1 / 40

Chapter 12: Momentum - PowerPoint PPT Presentation

  • Uploaded on

Chapter 12: Momentum. 12.1 Momentum 12.2 Force is the Rate of Change of Momentum 12.3 Angular Momentum. Chapter 12 Objectives. Calculate the linear momentum of a moving object given the mass and velocity. Describe the relationship between linear momentum and force.

I am the owner, or an agent authorized to act on behalf of the owner, of the copyrighted work described.
Download Presentation

PowerPoint Slideshow about ' Chapter 12: Momentum' - miracle

An Image/Link below is provided (as is) to download presentation

Download Policy: Content on the Website is provided to you AS IS for your information and personal use and may not be sold / licensed / shared on other websites without getting consent from its author.While downloading, if for some reason you are not able to download a presentation, the publisher may have deleted the file from their server.

- - - - - - - - - - - - - - - - - - - - - - - - - - E N D - - - - - - - - - - - - - - - - - - - - - - - - - -
Presentation Transcript
Chapter 12 momentum
Chapter 12: Momentum

12.1 Momentum

12.2 Force is the Rate of Change of Momentum

12.3 Angular Momentum

Chapter 12 objectives
Chapter 12 Objectives

Calculate the linear momentum of a moving object given the mass and velocity.

Describe the relationship between linear momentum and force.

Solve a one-dimensional elastic collision problem using momentum conservation.

Describe the properties of angular momentum in a system—for instance, a bicycle.

Calculate the angular momentum of a rotating object with a simple shape.

Chapter vocabulary
Chapter Vocabulary

  • angular momentum

  • collision

  • law of conservation of

  • momentum

  • elastic collision

  • gyroscope

  • impulse

  • inelastic collision

  • linear momentum

  • momentum

Inv 12 1 momentum
Inv 12.1 Momentum

Investigation Key Question:

What are some useful properties of momentum?

12 1 momentum
12.1 Momentum

  • Momentum is a property of moving matter.

  • Momentum describes the tendency of objects to keep going in the same direction with the same speed.

  • Changes in momentum result from forces or create forces.

12 1 momentum1
12.1 Momentum

  • The momentum of a ball depends on its mass and velocity.

  • Ball B has more momentum than ball A.

12 1 momentum and inertia
12.1 Momentum and Inertia

  • Inertia is another property of mass that resists changes in velocity; however, inertia depends only on mass.

  • Inertia is a scalar quantity.

  • Momentum is a property of moving mass that resists changes in a moving object’s velocity.

  • Momentum is a vector quantity.

12 1 momentum2
12.1 Momentum

  • Ball A is 1 kg moving 1m/sec, ball B is 1kg at 3 m/sec.

  • A 1 N force is applied to deflect the motion of each ball.

  • What happens?

  • Does the force deflect both balls equally?

  • Ball B deflects much less than ball A when the same force is applied because ball B had a greater initial momentum.

12 1 kinetic energy and momentum
12.1 Kinetic Energy and Momentum

  • Kinetic energy and momentum are different quantities, even though both depend on mass and speed.

  • Kinetic energy is a scalar quantity.

  • Momentum is a vector, so it always depends on direction.

Two balls with the same mass and speed have the same kinetic energy but opposite momentum.

12 1 calculating momentum

p = m v

12.1 Calculating Momentum

  • The momentum of a moving object is its mass multiplied by its velocity.

  • That means momentum increases with both mass and velocity.


(kg m/sec)

Velocity (m/sec)

Mass (kg)

Comparing momentum
Comparing momentum

A car is traveling at a velocity of 13.5 m/sec (30 mph) north on a straight road. The mass of the car is 1,300 kg. A motorcycle passes the car at a speed of 30 m/sec (67 mph). The motorcycle (with rider) has a mass of 350 kg. Calculate and compare the momentum of the car and motorcycle.

  • You are asked for momentum.

  • You are given masses and velocities.

