Base conversions method 1
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Base Conversions Method 1. (Any Base  Base 10). 1)Check the number for validity; each digit should be less than the base. . e.g. 102 4 is valid since each digit is less than the base. But 153 5 is invalid; 5 is not less than the base.

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Base Conversions Method 1

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Base conversions method 1

Base ConversionsMethod 1

(Any Base  Base 10)


1 check the number for validity each digit should be less than the base

1)Check the number for validity; each digit should be less than the base.


Base conversions method 1

e.g. 1024 is valid since each digit is less than the base. But 1535 is invalid; 5 is not less than the base.


Base conversions method 1

The person who started with this number was most likely checking work done with method 2, since method 1 is used to check method 2.


Base conversions method 1

2)Determine the positional value for each digit. Starting with the rightmost position, give it a value of 1 (base to the zero power).


Base conversions method 1

To determine the preceding positional values, multiply the current positional value by the base e.g. 3859 3 8 5 base 9 | | | 81 9 1


3 then multiply each digit by its positional value e g 3 x 81 243 8 x 9 72 5 x 1 5

3)Then multiply each digit by its positional valuee.g. 3 x 81 = 243 8 x 9 = 72 5 x 1 = 5


Base conversions method 1

3 x 81 = 243 8 x 9 = 72 5 x 1 = 54)and add them together ==== 320 this is the answer in base 10


Base conversions method 1

5)Finally, check the result for validity; each digit should be less than 10. (If it is not, then you did something wrong and should start over)


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