Two-Dimensional Motion

1 / 13

# Two-Dimensional Motion - PowerPoint PPT Presentation

Two-Dimensional Motion. Inclined Planes. Inclined Planes. A simple block on an incline. 30°. F g. Inclined Planes. B/c the block in on an incline, we adjust our coordinate system to fit the incline. Y. X. 30°. F g. Aligning the X axis with the Incline. Inclined Planes.

I am the owner, or an agent authorized to act on behalf of the owner, of the copyrighted work described.

## PowerPoint Slideshow about ' Two-Dimensional Motion' - nayda-hines

Download Policy: Content on the Website is provided to you AS IS for your information and personal use and may not be sold / licensed / shared on other websites without getting consent from its author.While downloading, if for some reason you are not able to download a presentation, the publisher may have deleted the file from their server.

- - - - - - - - - - - - - - - - - - - - - - - - - - E N D - - - - - - - - - - - - - - - - - - - - - - - - - -
Presentation Transcript

### Two-Dimensional Motion

Inclined Planes

Inclined Planes

A simple block on an incline

30°

Fg

Inclined Planes

B/c the block in on an incline,

we adjust our coordinate system to fit the incline

Y

X

30°

Fg

Aligning the X axis with the Incline

Inclined Planes
• Notice the gravitational force (Fg) is pulling straight down
• Doesn’ t the Fg also pull you down the hill?

YEP!

So, there are components of the Fg

(x and y)

Inclined Planes
• There is an Fgx and an Fgy

Fgx

Fgy

Fg

Inclined Planes
• Notice that the coordinate system has been adjusted… How much?

Y

X

30°

Fg

It has been adjusted by the incline, 30°

Inclined Planes
• Therefore the angle between Fg and Fgy is…

30°

Fgx

Fgy

30°

Fg

Inclined Planes
• Therefore the angle between Fg and Fgy is…

30°

Fgx

Fgy

30°

30°

Fg

Inclined Planes
• Now we are able to solve for fgx and fgy
• Fgx is the force pulling the block down the incline
• Fgy is the force keeping the block in contact with the incline
Inclined Planes
• Realign the vectors (Tip-to-Tail) to complete a right triangle and you get…

Fgy

30°

Fg

30°

Fgx

Inclined Planes
• Lets take a closer (magnified) look at the similar triangle

Fgy

30°

Fg

30°

Fgx

Inclined Planes
• Lets take a closer (magnified) look at the similar triangle

Y

Nice!

Fgy

30°

Fgx

X

Fg

Inclined Plane Problem
• A 784-N skier on a hill that makes a 35 angle with the horizontal begins to accelerate down the hill.
• Draw the pictorial diagram and free-body diagram
• What is the component of the skier’s weight parallel to the incline plane?
• What is the normal force?