1 / 28

MPM 2D Hand Back & Take Up Day

MPM 2D Hand Back & Take Up Day. November 17 th , 2010. Analytic Geometry Test. KU – 11 marks. A rhombus is a parallelogram – TRUE A rectangle is a square – FALSE A perpendicular slope to 2/10 is -5 – TRUE Two points on the circle x 2 + y 2 = 16 (4, 0) (-4, 0) (0, 4) (0, -4)  easiest.

miach
Download Presentation

MPM 2D Hand Back & Take Up Day

An Image/Link below is provided (as is) to download presentation Download Policy: Content on the Website is provided to you AS IS for your information and personal use and may not be sold / licensed / shared on other websites without getting consent from its author. Content is provided to you AS IS for your information and personal use only. Download presentation by click this link. While downloading, if for some reason you are not able to download a presentation, the publisher may have deleted the file from their server. During download, if you can't get a presentation, the file might be deleted by the publisher.

E N D

Presentation Transcript

  1. MPM 2DHand Back & Take Up Day November 17th, 2010

  2. Analytic Geometry Test

  3. KU – 11 marks • A rhombus is a parallelogram – TRUE • A rectangle is a square – FALSE • A perpendicular slope to 2/10 is -5 – TRUE • Two points on the circle x2 + y2 = 16 (4, 0) (-4, 0) (0, 4) (0, -4) easiest

  4. KU – 11 marks (continued) • Distance between (2, 5) and (-6, 2) • Determine the midpoint of A(-3, -3) and B(1, 5)

  5. KU – 11 marks (continued) • FG is called a(n) perpendicular bisector, chord • BD is called a(n) median • AH is called a(n) altitude • LMN is a(n) right-angled scalene triangle • Point D is a(n) midpoint

  6. Part B - Application 8. Classify Quadrilateral ABCD. Justify. Opposite pairs of sides are equal. (One pair 8, one pair 5). Negative reciprocal slopes (1/3 and -3), this means 90° angles. Therefore, this quadrilateral is a rectangle.

  7. Part B – Application (continued) • Determine the equation of the altitude from Vertex A. A(-3, 4) B(5, 6) C(0, -4) Slope of BC:

  8. Part B – Application (continued) • Write the equation for a circle centered at (0,0) and passes through (-5, 2).

  9. Part B – Application (continued) 11. a) difference between the areas of circles: x2 + y2 = 125 and x2 + y2 = 200 b) Where is the point (2, 13)? (inside both, outside both, between).Justify. This circle has a radius of sqrt(173). This is larger than the sqrt(125) but less than the sqrt(200) and therefore lies between the two circles.

  10. Part B – Application (continued) 12. A plan is being constructed to connect houses in a new neighbourhood to a water main. A house located at (2, 9) is to be connected to a water main that runs along the line y = (2/3)x – 1. What is the minimum length of plastic pipe needed to connect the house to the water main? Assume all units are in meters.

  11. Question 12 - Solution Slope of Watermain = 2 / 3 Perpendicular slope = -3 / 2 Equation from house to water main: Find POI from house to water main: Calculate distance: House to water main: Therefore the minimum pipe length is approximately 7.2m long.

  12. Part B – Application (continued) 13. Curling Game. Rings have radius of 6ft. Rock is placed center at (5, 4) Rocks radius is 4.7”. Will it score? Distance to center of rock: 6ft * 12 = 72 inches The center of the rock is outside of the rings, so the radius of the rock comes into play. Distance to center of rock – radius of rock: 76.8 inches – 4.7 inches = 72.1 inches Therefore, there is 0.1 inches between the rings and the edge of the rock.The rock will not score. 6.4 * 12 = 76.8 inches

  13. Part B – Application (continued) 14. Show that the slope of JK is parallel to AC. Get K (midpoint of AB): Get J (midpoint of BC):

  14. Question #14 - continued Find slope of AC: Find slope of JK

  15. Linear Systems – Level 4

  16. Step #1 – Determine equations for each band. • Let C represent the total cost of the band, • Let h represent the number of hours the band would play. • Linear Systems  C = 65h + 400 • Coefficients  C = 80h + 250 • Prime Factors  C = 150h

  17. Step #2 – Table of Values

  18. Step #3 Graph

  19. Step #4 – Find POI Exactly where Coefficients and Linear Systems meet!! C = 150h C = 80h + 250 150h = 80h + 250 70h = 250 h = 250 / 70 **hours is approx 3.5714 C = 150h C = 150(250 / 70) C = 3750 / 7 **Cost is approx 535.7142

  20. Step #5 - TI Could confirm calculations using TI Calculator!!

  21. Step #6 - Conclusion • The problem does not specify how long the dance-a-thon will be ... so I am making a general conclusion for multiple lengths. • If the dance-a-thon is less than 3.5 hours in length (although this wouldn’t be a dance-a-thon in my opinion) SRB should decide to hire the Prime Factors as their band. They would be the cheapest for this length of dance. • If the dance-a-thon is somewhere between 3.5 hours and 10 hours in length (now this is more like the length of a dance-a-thon) SRB should decide to hire the Coefficients as their band. They are the cheapest for this length of dance. • If SRB is truly doing a dance-a-thon and going over 10 hours in length, they should hire the Linear Systems. They are the cheapest for this length of dance.

  22. Analytic GeometryPerformance Assessment Comments

  23. Application vs Thinking(evaluation categories) • Application • What everyone did! (You showed me what you knew!! ) • Applies knowledge & skills in familiar contexts • Transfers knowledge & skills into new contexts • Making connections between contexts • Concepts, representations, prior knowledge, real world, etc. • Thinking • What you need to work on! • Use of planning skills • Formulating and interpreting the problem, making conjectures, making a plan for solving the problem • Use of process skills • Carrying out a plan, looking back at solution (evaluating reasonableness, making arguments, reasoning, justifying, proving, reflecting) • Use of critical / creative thinking processes • Problem solving, inquiry From: Curriculum Achievement Chart

  24. What are we looking for … • Overall expectations … vs Specific expectations • Specific – solve using subsitution and elimination • Overall – solve problems involving intersection of straight lines • Thinking … vs Application • Creativity • Planning

  25. Next Steps … • Less calculations … what could have been: • Use grid to calculate slopes instead of slope formula every single time • Show one/two calculation(s) of distance, and estimate others for use in other problems • use technology (TI) to quickly calculate

  26. Next Steps … • Look at possible indicators on rubric: • Representing • Models – Diagrams – Accurate Calculations • Reasoning & Reflecting • Reasoning – Drawing Conclusions – Estimating – Assuming – Evaluating Results – Making Judgements – Planning – Reasonableness of … - Efficiency – Generalizing – Alternative Approaches • Communicating • