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Composed for SE 115 C programming Faculty of Engineering & Computer Sciences Izmir University of Economics. Assoc. Prof. Dr. Süleyman Kondakci [email protected] http://homes.ieu.edu.tr/skondakci. Summary of C Operations. Arithmetic : int i = i+1; i++; i--; i *= 2;

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slide1
Composed for SE 115 C programmingFaculty of Engineering & Computer Sciences Izmir University of Economics

Assoc. Prof. Dr. Süleyman Kondakci

[email protected]

http://homes.ieu.edu.tr/skondakci

slide2

Summary of C Operations

  • Arithmetic:
      • int i = i+1; i++; i--; i *= 2;
      • +, -, *, /, %,
  • Relational and Logical:
      • <, >, <=, >=, ==, !=
      • &&, ||, &, |, !
  • Flow Control:
    • if ( ) { } else { }
    • while ( ) { }
    • do { } while ( );
    • for(i=1; i <= 100; i++) { }
    • switch ( ) {case 1: … }
    • continue; break;
relational equality and logical operators
Relational,equality, and logical operators

Relational Operator:

Less than: <

Greater than: >

Less than or equal: <=

Greater than or equal: >=

equality and logical operators
Equality and Logical Operators

EqualityOperators:

Equal: ==

Not equal: !=

Logical Operators:

Negation: !

Logical and: &&

Logical or: ||

example conditional operators
Example: Conditional Operators

int main()

{

int x=0, y=10, w=20, z, T=1, F=0;

z = (x == 0); /*** logical operator; result --> 0 or 1 ***/

z = (x = 0); /*** assignment operator; result --> ***/

z = (x == 1);

z = (x = 15);

z = (x != 2);

z = (x < 10);

z = (x <= 50);

z = ((x=y) < 10); /*** performs assignment, compares with 10 ***/

z = (x==5 && y<15);

z = (x==5 && y>5 && w==10);

z = (x==5 || y>5 && w==10);

z = (T && T && F && x && x); /*** ==> F; ***/

z = (F || T || x || x); /*** ==> T; ***/

/*** value of x doesn\'t matter ***/

return 0;

}

input to output from program
Input to & Output From Program

Input: scanf ("format specifier", variable)

Output: printf ("format specifier", variable)

Format specifiers

%c = as a character

%d = as a decimal integer

%e = as a floating-point number in scientififc notation

%f = as a floating-point number

%g = in the e-format or f-format, whichever is shorter

%s = as a string of characters

small sample programs
Small Sample Programs

/*hello.c - traditional zeroeth program*/

#include <stdio.h>

int main()

{

printf("Hello world!\n");

return 0;

}

On the screen

Hello world!

escape sequences

\a

\f

\b

bell

backspace

formfeed

\\

\v

\t

horizontal tab

vertical tab

backslash

\\'

\"

\ooo

single quote

double quote

octal number

\xhh

\?

\n

newline

question mark

hexadecimal number

\r

carriage return

Escape Sequences

Escaped characters produce visual and audible effects

the output function printf

Character

Argument Type; Printed As

d, I

int; decimal number

o

int; unsigned octal number (without a leading zero)

x, X

int; unsigned hexadecimal number (without a leading Ox or OX, using abcdef or ABCDEF for 10,...,15)

u

int; unsigned decimal number

c

int; single character

s

char; print characters from the string until a \'\0\' or the number of charachters given by the precision

f

double; [-]m.dddddd, where the number of d\'s is given by the precision (default is 6)

e, E

double; [-]m.dddddde ± xx or [-]m.ddddddE ± xx where the number of d\'s is given by the precision (default is 6)

g, G

double; use %e or %E if the exponent is less than -4 or greater than or equal to the precision; otherwise use %f; trailing zeros and a trailing decimal point are not printed

p

void *; pointer (implementation-dependent representation)

%

no argument is converted; print a %

The Output Function (printf)
the input function scanf

Character

Input Data; Argument Type

d

decimal integer; int *

I

integer; int * ; the integer may be in octal (leading 0) or hexadecimal (leading 0x or 0X)

o

octal intger (with or without leading zero); int *

u

unsigned decimal integer; unsigned int *

x

hexadecimal number (with or without a leading 0x or 0X); int *

c

characters; char *. The next input characters (default 1) are placed at the indicated spot. The normal skip over white space is suppressed; to read the next non-white space character, use %1s

s

character string (not quoted); char * ; pointing to an array of characters large enough for the string and a terminating `\0\' that will be added

e, f, g

floating-point number with optional sign, optional decimal point, and optional exponent; float *

%

literal %; no assignment is made

The Input Function (scanf)
small sample programs1
Small Sample Programs

/*fahr.c (several versions) - convert Fahrenheit to Celsius. */

int main()

{

int fahr = 42, cels;

cels = 5*(fahr-32)/9;

printf("%d degrees Fahrenheit is %d degrees Celsius\n", fahr, cels);

return 0;

}

c programming
C Programming

Control Structures

the if statement
The if Statement

The if statement has two forms:

if(expression 1)

statement1;

else if (expression 2)

statement 2;

else statement 3

nested if statement
Nested if Statement

if (expression) {

if (expression) {

statements

if (expression) {

statements

}

}

} else {

statements

}

the operator
The ?: operator

expression1?expression2:expression3

Same as

if(expression1) expression2

else expression3

example the and operator s
Example: The ? and : operators

X = 12;

y = (x < 5) ? 5 : 10;

Same as

if (x < 5) y = 5;

else

y = 10;

c language blocks and styling
C Language Blocks and Styling

single block

{

Statements

}

{

{

... {

}

}

}

outer block

inner block

Multiple nested block structure

example single block
Example: Single Block

for (i=0; i<=10; i++) {

printf("index is: %d", i);

}

if (a == b && a <= c || c >0)

printf("Aha!! \a\a");

You can aslo write like this:

if (a == b && a <= c || c >0)

{

printf("Aha!!\a\a");

}

Or

if (a == b && a <= c || c >0) printf("Aha!!\a\a");

example multiple nested blocks
Example: Multiple (nested) Blocks

int a=2; int b=30; int c=11;

if(a==b){

if( b<=c && c >10){

c= a-b;

while (a <=10) {

printf("Value of a: %d", a);

B = a*c;

}

a = a-1;

}

}else{

printf("That is all folks!");

}

small sample programs2
Small Sample Programs

/* Uses scanf() to get input */

/* Uses printf() to shw the result */

#include <stdio.h>

int main()

{

int fahr, cels;

printf("How many degrees? ");

scanf("%d", &fahr);

cels = 5*(fahr-32)/9;

printf("%d degrees Fahrenheit is %d degrees Celsius\n", fahr, cels);

return 0;

}

small sample programs3
Small Sample Programs

/*same, but with reals instead of integers*/

#include <tdio.h>

int main()

{

double fahr, cels;

printf("How many degrees? ");

scanf("%lf", &fahr);

cels = 5.0*(fahr-32.0)/9.0;

printf("%.3f degrees Fahrenheit is %.3f degrees Celsius\n", fahr, cels);

return 0;

}

small sample programs4
Small Sample Programs

/*fahrcels.c (several versions) - use a conditional statement to select one of

two calculations.*/

#include <stdio.h>

int main()

