# 1.3 Density and Gas Laws - PowerPoint PPT Presentation

1 / 10

1.3 Density and Gas Laws. DENSITY. Density is the relationship of mass to volume. It describes how tightly the atoms and molecules of a substance are packed together. Density. D = M / V M = DV V = M / D M - Mass : g , kg V - Volume : cm 3, L D - Density : g/cm 3 , g /L

I am the owner, or an agent authorized to act on behalf of the owner, of the copyrighted work described.

1.3 Density and Gas Laws

Download Policy: Content on the Website is provided to you AS IS for your information and personal use and may not be sold / licensed / shared on other websites without getting consent from its author.While downloading, if for some reason you are not able to download a presentation, the publisher may have deleted the file from their server.

- - - - - - - - - - - - - - - - - - - - - - - - - - E N D - - - - - - - - - - - - - - - - - - - - - - - - - -

## 1.3 Density and Gas Laws

### DENSITY

• Density is the relationship of mass to volume.

• It describes how tightly the atoms and molecules of a substance are packed together.

### Density

D = M / V

M = DV

V = M / D

M - Mass: g, kg

V - Volume: cm3, L

D - Density: g/cm3, g/L

kg/cm3, kg/L…

### Density Example

If a sample of zinc has a mass of 25.4 g and its volume is 12.3 cm3. What is the density of the sample?

E: d = m/v

W: d = 25.4 g / 12.3 cm3

AU: d = 2.07 g/cm3

### Boyle Law

• Boyles Law shows the relationship between pressure (how tight a gas is packed) and volume (how much space an object takes up).

• It is an inverse or indirect relationship. As the pressure increases the volume decreases…

### Boyles’ Law (inverse)

P1V1 = P2V2

Pressure*Volume = Pressure*Volume

Before After

P – kPa, atm,

V – cm3, L,

To solve – multiply together and divide.

P V P V

=

### Boyles’ Law Example

Hydrogen is stored at 1.3 atm in a 3 L container. If it were to be released into a 50 L container, what would the pressure be?

E: P1V1 = P2V2

W: 1.3atm * 3L = P2 atm * 50 L

AU: 0.078 atm

### Charles’ Law

• Charles’ Law shows the relationship between volume and temperature.

• It is a direct relationship.

• As volume increases, temperature increases…

### Charles’ Law (Direct)

Before = After

Volume = Volume

Temp Temp

V - L, cm3…

T – K (to convert from C to K, add 273)

To solve – multiply diagonal and divide

V

T

=

### Charles’ Example

Balloons at 300 K have a volume of 2.5 L. If the temperature is increased to 500 K, what volume would they occupy?

E:

W: 2.5 L = V2 L

300K 500K

AU: 4.17 L