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1.3 Segments and Their MeasuresPowerPoint Presentation

1.3 Segments and Their Measures

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1.3 Segments and Their Measures

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1.3 Segments and Their Measures

- Use segment postulates.
- Use the Distance Formula to measure distances as applied.

- In geometry, rules that are accepted without proof are called postulates, or axioms. Rules that are proved are called theorems. In this lesson, you will study two postulates about the lengths of segments.

The points on a line can be matched one to one with the real numbers. The real number that corresponds to a point is the coordinate of the point.

The distance between points A and B written as AB, is the absolute value of the difference between the coordinates of A and B.

AB is also called the length of AB.

Names of points

A

B

x1

x2

Coordinates of points

A

AB

B

x1

x2

AB = |x2 – x1|

Measure the length of the segment to the nearest millimeter.

Solution: Use a metric ruler. Align one mark of the ruler with A. Then estimate the coordinate of B. For example if you align A with 3, B appears to align with 5.5.

The distance between A and B is about 2.5 cm.

AB = |5.5 – 3| = |2.5| = 2.5

- It doesn’t matter how you place the ruler. For example, if the ruler in Example 1 is placed so that A is aligned with 4, then B align 6.5. The difference in the coordinates is the same.

USING SEGMENT POSTULATES

Finding the Distance on a Number Line

Find AB, BA, CB, BC, BD, and DB

Solutions:

AB = 1.5, BA = 1.5, CB = 3, BC = 3, BD = 5, DB = 5

When three points lie on a line, you can say that one of them is between the other two. This concept applies to collinear points only. For instance, in the figures on the next slide, point B is between points A and C, but point E is not between points D and F.

A

Point B is between points A and C.

B

C

D

E

Point E is NOT between points D and F.

F

If B is between A and C, then AB + BC = AC. If AB + BC = AC, then B is between A and C.

AC

A

B

C

AB

BC

USING SEGMENT POSTULATES

In the diagram, AD = 34, BC = 14, CD = 13 and AB = BE = EC.

Find BE, EC, AB, AE, ED, and BD

Solution: BE = 7, EC = 7, AB = 7, AE = 14, ED = 20, and BD = 27

The Distance Formula

- The distance d between two points (x1,y1) and (x2,y2) is given by

B(x2, y2)

A(x1, y1)

USING THE DISTANCE FORMULA

What is the Distance Formula based on?

B(x2, y2)

| y2 – y1 |

| x2 – x1 |

C(x2, y1)

A(x1, y1)

Pythagorean Theorem

c2 = a2 + b2

D =

USING THE DISTANCE FORMULA

Find the distance between the points X(2, -5) and Y(- 4, - 9)

Solution:

Classwork p. 21-22 #19, 31, 35, 37, 41

p. 21-22 #14 -42, 46, 60-70 Evens