{

double fahr, cels;

int unit; /*\'C\' for Celsius input, \'F\' for Fahrenheit*/

/*get input type*/

printf("Type C to convert Celsius to Fahrenheit, or F to go the other way: ");

unit = getchar();

/*get input, and do the appropriate calculation*/

printf("degrees? ");

if(unit == \'C\')

{

scanf("%lf", &cels);

fahr = 9.0*cels/5.0+32.0;

}

else

{

scanf("%lf", &fahr);

cels = 5.0*(fahr-32.0)/9.0;

}

printf("%.3f degrees Fahrenheit is %.3f degrees Celsius\n", fahr, cels);

return 0;

}

small sample programs5
Small Sample Programs

/*uses logical OR to handle lowercase*/

#include <stdio.h>

int main(){

double fahr, cels;

int unit; /*\'C\' for Celsius input, \'F\' for Fahrenheit*/

/*get input type*/

printf("Type C to convert Celsius to Fahrenheit, or F to go the other way: ");

unit = getchar();

/*get input, and do the appropriate calculation*/

printf("degrees? ");

if((unit == \'C\') || (unit == \'c\')) {

scanf("%lf", &cels);

fahr = 9.0*cels/5.0+32.0;

} else {

scanf("%lf", &fahr);

cels = 5.0*(fahr-32.0)/9.0;

}

printf("%.3f degrees Fahrenheit is %.3f degrees Celsius\n", fahr, cels);

return 0;

}

small sample programs6
Small Sample Programs

/*uses a conditional expression as well as a conditional statement*/

#include <stdio.h>

#include <ctype.h>

int main()

{

double fahr, cels;

int unit; /*\'C\' for Celsius input, \'F\' for Fahrenheit*/

/*get input type*/

printf("Type C to convert Celsius to Fahrenheit, or F to go the other way: ");

unit = toupper(getchar());

/*get input, and do the appropriate calculation*/

printf("degrees? ");

scanf("%lf", (unit==\'C\')? &cels: &fahr);

if(unit == \'C\')

fahr = 9.0*cels/5.0+32.0;

else

cels = 5.0*(fahr-32.0)/9.0;

printf("%.3f degrees Fahrenheit is %.3f degrees Celsius\n", fahr, cels);

return 0;

}

small sample programs7
Small Sample Programs

#include <stdio.h>

#include <ctype.h>

int main() {

double fahr, cels;

int unit; /*\'C\' for Celsius input, \'F\' for Fahrenheit*/

/*get input type*/

printf("Type C to convert Celsius to Fahrenheit, or F to go the other way: ");

unit = toupper(getchar());

/*get input, and do the appropriate calculation*/

printf("degrees? ");

if(unit == \'C\') {

scanf("%lf", &cels);

fahr = 9.0*cels/5.0+32.0;

} else {

scanf("%lf", &fahr);

cels = 5.0*(fahr-32.0)/9.0;

}

printf("%.3f degrees Fahrenheit is %.3f degrees Celsius\n", fahr, cels);

return 0;

}

c programming1
C Programming

Loops (Iterations)

the for loop syntax
The for Loop Syntax

for (initialize; check; update) {

statements

}

example for loop
Example: forLoop

#include <stdio.h>

#include <stdlib.h>

int main(){

int i;

for(i = 0; i <= 10; i++){

// Inside the loop

printf("loop count = %d\n", i);

}

// End of the loop

return 0;

}

the while loop syntax
The while Loop Syntax

while(expression)

Statement;

Or like this!

while(expression) {

Statements

}

example while loop
Example: while Loop

include <stdio.h>

#include <stdlib.h>

int main(){

int input_c;

/* The Classic Bit */

while( (input_c = getchar()) != EOF){

printf("%c was read\n", input_c);

}

return 0;

}

the do while loop syntax
The do-while Loop Syntax

do {

statements

} while(expression);

while(expression) {

statements

}

example for and while loops
Example: forand while Loops

#include <stdio.h>

#include <stdlib.h>

int main(){

int i;

i = 0;

while(i <= 10){

printf("%d\n", i);

i++;

}

return 0;

}

#include <stdio.h>

#include <stdlib.h>

int main(){

int i;

for(i = 0; i <= 10; i++){

printf("%d\n", i);

}

return 0;

}

example do while loop
Example: do-while Loop

#include <stdio.h>

#include <stdlib.h>

int main(){

int i; i = 0;

/* check */

do {

printf("%d\n", i);

/* increment i */

i++;

} while(i <= 10);

return 0;

}

the switch statement
The switch Statement

expression = some_value; /* can be the result of another expression or a user defined value. */

some_value can be const1, const2,..., const100 or else

switch (expression){

case const1: statements ; break;

case const2: statements; break;

...

case const100: statements; break

default: statements; break;

}

example switch statement
Example: switch Statement

#include <stdio.h>

#include <stdlib.h>

int main(){

int i;

for(i = 0; i <= 3; i++){

switch(i){

case 1: printf("1 \n");

break;

case 2: printf("2 \n");

break;

case 3: printf("3 \n");

break;

default: printf("default\n");

break;

}

}

return 0;

}

#include <stdio.h>

#include <stdlib.h>

int main(){

int i;

for(i = 0; i <= 3; i++){

if (i == 1) printf("1 \n");

else if (i == 2) printf("2 \n");

else if (== 3) printf("3 \n");

else printf("default\n");

}

return 0;

}

the break statemet
The break statemet

#include <stdio.h>

#include <stdlib.h>

int main(){

int i;

for(i = 0; i < 100000000; i++){

printf("Press s to stop");

if(getchar() == \'s\')

break;

printf("%d\n", i);

}

return 0;

}

the continue statement
The continue Statement

#include <stdio.h>

int main(){

int i;

for(i = -10; i < 10; i++){

if(i == 0 || i==6 || i == 9 )

// do not print 0, 6, and 9, continue with others

continue;

printf("%d \n", i);

// Other statements .....

}

return 0;

}

c programming2
C Programming

Functions

functions why and how
If a program is too long

Modularization – easier to

code

debug

Code reuse

Passing arguments to functions

By value

By reference

Returning values from functions

By value

By reference

Functions - why and how ?
definition and usage of functions
Definition and Usage of Functions

#include <stdio.h>

#include <stdlib.h>

/** function prototype declarations start here**/

int add(int a, int b);

int GetPosinteger(void); // or just int GetPosinteger();

/** End of function prototype declarations **/

int main()

{

int x, y, z;

x = GetPosinteger();

y = GetPosinteger();

printf("%d + %d = %d\n", x, y, add(x,y));

return 0;

}

int add(int a, int b){

return a+b;

}

int GetPosinteger(void)

{

int a;

do

{

printf("Enter a positive integer: ");

scanf("%d", &a);

} while (a <= 0);

return a;

}

functions are subprograms
Functions are subprograms!
  • The syntax for declaring a function:
    • return-type function-name (argument declarations){local variable declarationsStatements
    • }
  • Signature (or prototype) of a function:
    • return-type function-name (argument list)
void in void out
Void in void out

voidprint_message(void) // Inputs are void!

