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Chapter 11. Section 11.8. Exercise #1. A parent teacher committee consisting of four people is to be formed from 20 parents and five teachers. Find the probability that the committee will consist of the following. (Assume that the selection will be random.). (a) All teachers

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Section 11.8

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Section 11 8 l.jpg

Chapter 11

Section 11.8

Exercise #1


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A parent teacher committee consisting of four people is to be formed from 20 parents and five teachers. Find the probability that the committee will consist of the following. (Assume that the selection will be random.)


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(a) All teachers

(b) Two teachers and two parents

(c) All parents

(d) One teacher and three parents


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A committee of four out of 20 parents and 5 teachers

a) P(all teachers)

n(all selections):

25!

25C4

=

4!(25 – 4)!


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A committee of four out of 20 parents and 5 teachers

a) P(all teachers)

n(all selections):

25!

25C4

=

4!(21!)


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A committee of four out of 20 parents and 5 teachers

a) P(all teachers)

n(all selections):

25 24 23 22 21!

25C4

=

4 3 2 1 21!


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A committee of four out of 20 parents and 5 teachers

a) P(all teachers)

n(all selections):

25C4

= 12,650


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A committee of four out of 20 parents and 5 teachers

a) P(all teachers)

n(all selections): 12,650

n(all teachers):

5!

5C4

=

4!(5 – 4)!


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A committee of four out of 20 parents and 5 teachers

a) P(all teachers)

n(all selections): 12,650

n(all teachers):

5!

5C4

=

4!(1!)


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A committee of four out of 20 parents and 5 teachers

a) P(all teachers)

n(all selections): 12,650

n(all teachers):

5 4!

5C4

=

4! 1


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A committee of four out of 20 parents and 5 teachers

a) P(all teachers)

n(all selections): 12,650

n(all teachers):

5C4

= 5


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A committee of four out of 20 parents and 5 teachers

a) P(all teachers)

n(all selections): 12,650

n(all teachers): 5

n(all teachers)

P(all teachers) =

n(all selections)


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A committee of four out of 20 parents and 5 teachers

a) P(all teachers)

n(all selections): 12,650

n(all teachers): 5

5

P(all teachers) =

12,650


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A committee of four out of 20 parents and 5 teachers

a) P(all teachers)

n(all selections): 12,650

n(all teachers): 5

1

P(all teachers) =

2,530


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A committee of four out of 20 parents and 5 teachers

a) P(all teachers)

n(all selections): 12,650

n(all teachers): 5

P(all teachers) = 0.0004


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n(2 teachers and 2 parents):

5!

20!

5C2

20C2

=

2!(3!)

2!(18!)

A committee of four out of 20 parents and 5 teachers

b) P(2 teachers and 2 parents)


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A committee of four out of 20 parents and 5 teachers

b) P(2 teachers and 2 parents)

n(2 teachers and 2 parents):

5 4

20 19

5C2

20C2

=

2 1

2 1


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A committee of four out of 20 parents and 5 teachers

b) P(2 teachers and 2 parents)

n(2 teachers and 2 parents):

20

380

5C2

20C2

=

2

2


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A committee of four out of 20 parents and 5 teachers

b) P(2 teachers and 2 parents)

n(2 teachers and 2 parents):

5C2

20C2

= 10 190


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A committee of four out of 20 parents and 5 teachers

b) P(2 teachers and 2 parents)

n(2 teachers and 2 parents):

5C2

20C2

= 1,900


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A committee of four out of 20 parents and 5 teachers

b) P(2 teachers and 2 parents)

n(2 teachers and 2 parents): 1,900

P(2 teachers and 2 parents) =

n(2 teachers and 2 parents)

n(all selections)

n(all selections): 12,650


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A committee of four out of 20 parents and 5 teachers

b) P(2 teachers and 2 parents)

n(2 teachers and 2 parents): 1,900

n(all selections): 12,650

P(2 teachers and 2 parents) =

1,900

12,650


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A committee of four out of 20 parents and 5 teachers

b) P(2 teachers and 2 parents)

P(2 teachers and 2 parents) =0.15


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n(all parents):

20!

20C4

=

4!(16!)

