest in a water purification system (5 year property) requiring $800,000 capital. The system will last 7 years with a salvage of $100,000. The before-tax cash flow for each of years 1 to 6 is $200,000. Regular MACRS depreciation is used; the applicable tax rate is 34%. Construct a table showing each of the following for each of the 7 years.


Solution

Solution


Solution1

Solution


Residential rental

Residential Rental


Macrs ads election

MACRS - ADS Election

  • Straight Line with either a half-year or half-month convention.

  • Required for property

    • outside U.S.

    • having tax-exempt status

    • financed by tax-exempt bonds

    • covered by executive order


Example

Example

Ex: A press forming machine is purchased for the manufacture of steel beams for $300,000. The press is considered a 7 year property class (MACRS-GDS = 7). Compute the annual depreciation using the MACRS Alternative Depreciation Election.


Example1

Example

Soln: MACRS - ADS has a longer life than does MACRS - GDS. In this case 14 years.

Dn= $300,000/14

= $21,428n = 2, . . ., 14

= $21,428 / 2

= $10,714n = 1, 15


Units of production method

Units of Production Method

  • Allows for equal depreciation for each unit of output

    where

    Ut = units produced during the year

    U = total units likely to be produced during life

    (P-F) = depreciable amount allowed


Operating day method

Q

=

-

t

D

(

P

F

)

t

Q

Operating Day Method

  • Allows for equal depreciation for each unit of output

    where

    Qt = total hours used during the year

    Q = total hours available during the year

    (P-F) = depreciable amount allowed


Income forecast method

R

=

-

t

D

(

P

F

)

t

R

Income Forecast Method

  • Allows for equal depreciation for each unit of output

    where

    Rt = rent income earned during the year

    R = total likely rent to be earned during life

    (P-F) = depreciable amount allowed


Depletion method

Depletion Method

  • Allows for equal depreciation for each unit of output

    where

    Vt = volume extracted during the year

    V = total volume available in reserve

    (P-F) = depreciable amount allowed

V

=

-

t

D

(

P

F

)

t

V


Example2

Example

Ex: NorCo Oil has a 10 year, $27,000,000 lease on a natural gas reservoir in western South Dakota. The reservoir is expected to produce 10 million cubic ft. of gas each year during the period of the lease. Compute the expected depletion allowance for each year.


Example3

Example

Ex:


Percentage depletion

Percentage Depletion

  • Depletion is taken as a constant percentage of gross income

    Allowable Percentages

    Oil/Gas15%

    Natural Gas22%

    Sulphur/Uranium22%

    Gold, silver, …15%

    Coal10%


Example4

Example

Ex: NorCo Oil has a 10 year, $27,000,000 lease on a natural gas reservoir in western South Dakota. The reservoir is expected to produce 10 million cubic ft. of gas each year during the period of the lease at $1.50 per cubic ft.

Gross Income = 1.5(10,000,000)

= 15,000,000

Depletion= 15,000,000 (0.22)

= $3,300,000


Capital gains losses

Capital Gains/Losses

  • Compute net long/short term gains or losses

    Short-term gains$20,000

    Short-term losses- 28,500

    Net short term loss($ 8,500)

    Long term gains 85,000

    Long term losses- 19,500

    Net long term gain$ 65,500


Gain consolidation

Gain Consolidation

  • Compute net long/short term gains or losses

    Net long term gain$ 65,500

    Net short term loss($ 8,500)

    Net Capital gain$ 57,000


Gain consolidation1

Gain Consolidation

  • Compute net long/short term gains or losses

    Net long term gain$ 65,500

    Net short term loss($ 8,500)

    Net Capital gain$ 57,000

    Taxed as ordinary (35%)$ 19,950

    Taxed at capital gain (28%)$ 15,960


Example5

Example

K-Corp earned $ 750,000 as ordinary income and has $100,000 in net capital gain. Compute the tax on the net capital gain.


Example6

Example

K-Corp earned $ 60,000 as ordinary income and has $100,000 in net capital gain. Compute the tax on the net capital gain.


Example7

Example

K-Corp earned $ 300,000 as ordinary income and has $100,000 in net capital LOSS. Compute the tax on the net capital gain.

A Net Capital Loss may be carried back up to 3 years or carried forward up to 5 years to offset other net capital gains.


Example8

Example

Suppose K-Corp had the following NI, Gains, and taxes in the 3 previous years.

1995 1996 1997

Net Income500,000700,000650,000

Capital Gain(80,000)120,000 50,000

Tax170,000238,000221,000

Gain Tax 0 33,600 14,000

Total Tax170,000271,600235,000


Example9

Example

We would carry this year’s net loss back to 1996 to offset net capital gain giving

1995 1996 1997

Net Income500,000700,000650,000

Capital Gain(80,000) 20,000 50,000

Tax170,000238,000221,000

Gain Tax 0 5,600 14,000

Total Tax170,000243,600235,000


Depreciation recapture

Depreciation Recapture

Ex: K-Corp purchases a Loader for $250,000 which has a 7 year property class life. After 3 years, $140,675 has been depreciated and the book value is now $109,325. K-Corp now sells the loader for $150,000.


Depreciation recapture1

Depreciation Recapture

Ex: K-Corp purchases a Loader for $250,000 which has a 7 year property class life. After 3 years, $140,675 has been depreciated and the book value is now $109,325. K-Corp now sells the loader for $150,000.

Recapture = 150,000 - 109,325

= $40,675


Depreciation recapture2

Depreciation Recapture

Ex: Suppose K-Corp were able to sell this same loader for $ 275,000.

Capital Gain = 275,000 - 250,000

= $25,000

Depr. Recapture = 250,000 - 109,325

= $140,675


Depreciation recapture3

Depreciation Recapture

Ex: Suppose K-Corp were able to sell this same loader for $ 275,000.

Capital Gain = 275,000 - 250,000

= $25,000

Depr. Recapture = 250,000 - 109,325

= $140,675

$ 25,000 taxed at 28%

$140,675 taxed at 35%


Depreciation recapture4

Depreciation Recapture

Non residential or commercial real property

IfThen

Ft > PFt - P is section 1231 capital gain

Bt < Ft < PFt - Bt recaptured as ordinary income

Ft < BtBt - Ft is section 1231 loss

Residential or Commercial real property

IfThen

Bt < FtFt - Bt is section 1231 gain

Ft < BtBt - Ft is section 1231 loss


Investment tax credit

Investment Tax Credit

  • Stimulate investment by providing reduced taxation in year in which asset is placed in service.

  • On-again, off-again

  • Repealed in 1985 with tax rate 46% 35%


Investment tax credit1

Investment Tax Credit

K-Corp purchases a CNC machine for $100,000.

ITC = 100,000(0.10) = 10,000

Initial Cost Basis (for depreciation) is reduced 5%

Padj = 100,000(.95) = 95,000


  • Login