{

// Here void means no input parameter and no return value

printf("hello"); // No return

}

intadd(int a, int b) // We have two int inputs a & b

{

int sum;

sum = a + b;

return sum; // This is the output

}

slide43

Functions – Call by Value

  • #include <stdio.h>
  • int sum(int a, int b);
  • /* function prototype at start of file */
  • void main(void){
  • int total = sum(4,5); /* call to the function */
    • printf("The sum of 4 and 5 is %d", total);
  • }
  • int sum(int a, int b){ /* the function itself
  • - arguments passed by value*/
  • return (a+b); /* return by value */
  • }
slide44

Functions- Call by Reference(later!!)

#include <stdio.h>

/* function prototype at start of the code */

int sum(int *pa, int *pb); // Pointer references as input

void main(void){

int a=4, b=5;

int *ptr = &b; int total;

total = sum(&a,ptr); /* call to the function */

printf("The sum of 4 and 5 is %d", total);

}

int sum(int *pa, int *pb){

/* the function definition here

- arguments passed by reference */

return (*pa+*pb); /* return by ref */

}

c programming3
C Programming

User Interface

making menus for users
Making Menus for Users

void menu ()

{

printf("The following options\n");

printf("R ==> Register a book\n ");

printf("D ==> Display data about all books\n "); printf("F ==> Find and show a book\n ");

printf("Enter [R,D,F] or [Q] to Quit: ");

}

using functions with menu
Using functions with Menu

void main(void)

{

char opt;

menu();

opt=getchar();

do {

switch (opt) {

case \'r\'| R\': Register(); break;

case \'f\'|\'F\': Find(); break;

case \'d\'|\'D\': Show_data(); break;

case \'d\'|\'D\': break();

default: menu(); opt=getchar();break;

}

}while (opt != \'q\' && opt != \'Q\');

}

example pseudo code
Example Pseudo-code

# include<stdio.h>

# typedef enum {worse=-1, bad=0, good=1, best=2} credit;

/* Some global constant definitions, if required ... */

/* Start of function defs */

void register();void list();void find_disp();

void delete();void change();int get_option();

// End of function Defs

/* End of function Defs */

/* Start of main(), Action definitions */

int main() {

/* Some local variable and constant defs */

short int opt;

do {

opt=get_option();

switch(opt)

{

case 1: register(); break;

case 2: list(); break;

case 3: find_disp(); break;

case 4: delete(); break;

case 5: change(); break;

case 6: exit(); /* exit the loop, hence the program */

}

} while(1); /* End of while */

return 0;

} /* End of main() */

c programming4
C Programming

Recursive Functions

recursion
Recursion

Recursion = a function calls itself as a function for unknown times. We call this recursive call

for (i = 1 ; i <= n-1; i++) sum++;

int sum(int n) {

if (n <= 1)

return 1

else

return (n + sum(n-1));

}

recursive function
Recursive function

int f( int x )

{

if( x == 0 )

return 0;

else

return 2 * f( x - 1 ) + x * x;

}

recursion1
Recursion

Calculate factorial (n!) of a positive integer:

n! = n(n-1)(n-2)...(n-n-1), 0! = 1! = 1

int factorial(int n) {

if (n <= 1)

return 1;

else

return (n * factorial(n-1));

}

k th fibonacci numbers1
kth Fibonacci Numbers

Binary recursion

int BinaryFib(k) {

// Input: An integer k

// Output: The kth Fibonacci number

if (k <= 1) then

return k ;

else

return BinaryFib(k-1)+BinaryFib(k-2);

}

summary of conditional operators
Summary of Conditional Operators

int x=0, y=10, w=20, z, T=1, F=0;

z = (x == 0); /*** logical operator; result --> 0 or 1 ***/

z = (x = 0); /*** assignment operator; result --> ***/

z = (x == 1);

z = (x = 15);

z = (x != 2);

z = (x < 10);

z = (x <= 50);

z = ((x=y) < 10); /*** performs assignment, compares with 10 ***/

z = (x==5 && y<15);

z = (x==5 && y>5 && w==10);

z = (x==5 || y>5 && w==10);

z = (T && T && F && x && x); /*** ==> F; ***/

z = (F || T || x || x); /*** ==> T; ***/

/*** for && and !!, order is specified, stops when result is known, ***/

/*** value of x doesn\'t matter ***/

summary of the c operations
Summary of the C Operations
  • Operators same as in C++ and Java:
    • Arithmetic
      • int i = i+1; i++; i--; i *= 2;
      • +, -, *, /, %,
    • Relational and Logical
      • <, >, <=, >=, ==, !=
      • &&, ||, &, |, !
  • Syntax same as in C++ and Java:
    • if ( ) { } else { }
    • while ( ) { }
    • do { } while ( );
    • for(i=1; i <= 100; i++) { }
    • switch ( ) {case 1: … }
    • continue; break;
c programming5
C Programming

Arrays & Pointers

one dimensional arrays
One-Dimensional Arrays

#include <stdio.h>

void main(void)

{

int number[12]; /* 12 cells, one cell per element */

int index, sum = 0;

/* Always initialize arrays before use! */

for (index = 0; index < 12; index++) {

// cells are numbered from 0 to 11 not from 1 to 12!

number[index] = index;

}

for (index = 0; index < 12; index = index + 1) {

sum += number[index]; /* sum array elements */

}

return;

}

array initialization
Array Initialization

int i[10] = { 1,2,3,4,5,6,7,8,9,10 };

Character arrays that hold strings allow shorthand initializations, like

char str[9] = "I like C";

which is the same as:

char str[9] = { \'I\',\' \',\'l\',\'i\',\'k\',\'e\',\' \',\'C\',\'\0\' };

two dimensional arrays
Two-dimensional Arrays

col1 col2 col3 col4 ...

row1: matrix[0][0] matrix[0][1] matrix[0][2] matrix[0][3] ...

row2: matrix[1][0] matrix[1][1] matrix[1][2] matrix[1][3] ...

row3: matrix[2][0] matrix[2][1] matrix[2][2] matrix[2][3] ...

... ... ... ... ...

rowM: matrix[M][0] matrix[M][1] matrix[M][2] matrix[M][3] ...

void fillTable ()

{ int row, col, maxRow, maxCol;

int matrix [maxRow][maxCol];

        for (int row = 0; row < maxRow; row++)             for (int col = 0; col < maxCol; col++)                 matrix [row][col] = row + col; }

two dimensional arrays1
Two-dimensional Arrays

void fillTable ()

{ int row, col, maxRow, maxCol;

int matrix [maxRow][maxCol];

      for (int row = 0; row < maxRow; row++)         for (int col = 0; col < maxCol; col++)              matrix [row][col] = row + col; }

Outer loop executes (with row = 0) first, the inner loop fills in the values in the first row of matrix, namely:

matrix[0][0] = row + col,

matrix[0][1] = row + col,

matrix[0][2] = row + col,

and matrix[0][3] = row + col.

The next round of the outer loop fills in the second row of matrix.

