1 / 8

Altitudes and Medians

Altitudes and Medians. Median of A meets the mid point of BC. A. B. ( , ). x 1 +x 2 y 1 +y 2. Median. C. 2 2. m 1 m 2 = -1. Altitude. A. B. C. Altitude of A meets BC at right angles. A. Altitude from B. B. median from C. C. Altitudes and Medians.

milton
Download Presentation

Altitudes and Medians

An Image/Link below is provided (as is) to download presentation Download Policy: Content on the Website is provided to you AS IS for your information and personal use and may not be sold / licensed / shared on other websites without getting consent from its author. Content is provided to you AS IS for your information and personal use only. Download presentation by click this link. While downloading, if for some reason you are not able to download a presentation, the publisher may have deleted the file from their server. During download, if you can't get a presentation, the file might be deleted by the publisher.

E N D

Presentation Transcript


  1. Altitudes and Medians

  2. Median of A meets the mid point of BC A B ( , ) x1+x2 y1+y2 Median C 2 2

  3. m1m2 = -1 Altitude A B C Altitude of A meets BC at right angles

  4. A Altitude from B B median from C C

  5. Altitudes and Medians Altitude of A meets BC at right angles A m1m2 = -1 B ( , ) x1+x2y1+y2 2 2 C Median of A meets the mid point of BC

  6. A(2,1) B(5,8) C(9,6) are vertices of ABC Find equation of Altitude through B Need m and (a,b) ? perpendicular to AC C(9,6) √ mAC =6 - 1 = 5/7 9 – 2 B(5,8) maltB = - 7/5 A(2,1) use y – b = m(x – a)

  7. A(2,1) B(5,8) C(9,6) are vertices of ABC Find equation of Median through A √ Need m and (a,b) ? find mid point C(9,6) √ √ T (7 , 7) T = (7 , 7) B(5,8) find mAT either point will do A(2,1) use y – b = m(x – a)

  8. and Finally Perpendicular Bisector cut in half at right angles x1+x2y1+y2 2 2 m1m2 = -1

More Related