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# Background of Connector Scenario for Worst Case proposal Used Probability Density Function PowerPoint PPT Presentation

Background of Connector Scenario for Worst Case proposal Simulations for the 10GbE Base SR (850nm, 50µm-MM-Fiber). In the Modeling for the specification of the 10GBit/s transmission on the 50µm multimode fiber was used the following statistics for the connector offsets:

Background of Connector Scenario for Worst Case proposal Used Probability Density Function

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### Background of Connector Scenario for Worst Case proposalSimulations for the 10GbE Base SR (850nm, 50µm-MM-Fiber)

• In the Modeling for the specification of the 10GBit/s transmission on the 50µm multimode fiber was used the following statistics for the connector offsets:

(see Pepeljugoski et.al., JLT, Vol.21, No.5, May 2003, p.1256)

Rayleigh Distribution of connector offsets:

Mean value of 3,58µm,

Probability of exceeding 7µm offset is: 5%

This distribution is used for the current worst case model.

### Background of Connector Scenario for Worst Case proposalIdea of a Set of Different Connector Offsets

• The combination of short – long – short fibers with 4 connectors seems to be a standard application configuration

• The selected worst case should have a low but reasonable probability for the selected set of offsets.

• If one 7µm offset connector has p=0.05 than a set of 4 connectors with 7µm offset have the probability of

p= 0.054 = 6 x10-6 which is extremely low.

• Therefore we chose the offset of the second connector at a value where two connectors of the same offset have the probability of p=0.05,

• The third offset at the value for three connectors with same offset of p=0.05,

• And similar for the fourth offset.

### Background of Connector Scenario for Worst Case proposalProbability Function with Multiple Connectors

Probability of 5%:

1 connector : offset 7 µm

2 connectors: offset 5 µm

3 connectors: offset 4 µm

4 connectors: offset 3,5µm

Overall probability of the

combination of one connector

of each offset:

P=0.05%