The third and final round of the outer loop fills in the final row of matrix.

printing contents of 2 dimensional arrays
Printing contents of 2-dimensional Arrays

void displayTable ()     { int row, col;

       for ( row = 0; row < maxRow; row ++)         {             for (col = 0; col < maxCol; col ++) {printf("%d\n",matrix [row][col]);

}printf("\n");         } }

initialization of two dimensional arrays
Initialization of Two-dimensional Arrays

Two-dimensional arrays are initialized in the same way as the one-dimensional arrays, e.g.,

int myArray[6][2] =

{

1,1,

2,4,

3,9,

4,16,

5,25,

6,36

};

more arrays
More Arrays
  • Array of Strings
    • char name[6];
    • name = {‘C’,’S’,’4’,’1’,’4’,’\0’}; /* ’\0’= end of string */
    • printf("%s", name); /* print until ‘\0’ */
    • Functions to operate on strings
      • strcpy, strncpy, strcmp, strncmp, strcat, strncat, etc...
      • #include <strings.h> at program start
  • Multi-dimensional arrays
  • int points[3][4];
  • points [1][3] = 12; /* NOT points[3,4] */
  • printf("%d", points[1][3]);
more array of strings
More Array of Strings

#include <stdio.h>

int main() {

char msg[10]; /* array of 10 chars */

char *p; /* pointer to a char */

char msg2[]="Hello"; /* msg2 = ‘H’,’e’,’l’,’l’,’o’,’\0’ */

msg = "Hello"; /* ERROR. msg has a const address.*/

p = "Hello"; /* address of "Merhaba" goes into p */

msg = p; /* ERROR. Message has a constant address. */

/* cannot change it. */

p = msg; /* OK */

p[0] = ‘H’, p[1] = ‘i’,p[2]=‘\0’;

/* *p and msg are now "Hi" */

return 0;

}

algorithm iterativelinearsum a n
Algorithm IterativeLinearSum(A,n)

int IterativeLinearSum(A,n) {

// Input: An integer array A and an integer n (size)

// Output: The sum of the first n integers

if (n == 1) return A[0];

else

while (n != 0){

sum = sum + A[n];

n = n – 1;

}

return sum;

}

algorithm linearsum a n
Algorithm LinearSum(A,n)

int LinearSum(A,n) {

// Input: An integer array A and an integer n (size)

// Output: The sum of the first n integers

if (n == 1) return A[0];

else

return LinearSum(A,n-1) + A[n-1];

}

iterative approach
Iterative Approach

void IterativeReverseArray(A,i,n) {

// Input: An integer array A and an integers i and n

// Output: The reversal of n integers in A starting at index i

while (n > 1) {

swap (A[i], A[i+n-1]);

i =i +1;

n = n-2;

}

return;

}

recursive reversearray a i n
Recursive ReverseArray(A,i,n)

void ReverseArray(A,i,n) {

// Input: An integer array A and an integers i and n

// Output: The reversal of n integers in A starting at index i

if (n > 1) {

swap (A[i], A[i+n-1]);

ReverseArray(A, i+1, n-2);

}

return;

}

higher order recursion
Higher-Order Recursion

Making recursive calls more than a single call at a time.

int BinarySum(A,i,n) {

// Input: An integer array A and an integers i and n

// Output: The sum of n integers in A starting at index i

if (n == 1) {

return A[i];

return BinarySum(A,i,[n/2])+BinarySum(A,i+[n/2],[n/2]);

}

array operations searching
Array Operations: Searching

2

10

25

11

34

22

int score[5]

1

i

tmp

max=score[i];

for (i = 0; i < CLASS_SIZE; ++i) {

if (max <= score[i] ) {

max = score[i];

}

}

array operations searching1
Array Operations: Searching

#include "stdafx.h"

#include <stdio.h>

#define CLASS_SIZE 10

int main(void)

{

int i, score[CLASS_SIZE], max;

printf("Input %d How many scores: ", CLASS_SIZE);

for (i = 0; i < CLASS_SIZE; ++i) {

scanf("%d", &score[i]);

}

max=score[i];

for (i = 0; i < CLASS_SIZE; ++i) {

if (max <= score[i] ) {

max = score[i];

}

}

printf("\nMax is: %d\n\n", max);

return 0;

}

array operations string sorting
Array Operations: String Sorting

void string_sort(char *s[]){

char tmp; int i, j, length;

length=string_length(s);

for(i=0; i<length-1; i++) {

for (j=i+1; j<length; j++) {

if (strcmp(*s[i], *s[j]) == 0)

{

tmp=s[i]; s[i]=s[j]; s[j]=tmp;

}

}

}

}

int string_length(char str[]){

int i;

for(i=0; i<80; i++)

{

if(str[i]==\'\0\') return(i);

}

}

array operations sorting
Array Operations: Sorting

2

10

25

11

34

22

int score[5]

3

i

j-1

j

tmp

1

for (i = 0; i < CLASS_SIZE - 1; ++i)

for (j = CLASS_SIZE - 1; j > i; --j)

if (score[j-1] < score[j]) {

tmp = score[j-1];

score[j-1] = score[j];

score[j] = tmp;

}

array operations sorting1
Array Operations: Sorting

#include <stdio.h>

#define CLASS_SIZE 5

int main(void)

{

int i, j, score[CLASS_SIZE], sum = 0, tmp;

printf("Input %d scores: ", CLASS_SIZE);

for (i = 0; i < CLASS_SIZE; ++i) {

scanf("%d", &score[i]);

sum += score[i];

}

for (i = 0; i < CLASS_SIZE - 1; ++i) /* bubble sort */

for (j = CLASS_SIZE - 1; j > i; --j)

if (score[j-1] < score[j]) { /* check the order */

tmp = score[j-1];

score[j-1] = score[j];

score[j] = tmp;

}

printf("\nOrdered scores:\n\n");

for (i = 0; i < CLASS_SIZE; ++i)

printf(" score[%d] =%5d\n", i, score[i]);

printf("\n%18d%s\n%18.1f%s\n\n",

sum, " is the sum of all the scores",

(double) sum / CLASS_SIZE, " is the class average");

return 0;

}

read in words
Read in Words

void main(void){

char word[32]; /* work space keeps only one word*/

char *w[N]; /* an array of pointers to store words*/

int n; /* number of words to be sorted */

int i;

printf("Enter words\n");

for (i = 0; scanf("%s", word) == 1 ; ++i) {

if (i >= N) break;

if (strlen(word) >= 32) break;

w[i] = (char *)calloc(strlen(word) + 1, sizeof(char));

/* w[i] = new char[strlen(word) + 1]; */

if (w[i] == NULL) printf ("Empty Word ...\n");

strcpy(w[i], word);

}

n = i;

for (i = 0; i < n; ++i) printf("%s\n", w[i]); /* Display words */

}

sort words
Sort Words

void sort_words(char *w[], int n) /* sort n words */

{

int i, j;

for (i = 0; i < n; ++i)

for (j = i + 1; j < n; ++j)

if (strcmp(w[i], w[j]) > 0)

swap(&w[i], &w[j]);

}

void swap(char **p, char **q){

char *tmp;

tmp = *p;

*p = *q;

*q = tmp;

}

slide78

Pointers!!!!

(&x) 1000

(&x) 1000

x = 10

x = 5

y = 7

y = 7

(&y) 1004

(&y) 1004

1000

ptr = &x = 1000

(&ptr) 1200

(&ptr) 1200

  • Pointer = variable containing address of another variable
  • intx = 5; /* data variable */
  • int y = 7; /* data variable */
  • int *ptr = &x; /* & = address operator */

5

7

1200

ptr

x

y

*ptr = 10;

7

10

1200

y

ptr

x

slide79

Pointers - 1

any float

f

f_addr

?

