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Symmetry. Viviana C. Castellón East Los Angeles College MEnTe Mathematics Enrichment through Technology.

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### Symmetry

Viviana C. Castellón

East Los Angeles College

MEnTe

Mathematics Enrichment

through Technology

A graph that is symmetric to the origin, can be seen as slicing a figure vertically and horizontally. In other words, for every point (x,y) on the graph, the point (-x,-y) is also on the graph.

Symmetric with Respect to the originThe figure illustrates slicing a figure vertically and horizontally. In other words, for every point (x,y) on the graph, the point (-x,-y) is also on the graph.symmetric with respect to the origin. A reflection about the y-axis, followed by a reflection about the x-axis.

The following figures illustrate slicing a figure vertically and horizontally. In other words, for every point (x,y) on the graph, the point (-x,-y) is also on the graph.symmetric with respect to the origin

Testing for Symmetry slicing a figure vertically and horizontally. In other words, for every point (x,y) on the graph, the point (-x,-y) is also on the graph.with respect to the origin

Substitute -x for every x and a –y for every y, in the equation. If the equation is EXACTLY as the original equation, the graph is symmetric with respect to the origin.

Testing for Symmetry slicing a figure vertically and horizontally. In other words, for every point (x,y) on the graph, the point (-x,-y) is also on the graph.with respect to the origin

The following equation is given:

Substitute –x for every x

and –y for every y.

Since the equation is EXACTLY the same as

the original equation, then the graph is

symmetric with respect to the origin.

After substituting a origin?–x for every x and a –y for every y,the equation is EXACTLY the same as the original. Therefore, the equation is symmetric with respect to the origin.

After substituting a origin?–x for every x and a–y for every y, the equation is NOT EXACTLY the same as the original. Therefore, the equation is NOT symmetric with respect to the origin.

After substituting a origin?–x for every x and a –y for every y, the equation is NOT EXACTLY the same as the original. Therefore, the equation is NOT symmetric with respect to the origin.

The function could also be graphed to show that it is origin?NOT symmetric with respect to the origin.

After substituting a origin?–x for every x and a –y for every y, the equation is EXACTLY the same as the original. Therefore, the equation is symmetric with respect to the origin.

The function could also be graphed to show that it is origin?symmetric with respect to the origin.

Congratulations!! origin?You just completed symmetric with respect to the origin

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