A committee of four out of 20 parents and 5 teachers

c) P(all parents)


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A committee of four out of 20 parents and 5 teachers

c) P(all parents)

n(all parents):

20 19 18 17

20C4

=

4 3 2 1


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A committee of four out of 20 parents and 5 teachers

c) P(all parents)

n(all parents):

116,280

20C4

=

24


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A committee of four out of 20 parents and 5 teachers

c) P(all parents)

n(all parents):

20C4

= 4,845


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A committee of four out of 20 parents and 5 teachers

c) P(all parents)

n(all parents): 4,845

n(all parents)

P(all parents):

n(all selections)

n(all selections): 12,650


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A committee of four out of 20 parents and 5 teachers

c) P(all parents)

n(all parents): 4,845

n(all selections): 12,650

4,845

P(all parents):

12,650


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A committee of four out of 20 parents and 5 teachers

c) P(all parents)

P(all parents): 0.383


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n(1 teacher and 3 parents):

5!

20!

5C1

20C3

=

1!(4!)

3!(17!)

A committee of four out of 20 parents and 5 teachers

d) P(1 teacher and 3 parents)


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A committee of four out of 20 parents and 5 teachers

d) P(1 teacher and 3 parents)

n(1 teacher and 3 parents):

5

20 19 18

5C1

20C3

=

1

3 2 1


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A committee of four out of 20 parents and 5 teachers

d) P(1 teacher and 3 parents)

n(1 teacher and 3 parents):

5

6,840

5C1

20C3

=

1

6


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A committee of four out of 20 parents and 5 teachers

d) P(1 teacher and 3 parents)

n(1 teacher and 3 parents):

34,200

5C1

20C3

=

6


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A committee of four out of 20 parents and 5 teachers

d) P(1 teacher and 3 parents)

n(1 teacher and 3 parents):

5C1

20C3

= 5,700


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A committee of four out of 20 parents and 5 teachers

d) P(1 teacher and 3 parents)

n(1 teacher and 3 parents): 5,700

P(1 teacher and 3 parents) =

n(1 teacher and 3 parents)

n(all selections)

n(all selections): 12,650


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A committee of four out of 20 parents and 5 teachers

d) P(1 teacher and 3 parents)

n(1 teacher and 3 parents): 5,700

n(all selections): 12,650

P(1 teacher and 3 parents) =

5,700

12,650


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A committee of four out of 20 parents and 5 teachers

d) P(1 teacher and 3 parents)

P(1 teacher and 3 parents) =0.450


Section 11 839 l.jpg

Chapter 11

Section 11.8

Exercise #3


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A city council consists of 10 members. Four are Republicans, three are Democrats, and three are Independents. If a committee of three is to be selected, find the probability of selecting

All Republicans

All Democrats


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(c) One of each party

Two Democrats and one Independent

One Independent and two Republicans


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A committee of 3 out of 10 members: 4 Republicans (R), 3 Democrats (D), 3 Independents (I)

a) P(all R)

n(all selections):

10!

10C3

=

3!(10 – 3)!


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A committee of 3 out of 10 members: 4 Republicans (R), 3 Democrats (D), 3 Independents (I)

a) P(all R)

n(all selections):

10!

10C3

=

3!(7!)


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A committee of 3 out of 10 members: 4 Republicans (R), 3 Democrats (D), 3 Independents (I)

a) P(all R)

n(all selections):

10 9 8 7!

10C3

=

3 2 1 7!


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A committee of 3 out of 10 members: 4 Republicans (R), 3 Democrats (D), 3 Independents (I)

a) P(all R)

n(all selections):

720

10C3

=

6


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A committee of 3 out of 10 members: 4 Republicans (R), 3 Democrats (D), 3 Independents (I)

a) P(all R)

n(all selections):

10C3

= 120


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A committee of 3 out of 10 members: 4 Republicans (R), 3 Democrats (D), 3 Independents (I)

a) P(all R)

n(all selections): 120

n(all R):

4!

4C3

=

3!(4 – 3)!


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A committee of 3 out of 10 members: 4 Republicans (R), 3 Democrats (D), 3 Independents (I)

a) P(all R)

n(all selections): 120

n(all R):

4!

4C3

=

3!(1!)


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A committee of 3 out of 10 members: 4 Republicans (R), 3 Democrats (D), 3 Independents (I)

a) P(all R)

n(all selections): 120

n(all R):

4 3!

4C3

=

3! 1


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A committee of 3 out of 10 members: 4 Republicans (R), 3 Democrats (D), 3 Independents (I)

a) P(all R)

n(all selections): 120

n(all R):

4C3

= 4


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A committee of 3 out of 10 members: 4 Republicans (R), 3 Democrats (D), 3 Independents (I)

a) P(all R)

n(all selections): 120

n(all R): 4

n(all R)

P(all R) =

n(all selections)


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A committee of 3 out of 10 members: 4 Republicans (R), 3 Democrats (D), 3 Independents (I)

a) P(all R)

n(all selections): 120

n(all R): 4

4

P(all R) =

120


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A committee of 3 out of 10 members: 4 Republicans (R), 3 Democrats (D), 3 Independents (I)

a) P(all R)

n(all selections): 120

n(all R): 4

1

P(all R) =

30


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A committee of 3 out of 10 members: 4 Republicans (R), 3 Democrats (D), 3 Independents (I)

a) P(all R)

P(all R) = 0.033


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n(all D):

3!

3C3

=

3!(3 – 3)!

A committee of 3 out of 10 members: 4 Republicans (R), 3 Democrats (D), 3 Independents (I)

b) P(all D)


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A committee of 3 out of 10 members: 4 Republicans (R), 3 Democrats (D), 3 Independents (I)

b) P(all D)

n(all D):

3!

3C3

=

3!(0)!


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A committee of 3 out of 10 members: 4 Republicans (R), 3 Democrats (D), 3 Independents (I)

b) P(all D)

n(all D):

3C3

= 1


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A committee of 3 out of 10 members: 4 Republicans (R), 3 Democrats (D), 3 Independents (I)

b) P(all D)

n(all D): 1

n(all D)

P(all D) =

n(all selections)

n(all selections): 120


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A committee of 3 out of 10 members: 4 Republicans (R), 3 Democrats (D), 3 Independents (I)

b) P(all D)

n(all D): 1

n(all selections): 120

1

P(all D) =

120


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A committee of 3 out of 10 members: 4 Republicans (R), 3 Democrats (D), 3 Independents (I)

b) P(all D)

P(all D) = 0.0083


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n(one R, one D, one I):

4!

3!

3!

4C1

3C1

3C1

=

1!(3!)

1!(2!)

1!(2!)

A committee of 3 out of 10 members: 4 Republicans (R), 3 Democrats (D), 3 Independents (I)

c) P(one R, one D, one I)


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A committee of 3 out of 10 members: 4 Republicans (R), 3 Democrats (D), 3 Independents (I)

c) P(one R, one D, one I)

n(one R, one D, one I):

4C1

3C1

3C1

= 4 3 3


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A committee of 3 out of 10 members: 4 Republicans (R), 3 Democrats (D), 3 Independents (I)

c) P(one R, one D, one I)

n(one R, one D, one I):

4C1

3C1

3C1

= 36


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A committee of 3 out of 10 members: 4 Republicans (R), 3 Democrats (D), 3 Independents (I)

c) P(one R, one D, one I)

n(one R, one D, one I): 36

P(one R, one D, one I) =

n(one R, one D, one I)

n(all selections)

n(all selections): 120


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A committee of 3 out of 10 members: 4 Republicans (R), 3 Democrats (D), 3 Independents (I)

c) P(one R, one D, one I)

n(one R, one D, one I): 36

n(all selections): 120

P(one R, one D, one I) =

36

120


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A committee of 3 out of 10 members: 4 Republicans (R), 3 Democrats (D), 3 Independents (I)

c) P(one R, one D, one I)

P(one R, one D, one I) =0.300


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n(two D and one I):

3!

3!

3C2

3C1

=

2!(1!)

1!(2!)

A committee of 3 out of 10 members: 4 Republicans (R), 3 Democrats (D), 3 Independents (I)

d) P(two D and one I)


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A committee of 3 out of 10 members: 4 Republicans (R), 3 Democrats (D), 3 Independents (I)

d) P(two D and one I)

n(two D and one I):

3C2

3C1

= 3 3


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A committee of 3 out of 10 members: 4 Republicans (R), 3 Democrats (D), 3 Independents (I)

d) P(two D and one I)

n(two D and one I):

3C2

3C1

= 9


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A committee of 3 out of 10 members: 4 Republicans (R), 3 Democrats (D), 3 Independents (I)

d) P(two D and one I)

n(two D and one I): 9

n(two D and one I)

P(two D and one I) =

n(all selections)

n(all selections): 120


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A committee of 3 out of 10 members: 4 Republicans (R), 3 Democrats (D), 3 Independents (I)

d) P(two D and one I)

n(two D and one I): 9

n(all selections): 120

9

P(two D and one I) =

120


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A committee of 3 out of 10 members: 4 Republicans (R), 3 Democrats (D), 3 Independents (I)

d) P(two D and one I)

P(two D and one I) = 0.075


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n(one I and two R):

3!

4!

3C1

4C2

=

1!(2!)

2!(2!)

A committee of 3 out of 10 members: 4 Republicans (R), 3 Democrats (D), 3 Independents (I)

e) P(one I and two R)


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A committee of 3 out of 10 members: 4 Republicans (R), 3 Democrats (D), 3 Independents (I)

e) P(one I and two R)

n(one I and two R):

4 3

3C1

4C2

= 3

2 2


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A committee of 3 out of 10 members: 4 Republicans (R), 3 Democrats (D), 3 Independents (I)

e) P(one I and two R)

n(one I and two R):

12

3C1

4C2

= 3

2


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A committee of 3 out of 10 members: 4 Republicans (R), 3 Democrats (D), 3 Independents (I)

e) P(one I and two R)

n(one I and two R):

3C1

4C2

= 3 6


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A committee of 3 out of 10 members: 4 Republicans (R), 3 Democrats (D), 3 Independents (I)

e) P(one I and two R)

n(one I and two R):

3C1

4C2

= 18


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A committee of 3 out of 10 members: 4 Republicans (R), 3 Democrats (D), 3 Independents (I)

e) P(one I and two R)

n(one I and two R): 18

n(one I and two R)

P(one I and two R) =

n(all selections)

n(all selections): 120


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A committee of 3 out of 10 members: 4 Republicans (R), 3 Democrats (D), 3 Independents (I)

e) P(one I and two R)

n(one I and two R): 18

n(all selections): 120

18

P(one I and two R) =

120


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A committee of 3 out of 10 members: 4 Republicans (R), 3 Democrats (D), 3 Independents (I)

e) P(one I and two R)

P(one I and two R) =0.15


Section 11 881 l.jpg

Chapter 11

Section 11.8

Exercise #11


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Find the probability of selecting three science books and four math books from eight science books and nine math books. The books are selected at random.


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n(3 S and 4 M):

8!

9!

8C3

9C4

=

3!(5!)

4!(5!)

Select 3 science books (S) and 4 math books (M) from 8 science books and 9 math books.


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Select 3 science books (S) and 4 math books (M) from 8 science books and 9 math books.

n(3 S and 4 M):

8 7 6 5!

9 8 7 6 5!

8C3

9C4

=

3 2 1 5!

4 3 2 1 5!


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Select 3 science books (S) and 4 math books (M) from 8 science books and 9 math books.

n(3 S and 4 M):

336

3024

8C3

9C4

=

6

24


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Select 3 science books (S) and 4 math books (M) from 8 science books and 9 math books.

n(3 S and 4 M):

8C3

9C4

= 56 126


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Select 3 science books (S) and 4 math books (M) from 8 science books and 9 math books.

n(3 S and 4 M):

8C3

9C4

= 7056


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Select 3 science books (S) and 4 math books (M) from 8 science books and 9 math books.

n(3 S and 4 M): 7,056

n(all selections):

17!

17C7

=

7!(10!)


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Select 3 science books (S) and 4 math books (M) from 8 science books and 9 math books.

n(3 S and 4 M): 7,056

n(all selections):

17 16 15 14 13 12 11 10!

17C7

=

7 6 5 4 3 2 1 10!


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Select 3 science books (S) and 4 math books (M) from 8 science books and 9 math books.

n(3 S and 4 M): 7,056

n(all selections):

98,017,920

17C7

=

5040


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Select 3 science books (S) and 4 math books (M) from 8 science books and 9 math books.

n(3 S and 4 M): 7,056

n(all selections):

17C7

= 19,448


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Select 3 science books (S) and 4 math books (M) from 8 science books and 9 math books.

n(3 S and 4 M): 7,056

n(3 S and 4 M)

P(3 S and 4 M) =

n(all selections)

n(all selections): 19,448


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Select 3 science books (S) and 4 math books (M) from 8 science books and 9 math books.

n(3 S and 4 M): 7,056

n(all selections): 19,448

7,056

P(3 S and 4 M) =

19,448


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Select 3 science books (S) and 4 math books (M) from 8 science books and 9 math books.

P(3 S and 4 M) =0.363


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