?

?

any address

4300

4304

f

f_addr

?

4300

4300

4304

float f; /* data variable */

float *f_addr; /* pointer variable */

f_addr = &f; /* & = address operator */

slide80

Pointers - 2

f

f_addr

3.2

1.3

4300

4300

4300

4304

f

f_addr

4300

4304

*f_addr = 3.2; /* indirection operator */

float g=*f_addr; /* indirection:g is now 3.2 */

f = 1.3;

arrays and pointers
Arrays and Pointers

An array name by itsels is an address or pointer value!

#define N 100

int a[N], i, *p, *q, sum = 0;

p = a; /* is equivalent to p = &a[0] */;

p = a + 1; /* is equivalent to p = &a[1] */;

int a[i] /* is equivalent to *(a + i) */;

Here *(a + i) is the dereferencing of the expressin a + i that points i elements positions past in a

p = a; /* points to the base of array a */

q = p + 1; /* equivalent to q =&a[1] */

printf("%d\n", q – p);

printf("%d\n", (int) q - (int) p);

for (p = a; p <&a[N]; ++p) sum += *p;

for (i = 0; i < N; ++i) sum += *(a + i);

pointer arithmetic
Pointer Arithmetic
  • int main(int argc, char* argv[]){
  • double a[2], *p, *q;
  • p = a; /* points to the base of array a */
  • q = p + 1; /* equivalent to q =&a[1] */
  • printf("=============================\n");
      • printf(" p = %d", p);
      • printf("\n q = %d", q );
      • printf("\n q - p = %d", q - p);
      • printf("\n q - p = %d\n", (int) q - (int) p);
      • printf(" &a[0] = %d", &a[0] );
      • printf("\n &a[1] = %d &a[1] );
  • }
slide83

Pointer Example

#include <stdio.h>

void main(void) {

int j;

int *ptr;

ptr=&j; /* initialize ptr before using it */

/* *ptr=4 does NOT initialize ptr */

*ptr=4; /* j <- 4 assign 4 to j*/

j=*ptr; /* j <- ??? Ask students*/

}

pointers summary
Pointers: Summary
  • int a = 10, b = 2, *p;
  • p = &a; // p is assigned address of a
  • b = *p; // b is assigned the value pointed by p
  • b = *p; is equivalent to b = a;
  • An array name is an address or a pointer value
  • Arrays and pointers can be subscripted:
  • int A[10], *p; int i = 0; A[0]=23; p=A;
  • int b = A[i]; is equivalent to intb = *(A + 0);
  • int c = p[i]; is equivalent to intc = *(p + i);
  • p = A; is equivalent to p = &A[0];
  • p = A + 1; is equivalent to p = &A[1];
pointers summary1
Pointers: Summary

All will equally sum the array ellements:

1)

for (p = a; p <&a[N]; ++p)

sum += *p;

2)

for (i = 0; i < N; ++i)

sum += *(a + i);

3)

p = a;

for (i = 0; i < N; ++i)

sum += p[i];

call by value
Call-by-value
  • Whenever variables are passed as arguments to a function, their values are copied to the function parameters:
  • int main(){
  • int a=20; int b=30;
  • swap (a, b)
  • printf("%d %d: ", a, b);
  • return 0;
  • }
  • void swap(int x, y) {
  • int tmp;
  • tmp=x;
    • x=y;
    • y=tmp;
  • }
pointers call by reference
Pointers & Call-by-reference
  • Pointers are passed as arguments to a function, their addresses are assigned to the function parameters defined as pointers:
  • int main(){
  • int a=20; int b=30;
  • swap (&a, &b)
    • printf("%d %d: ", a, b);
    • return 0;
  • }
  • void swap(int *x, int *y) {
  • int tmp;
  • tmp = *x; // get value pointed by x.
    • *x = *y; // assign value pointed by y to x
    • *y = tmp;
  • }
slide88

Why pointer arguments?!

#include <stdio.h>

void swap(int, int);

int main() {

int num1 = 5, num2 = 10;

swap(num1, num2);

printf("num1 = %d and num2 = %d\n", num1, num2);

return 0;

}

void swap(int n1, int n2) { /* passed by value */

int temp;

temp = n1;

n1 = n2;

n2 = temp;

}

slide89

Why pointer arguments? This is why

#include <stdio.h>

void swap(int *, int *);

int main() {

int num1 = 5, num2 = 10;

swap(&num1, &num2);

printf("num1 = %d and num2 = %d\n", num1, num2);

return 0;

}

void swap(int *n1, int *n2) { /* passed and returned by reference */

int temp;

temp = *n1;

*n1 = *n2;

*n2 = temp;

}

slide90

Arrays as Function Arguments

#include <stdio.h>

void init_array(int array[], int size) ;

void main(void) {

int list[5];

init_array(list, 5);

for (i = 0; i < 5; i++)

printf("next:%d", array[i]);

}

void init_array(int array[], int size) { /* why size ? */

/* arrays ALWAYS passed by reference */

int i;

for (i = 0; i < size; i++)

array[i] = 0;

}

more pointers
More pointers

int month[12]; /* month is a pointer to base address 430*/

month[3] = 7; /* month address + 3 * int elements

=> int at address (430+3*4) is now 7 */

ptr = month + 2; /* ptr points to month[2],

=> ptr is now (430+2 * int elements)= 438 */

ptr[5] = 12;

/* ptr address + 5 int elements

=> int at address (434+5*4) is now 12.

Thus, month[7] is now 12 */

ptr++; /* ptr <- 438 + 1 * size of int = 442 */

(ptr + 4)[2] = 12; /* accessing ptr[6] i.e., array[9] */

  • Nowmonth[6], *(month+6), (month+4)[2], ptr[3], *(ptr+3) are all the same integer variable.
slide92

Pointer Example - argc and argv parameters

#include <stdio.h>

/* program called with cmd line parameters */

void main(int argc, char *argv[]) {

int ctr;

for (ctr = 0; ctr < argc; ctr = ctr + 1) {

printf("Argument #%d is -> |%s|\n", ctr, argv[ctr]);

} /* ex., argv[0] == the name of the program */

}

pointer s to function
Pointers to function
  • Advantage ? more flexibility

int func(); /*function returning integer*/

int *func(); /*function returning pointer to integer*/

int (*func)(); /*pointer to function returning integer*/

int *(*func)(); /*pointer to func returning ptr to int*/

slide94

Pointer to function - Example

#include <stdio.h>

void myproc (int d);

void mycaller(void (* f)(int), int param);

void main(void) {

myproc(10); /* call myproc with parameter 10*/

mycaller(myproc, 10); /* and do the same again ! */

}

void mycaller(void (* f)(int), int param){

(*f)(param); /* call function *f with param */

}

void myproc (int d){

. . . /* do something with d */

}

c programming6
C Programming

Advanced Stuff

container data types structures
Container Data types: Structures

#include <stdio.h>

struct birthday{

int month;

int day;

int year;

};

int main() {

struct birthday mybday;

mybday.day=1; mybday.month=1; mybday.year=1977;

printf("I was born on %d/%d/%d", birth.day,

birth.month, birth.year);

return 0;