  • Use: p = m v

  • Solve for car: p = (1,300 kg) (13.5 m/s) = 17,550 kg m/s

  • Solve for cycle: p = (350 kg) (30 m/s) = 10,500 kg m/s

    • The car has more momentum even though it is going much slower.

12 1 conservation of momentum
12.1 Conservation of Momentum

  • The law of conservation of momentum states when a system of interacting objects is not influenced by outside forces (like friction), the total momentum of the system cannot change.

If you throw a rock forward from a skateboard, you will move backward in response.

12 1 collisions in one dimension
12.1 Collisions in One Dimension

  • A collisionoccurs when two or more objects hit each other.

  • During a collision, momentum is transferred from one object to another.

  • Collisions can be elastic


Elastic collisions
Elastic collisions

Two 0.165 kg billiard balls roll toward each other and collide head-on.

Initially, the 5-ball has a velocity of 0.5 m/s.

The 10-ball has an initial velocity of -0.7 m/s.

The collision is elastic and the 10-ball rebounds with a velocity of 0.4 m/s, reversing its direction.

What is the velocity of the 5-ball after the collision?

Elastic collisions1
Elastic collisions

  • You are asked for 10-ball’s velocity after collision.

  • You are given mass, initial velocities, 5-ball’s final velocity.

  • Diagram the motion, use m1v1 + m2v2 = m1v3 + m2v4

  • Solve for V3 : (0.165 kg)(0.5 m/s) + (0.165 kg) (-0.7 kg)=

    (0.165 kg) v3 + (0.165 kg) (0.4 m/s)

  • V3 = -0.6 m/s

Inelastic collisions
Inelastic collisions

A train car moving to the right at 10 m/s collides with a parked train car.

They stick together and roll along the track.

If the moving car has a mass of 8,000 kg and the parked car has a mass of 2,000 kg, what is their combined velocity after the collision?

  • You are asked for the final velocity.

  • You are given masses, and initial velocity of moving train car.

Inelastic collisions1
Inelastic collisions

  • Diagram the problem, use m1v1 + m2v2 = (m1v1 +m2v2) v3

  • Solve for v3= (8,000 kg)(10 m/s) + (2,000 kg)(0 m/s)

    (8,000 + 2,000 kg)

    v3= 8 m/s

    The train cars moving together to right at 8 m/s.

12 1 collisions in 2 and 3 dimensions
12.1 Collisions in 2 and 3 Dimensions

  • Most real-life collisions do not occur in one dimension.

  • In a two or three-dimensional collision, objects move at angles to each other before or after they collide.

  • In order to analyze two-dimensional collisions you need to look at each dimension separately.

  • Momentum is conserved separatelyin the xand ydirections.

Chapter 12 momentum1
Chapter 12: Momentum

12.1 Momentum

12.2 Force is the Rate of Change of Momentum

12.3 Angular Momentum

12 2 force is the rate of change of momentum

Investigation Key Question:

How are force and momentum related?

12.2 Force is the Rate of Change of Momentum

12 2 force is the rate of change of momentum1
12.2 Force is the Rate of Change of Momentum

  • Momentum changes when a net force is applied.

  • The inverse is also true:

    • If momentum changes, forces are created.

  • If momentum changes quickly, large forces are involved.

12 2 force and momentum change

F = D p

D t

12.2 Force and Momentum Change

The relationship between force and motion follows directly from Newton's second law.

Force (N)

Change in momentum

(kg m/sec)

Change in time (sec)

Calculating force
Calculating force

  • You are asked for force exerted on rocket.

  • You are given rate of fuel ejection and speed of rocket

  • Use F = Δ ÷Δt

  • Solve: Δ = (100 kg) (-25,000 kg m/s) ÷ (1s) = - 25,000 N

    • The fuel exerts and equal and opposite force on rocket of +25,000 N.

