Loading in 5 sec....

[B] y - Exp 1 and 2 B doubles and A remains constantPowerPoint Presentation

[B] y - Exp 1 and 2 B doubles and A remains constant

- 54 Views
- Uploaded on
- Presentation posted in: General

[B] y - Exp 1 and 2 B doubles and A remains constant

Download Policy: Content on the Website is provided to you AS IS for your information and personal use and may not be sold / licensed / shared on other websites without getting consent from its author.While downloading, if for some reason you are not able to download a presentation, the publisher may have deleted the file from their server.

- - - - - - - - - - - - - - - - - - - - - - - - - - E N D - - - - - - - - - - - - - - - - - - - - - - - - - -

You must determine determine the rate law for the following reaction from the experimental results given A + 3 B AB3

Experimental Results

[A] M[B] M Rate [B]/s

Exp. 1 0.0100.200 3.10 x 10 -5

Exp. 2 0.0100.400 2.50 x 10 -4

Exp. 3 0.0200.600 1.67 x 10 -3

[B] y - Exp 1 and 2

B doubles and A remains constant

The rate increases approximately 8 fold

therefore exponent y must be 3

Experimental Results

[A] M[B] M Rate [B]/s

Exp. 1 0.0100.200 3.10 x 10 -5

Exp. 2 0.0100.400 2.50 x 10 -4

Exp. 3 0.0200.600 1.67 x 10 -3

[A] x Requires calculation since no two experiments have the same concentration for B.

Solve for exponent x as an unknown using an equation

formed by the ratio of the two experiments and including the previously determined exponent.

Exp 30.00167 = k [0.020] x [0.600]3

Exp 2 0.00025 = k [0.010] x [0.400]36.68 = 2 x (3.375)

1.979 = 2 x x 1

A + 3 B AB3

Experimental Results

[A] M[B] M Rate [B]/s

Exp. 1 0.0100.200 3.10 x 10 -5

Exp. 2 0.0100.400 7.98 x 10 -4

Exp. 3 0.0200.600 1.67 x 10 -3

rate = k [A] [B]3

Solve for k using one of the exp results

Exp 1 3.10 x 10 -5 = k [0.010] [0.200]3

k = 0.3875 = 0.39 M-3 s-1