}

slide97

Structures Cont’d

struct person{

char name[41];

int age;

float height;

struct { /* embedded or nested structure */

int month;

int day;

int year;

} birth;

};

struct person me;

me.birth.year=1977;………

struct person class[60];

/* array of info about everyone in class */

class[0].name="CS206"; class[0].birth.year=1971;……

accessing members of structures
Accessing Members of Structures

struct exp {

char c;

int i;

float arr[10];

};

struct exp exp1; struct exp *expPtr;

exp1.c = ‘A’; i = 20;

prinf("%c%d ", exp1.c, exp1.i);

expPtr->c=‘B’; expPtr->i=30;

prinf("%c%d ", expPtr->c, expPtr->i);

expPtr = &exp1;

prinf("%c%d ", expPtr->c, expPtr->i);

prinf("%c%d ", (*expPtr).c, (*expPtr).i);

slide99

enum - enumerated data types

#include <stdio.h>

enum month{

JANUARY, /* like #define JANUARY 0 */

FEBRUARY, /* like #define FEBRUARY 1 */

MARCH /* like #define MARCH2 */

APRIL /* like #define APRIL2 */

};

/* JANUARY is the same as month.JANUARY */

/* alternatively, …. */

enum month{

JANUARY=1, /* like #define JANUARY 1 */

FEBRUARY = 2, /* like #define FEBRUARY 2 */

MARCH /* … */

};

typdef synonym for a data type
typdef: Synonym for a data type
  • Easier to remember
  • For Clean code creation

typedef int numbers;

numbersa_number; /* same as int a_number; */

typedef struct person Person;

Person me; /* same as struct person me; */

typedef struct person *Personptr;

Personptr ptrtome; /* same as struct person *ptrtome;*/

memory layout of programs

Data - stack

Memory layout of programs

0

100

400

560

1010

1200

Header info

Code

all malloc()s

Dynamic memory

Data - Heap

Local memory

+ function call

stack

all normal vars

slide102

Dynamic Memory allocation

  • Explicit allocation and de-allocation

#include <stdio.h>

void main(void) {

int *ptr;

/* allocate space to hold an int */

ptr = malloc(sizeof(int));

/* Put something into the space */

*ptr=4;

free(ptr);

/* free up the allocated space */

char *w[10]; /* Space for 10 words: pointer array */

char word[12]

w[i] = calloc(strlen(word) + 1, sizeof(char));

/* allocate space to hold a word (string) */

}

structures summary
Structures: Summary

#include <stdio.h>

struct birthday{

int month;

int day;

int year;

};

int main() {

struct birthday mybday; /* Create structure */

mybday.day=1;

mybday.month=1;

mybday.year=1977;

printf("I was born on %d/%d/%d", birth.day,

birth.month, birth.year);

return 0;

}

slide104

More on Structures

struct person{

char name[41];

int age;

float height;

struct { /* embedded structure (iç içe)*/

int month;

int day;

int year;

} birth;

};

struct person me;

me.birth.year=1977;………

struct person class[2];

/* array of info about everyone in class */

class[0].name="Gül Nihal";

class[0].birth.year=1971;

Class[1].name="Mustafa Kemal"; class[0].birth.year=1883;……

slide105

Passing/Returning a structure

/* pass struct by value */

void display_year_1(struct birthday mybday) {

printf("I was born in %d\n", mybday.year);

} /* - inefficient: why ? */

. . . .

/* pass struct by reference */

void display_year_2(struct birthday *pmybday) {

printf("I was born in %d\n", pmybday->year);

/* warning ! ‘->’, not ‘.’, after a struct pointer*/

}

. . . .

/* return struct by value */

struct birthday get_bday(void){

struct birthday newbday;

newbday.day=02;

newbday;newbday.month=08;

newbday.year=1971;

return newbday;

}

c programming7
C Programming

File Operations

file i o writing data to files reading data from files

File I/O:Writing Data to FilesReading Data From Files

File Input Output Operations

File I/O

file operations
File Operations
  • Open the file
  • Do operations on the File
  • Close the file
files in c
Files in C
  • In C, each file is simply a sequential stream of bytes. C imposes no structure on a file.
  • A file must first be opened properly before it can be accessed for reading or writing. When a file is opened, a file handle is associated with the file.
  • Successfully opening a file returns a pointer to (i.e., the address of) a file structure,which contains a file descriptor and a file control block.
files in c1
Files in C
  • The statement:

FILE *fptr1, *fptr2 ;

declares that fptr1 and fptr2are pointer variables of type FILE. They will be assigned the address of a file descriptor, that is, an area of memory that will be associated with an input or output stream.

  • Whenever you are to read from or write to the file, you must first open the file and assign the address of its file descriptor (or structure) to the file pointer variable.
opening files
Opening Files
  • The statement:

fptr1 = fopen ( "mydata", "r" ) ;

 would open the file mydata for input (reading).

  • The statement:

fptr2 = fopen ("results", "w" ) ;

 would open the file results for output (writing).

  • Once the files are open, they stay open until you close them or end the program (which will close all files.)
testing for successful open
Testing for Successful Open
  • If the file was not able to be opened, then the value returned by the fopen routine is NULL.
  • For example, let\'s assume that the file mydata does not exist. Then:

FILE *fptr1 ;

fptr1 = fopen ( "mydata", "r") ;

if (fptr1 == NULL)

{

printf ("File \'mydata\' could not open.\n") ;

}

parameters for file access mode
Parameters for FILE access mode

Below are modes of opening a file:

"w" open write to text file

"r" read from text file

"a" append to end of file

"wb" write binary

"rb" read binary

"ab" binary appending

"r+" Text file read and write

"w+" Text file write and read

reading from files
Reading From Files
  • In the following segment of C language code:

int a, b ;

FILE *fptr1, *fptr2 ;

fptr1 = fopen ( "mydata", "r" ) ;

fscanf ( fptr1, "%d%d", &a, &b) ;

the fscanf function would read values from the file "pointed" to by fptr1 and assign those values to a and b.

end of file
End of File
  • The end-of-file indicator informs the program when there are no more data (no more bytes) to be processed.
  • There are a number of ways to test for the end-of-file condition. One is to use the feof function which returns a true or false condition:

fscanf (fptr1, "%d", &var) ;

if ( feof (fptr1) )

{

printf ("End-of-file encountered.\n) ;

}

end of file1
End of File
  • There are a number of ways to test for the end-of-file condition. Another way is to use the value returned by the fscanf function:

int istatus ;

istatus = fscanf (fptr1, "%d", &var) ;

if ( istatus == EOF )

{

printf ("End-of-file encountered.\n) ;

}

writing to files
Writing To Files
  • Likewise in a similar way, in the following segment of C language code:

int a = 5, b = 20;

FILE *fptr2 ;

fptr2 = fopen ( "results", "w" ) ;

fprintf ( fptr2, "%d %d\n", a, b ) ;

the fprintf functions would write the values stored in a and b to the file "pointed" to by fptr2.

closing files
Closing Files
  • The statements:

fclose ( fptr1 ) ;

fclose ( fptr2 ) ;

will close the files and release the file descriptor space and I/O buffer memory.