Starting at rest, an 1,800 kg rocket takes off, ejecting 100 kg of fuel per second out of its nozzle at a speed of 2,500 m/sec. Calculate the force on the rocket from the change in momentum of the fuel.

12 2 impulse
12.2 Impulse

  • The product of a force and the time the force acts is called the impulse.

  • Impulse is a way to measure a change in momentum because it is not always possible to calculate force and time individually since collisions happen so fast.

12 2 force and momentum change1

F D t = D p

12.2 Force and Momentum Change

To find the impulse, you rearrange the momentum form of the second law.

Impulse (N•sec)

Change in



Impulse can be expressed in kg•m/sec (momentum units) or in N•sec.

Chapter 12 momentum2
Chapter 12: Momentum

12.1 Momentum

12.2 Force is the Rate of Change of Momentum

12.3 Angular Momentum

Inv 12 3 angular momentum

Investigation Key Question:

How does the first law apply to rotational motion?

Inv 12.3 Angular Momentum

12 3 angular momentum
12.3 Angular Momentum

  • Momentum resulting from an object moving in linear motion is called linear momentum.

  • Momentum resulting from the rotation (or spin) of an object is called angular momentum.

12 3 conservation of angular momentum
12.3 Conservation of Angular Momentum

  • Angular momentum is important because it obeys a conservation law, as does linear momentum.

  • The total angular momentum of a closed system stays the same.

12 3 calculating angular momentum

L = Iw

12.3 Calculating angular momentum

Angular momentum is calculated in a similar way to linear momentum, except the mass and velocity are replaced by the moment of inertia and angular velocity.

Moment of inertia

(kg m2)



(kg m/sec2)




12 3 calculating angular momentum1
12.3 Calculating angular momentum

  • The moment of inertia of an object is the average of mass times radius squared for the whole object.

  • Since the radius is measured from the axis of rotation, the moment of inertia depends on the axis of rotation.

Calculating angular momentum
Calculating angular momentum

An artist is making a moving metal sculpture. She takes two identical 1 kg metal bars and bends one into a hoop with a radius of 0.16 m. The hoop spins like a wheel. The other bar is left straight with a length of 1 meter. The straight bar spins around its center. Both have an angular velocity of 1 rad/sec. Calculate the angular momentum of each and decide which would be harder to stop.

  • You are asked for angular momentum.

  • You are given mass, shape, and angular velocity.

    • Hint: both rotate about y axis.

  • Use L= I, Ihoop = mr2, Ibar = 1/12 ml2

Calculating angular momentum1
Calculating angular momentum

  • Solve hoop: Ihoop= (1 kg) (0.16 m)2 = 0.026 kg m2

    • Lhoop= (1 rad/s) (0.026 kg m2) = 0.026 kg m2/s

  • Solve bar: Ibar= (1/12)(1 kg) (1 m)2 = 0.083 kg m2

    • Lbar = (1 rad/s) (0.083 kg m2) = 0.083 kg m2/s

  • The bar has more than 3x the angular momentum of the hoop, so it is harder to stop.

12 3 gyroscopes angular momentum
12.3 Gyroscopes angular momentum

  • A gyroscope is a device that contains a spinning object with a lot of angular momentum.

  • Gyroscopes can do amazing tricks because they conserve angular momentum.

  • For example, a spinning gyroscope can easily balance on a pencil point.

12 3 gyroscopes angular momentum1
12.3 Gyroscopes angular momentum

  • A gyroscope on the space shuttle is mounted at the center of mass, allowing a computer to measure rotation of the spacecraft in three dimensions.

  • An on-board computer is able to accurately measure the rotation of the shuttle and maintain its orientation in space.

Jet Engines

  • Nearly all modern airplanes use jet propulsion to fly. Jet engines and rockets work because of conservation of linear momentum.

  • A rocket engine uses the same principles as a jet, except that in space, there is no oxygen.

  • Most rockets have to carry so much oxygen and fuel that the payload of people or satellites is usually less than 5 percent of the total mass of the rocket at launch.