reading and writing files
Reading and Writing Files

#include <stdio.h>

void main ( )

{

FILE *outfile, *infile ;

int b = 5, f ;

float a = 13.72, c = 6.68, e, g ;

outfile = fopen ("testdata", "w") ;

fprintf (outfile, "%6.2f%2d%5.2f", a, b, c) ;

fclose (outfile) ;

infile = fopen ("testdata", "r") ;

fscanf (infile,"%f %d %f", &e, &f, &g) ;

printf ("%6.2f%2d%5.2f\n", a, b, c) ;

printf ("%6.2f,%2d,%5.2f\n", e, f, g) ;

}

12345678901234567890

****************************

13.72 5 6.68

13.72, 5, 6.68

more lines in a file
More Lines in a File?
  • The last assignment requires us to read several lines of some information from a file and write it out to the screen and to a file. (Sounds repetitive, doesn\'t it?)
  • Simple repetitive tasks are easily performed with a "for" or "while" loop. For example:

int i, ii = 0;

FILE *fptr2 ;

fptr2 = fopen ( "results", "w" ) ;

for ( i = 1 ; i <= n ; i++ )

{

fprintf ( fptr2, "%d %d\n", a, b ) ;

}

fclose (fptr);

exp change the case of letters in a file
Exp: Change the case of letters in a file

#include <ctype.h> #include <fcntl.h>

#include <stdio.h> /* #include <unistad.h> only Unix/linux */

#define BUFSIZE 1024

void main(int argc, char *argv[]) {

char mybuf[BUFSIZE], *p;

int in_fd, out_fd, n;

in_fd = open(argv[1], O_RDONLY);

out_fd = open(argv[2], O_WRONLY | O_EXCL | O_CREAT, 0600);

while ((n = read(in_fd, mybuf, BUFSIZE)) > 0) {

for (p = mybuf; p - mybuf < n; ++p)

if (islower(*p)) *p = toupper(*p);

else if (isupper(*p)) *p = tolower(*p);

write(out_fd, mybuf, n);

}

close(in_fd);

close(out_fd);

}

replicate a file with caps
Replicate a file with caps

The following code (conv.c) will convert the content of a file having lowercase letters to corresponding capital (uppercase) letters

Do the followings on UNIX/linux:

gcc –o toupper conv.c

./toupper

replicate a file with caps1
Replicate a file with caps

fp = fopen(argv[1], "r+");

tmp_fp = tmpfile();

while ((c = getc(fp)) != EOF)

putc(toupper(c), tmp_fp);

rewind(tmp_fp);

fprintf(fp, "---\n");

while ((c = getc(tmp_fp)) != EOF)

putc(c, fp);

return 0;

}

#include <ctype.h>

#include <stdio.h>

#include <stdlib.h>

int main(int argc, char *argv[]) {

int c; FILE *fp, *tmp_fp;

if (argc != 2) {

printf("\n%s%s%s\n\n%s\n\n", "Usage: "

argv[0], " filename");

exit(1);

}

if (fp=fopen(argv[1],"rw") == NULL) {

printf("Cannot open %s - bye!\n", argv[1]);

exit(1);

}

double space a file
Double Space a File

#include <stdio.h> #include <stdlib.h>

void double_space(FILE *, FILE *);

void prn_info(char *);

int main(int argc, char **argv) {

FILE *ifp, *ofp;

if (argc != 3) {

prn_info(argv[0]);

exit(1);

}

ifp = fopen(argv[1], "r"); /* open for reading */

ofp = fopen(argv[2], "w"); /* open for writing */

double_space(ifp, ofp);

fclose(ifp);

fclose(ofp);

return 0;

}

double space a file cont d
Double Space a File (cont’ d)

void double_space(FILE *ifp, FILE *ofp) {

int c;

while ((c = getc(ifp)) != EOF) {

putc(c, ofp);

if (c == \'\n\')

putc(\'\n\', ofp); /* found a newline - duplicate it */

}

}

void prn_info(char *pgm_name){

printf("\n%s%s%s\n\n%s%s\n\n",

"Usage: ", pgm_name, " infile outfile",

"The contents of infile will be double-spaced ",

"and written to outfile.");

}

c programming8
C Programming

Preprocessors & Macros

the c preprocessor
The C Preprocessor
  • Preprocessors extend power of C
  • Lines starting with # are preprocessing directives.
  • #define macro facility generates inline code in place of functions. They provide fatser execution. Examples:
  • #include <stdio.h>
  • #include "filename"
  • #define identifier token_string
  • #define (identifier,…, identifier) token_string
the use of define
The Use of #define
  • #define PI 3.14159
  • #define size 1000
  • #define seconds_per_day (60*60*2)
  • #define EQ ==
  • #define LT <
  • #define LTE <=
  • #define NOT !=
  • Example:

int main(){

int i=0

while (i NOT 5){

printf ("hello!");

i++;

}

return 0;

}

macros
Macros
  • Macros are small codes that can be used

instead of functions.

  • They execute very fast!
  • Syntax:

#define (identifier,…, identifier) token_string

#define sq(x) ((x) * (x))

In the code

int w = 6;

sq(7 + w) expands to ((7 + 6) 0 (7 + 6))

sq(sq(5)) expands to what?

#define min(x,y) (((x) < (y)) ? (x) : (y))

How to call ?

int u,v,m;

scanf("%d%d", &u,&v);

int m = (u,v);

macros with arguments
Macros With Arguments
  • #define fractional_part(x) (x – (int) x)
  • #define random_char() (rand() % 26 + ‘a’)
  • #define random_int(x) (rand() % x)
  • #define mix(x,y) (((x) > (y)) ? (x) : (y))

int main() {

char a = random_char();

int r = random_int(100);

fractional_part(3.456);

printf("%c%d",c,r,f);

printf("%d%d",min(r,f));

printf("%c%d",max(r,f));

return 0;

}

some macros in stdio h and ctype h
Some Macros in stdio.h and ctype.h
  • In the file ctype.h we have
  • #define getchar() getc(stdin)
  • #define putcahr() putc((c),stdout)

Your code should contain this at the top

#include <ctype.h>

user defined data structures
User Defined Data Structures
  • All related data are collected in conglomerate structures
  • Many types of conglomerate structures:
    • Stacks
    • Queues (FIFO = First in First Out)
    • Trees
    • Vectors
    • Linked Lists
      • Single
      • Double
      • Circle
what are stacks
What Are Stacks ?

Overflow

MAX

PUSH

POP

0

-1

Underflow

stacks
Stacks

const int MaxStack = 1024;

const char EmptyFlag = \'\0\';

char items [ MaxStack ];

int top;

enum { FullStack = MaxStack, EmptyStack = -1 };

/* Required tack functions are: */

push(char);

char pop();

bool empty(); bool full();

stack example
Stack: Example

const int MaxStack = 1024;const char EmptyFlag = \'\0\';

char items [ MaxStack ];

int top;

enum { FullStack = MaxStack, EmptyStack = -1 };

void push(char);char pop();

bool empty(); bool full();

void push(char c){

if (full()) return;

items[++top] = c;

}

char pop(){

if (empty()) return EmptyFlag;

return items[top--];

}

stacks example
Stacks: Example

bool full(){

if (top + 1 == FullStack) {

cerr << "Stack Full at " << MaxStack << endl;

return true;

}

return false;

}

bool empty(){

if (top == EmptyStack) {

cerr <<"Stack empty" <<endl;

return true;

}

return false;

}

void main(void){

push(‘A’); push(‘B’);

pop();pop();

pop();

}

c programming10
C Programming

Linked Lists

linked lists

Head

Tail

next

next

Linked Lists
  • Nodes: Represent data storage points
  • Pointers: are used to handle nodes

A node

int a

char c

char *name = "kerem"

NULL

linked list operations
Linked List Operations
  • Creating a list element,
  • Prepending elements on top of lists,
  • Inserting elements into lists,
  • Appending to end of lists,
  • Finding/searching elements in the list
  • Sorting elements,
  • Deleting,
  • Moving elements around in the list.
linked list types

A node

int a

char c

char *name = "kerem"

Head

Tail

Tail

Head

next

next

next

next

A node

Tail

previous

Head

previous

NULL

next

next

next

A node

int a

char c

char *name = "kerem"

Linked List Types

Single linked lists

next

Double linked lists

Circle linked lists

NULL

linked lists1

data

next

3

2

1

2

3

1

next

next

next

next

next

next

NULL

NULL

Linked Lists

struct list {

int data;

struct list *next;

}a;

struct list a, b,c

a.data = 1; b.data=1;c.data=3;

a.next=b.next=c.next = NULL;

a.next = &b;

b.next =&c;

linear linked lists
Linear Linked Lists

#include <assert.h>#include <stdio.h>

#include <stdlib.h>

#define MAXLINE 100

typedef char DATA; /* will use char in examples */

struct linked_list {

DATA d;

struct linked_list *next;

};

typedef struct linked_list ELEMENT;

typedef ELEMENT *LINK;

linear linked lists1

C

A

B

A

A

B

next

next

next

next

next

next

NULL

NULL

NULL

Linear Linked Lists

LINK head;

head = malloc(sizeof(ELEMENT));

head->d =‘A’;

head->next = NULL;

/* Let’s add a second element */

head ->next = malloc(sizeof(ELEMENT));

head->next->d =‘B’;

head->next ->next = NULL;

/* Let’s add a 3rd element */

head ->next->next = malloc(sizeof(ELEMENT));

head->next->d ->next =‘C’;

head->next ->next ->next = NULL;

creating a list 1st declare the list
Creating a List: 1st Declare the List

#include <assert.h>

#include <stdio.h>

#include <stdlib.h>

#define MAXLINE 100

typedef char DATA; /* will use char in examples */

struct linked_list {

DATA d;

struct linked_list *next;

};

typedef struct linked_list ELEMENT;

typedef ELEMENT *LINK;

creating a list using iteration
Creating a List: Using Iteration

#include "list.h"

LINK s_to_l(char s[]) {

LINK head = NULL, tail; int i;

if (s[0] != \'\0\') { /* first element */

head = malloc(sizeof(ELEMENT));

head -> d = s[0];

tail = head;

for (i = 1; s[i] != \'\0\'; ++i) { /* add to tail */

tail -> next = malloc(sizeof(ELEMENT));

tail = tail -> next;

tail -> d = s[i];

}

tail -> next = NULL; /* end of list */

}

return head;

}

creating a list using recursion
Creating a List: Using Recursion

#include "list.h"

LINK string_to_list(char s[]) {

LINK head;

if (s[0] == \'\0\') /* base case */

return NULL;

else {

head = malloc(sizeof(ELEMENT));

head -> d = s[0];

head -> next = string_to_list(s + 1);

return head;

}

}

count elements of a list using iteration
Count Elements of a List: Using Iteration

#include "list.h"

int count_list(LINK head)

{

int count;

for (; head != NULL; head = head -> next)

++count;

return count;

}

count elements of a list using recursion
Count Elements of a List: Using Recursion

#include "list.h"

int count_list(LINK head)

{

if (head == NULL) return 0;

else

return(1 + count_list(head -> next));

}

print elements in a list using iteration
Print Elements in a List: Using Iteration

#include "list.h"

void wrt_list(LINK head)

{

LIST p;

if (head == NULL) printf("NULL list");

else

for (p = head; p != NULL; p = p -> next)

putchar(p -> d);

}

print elements in a list using recursion
Print Elements in a List: Using Recursion

#include "list.h"

void wrt_list(LINK head)

{

if (head == NULL) printf("NULL list");

Else {

printf("%c ", head -> d);

wrt_list(head ->next);

}

}

insertion of elements in a list

B

C

A

next

next

next

NULL

Insertion of Elements in a List

#include "list.h"

Void insert(LINK p1, LINK p2, LINK q)

{

Assert (p1-> next == p2);

p1->next = q;

q->next = p2;

}

initially

p2

p1

q

delete elements in a list using iteration
Delete Elements in a List: Using Iteration

#include "list.h"

void delete(LINK head)

{

LIST p;

if (head == NULL) printf("NULL list");

else

for (p = head; p != NULL; p = p -> next)

free(p);

}

delete elements in a list recursively
Delete Elements in a List: Recursively

#include "list.h"

void elete_list(LINK head)

{

if (head != NULL) {

delete_list(head ->next);

free(head);

}

}

c programming11
C Programming

First In - First Out Queues

a linked list implementation of a queue

data

daat

data

next

next

next

NULL

A linked list implementation of a queue

queue

Queue: First-In-First-Out (FIFO) data structure

cnt

front

rear

elem

elem

elem

the header file queue h
The header file: queue.h

#define EMPTY 0

#define FULL 10000

typedef unsigned int data;

typedef enum {false, true} boolean;

struct elem { /* an element in the queue */

data d;

struct elem *next;

};

typedef struct elem elem;

struct queue {

int cnt; /* a count of the elements */

elem *front; /* ptr to the front element */

elem *rear; /* ptr to the rear element */

};

typedef struct queue queue;

the header file queue h cont d
The header file: queue.h(cont’ d)

void initialize(queue *q);

void enqueue(data d, queue *q);

data dequeue(queue *q);

data front(const queue *q);

boolean empty(const queue *q);

boolean full(const queue *q);

basic queue routines cont d
Basic queue routines (cont’ d)

#include "queue.h"

void initialize(queue *q){

q -> cnt = 0;

q -> front = NULL;

q -> rear = NULL;

}

data dequeue(queue *q){

data d;

elem *p;

d = q -> front -> d;

p = q -> front;

q -> front = q -> front -> next;

q -> cnt--;

free(p);

return d;

}

basic queue routines cont d1
Basic queue routines(cont’ d)

void enqueue(data d, queue *q){

elem *p;

p = malloc(sizeof(elem));

p -> d = d;

p -> next = NULL;

if (!empty(q)) {

q -> rear -> next = p;

q -> rear = p;

} else

q -> front = q -> rear = p;

q -> cnt++;

}

basic queue routines cont d2
Basic queue routines(cont’ d)

data front(const queue *q){

return (q -> front -> d);

}

boolean empty(const queue *q){

return ((boolean) (q -> cnt == EMPTY));

}

boolean full(const queue *q){

return ((boolean) (q -> cnt == FULL));

}

c programming12
C Programming

The End (for now)

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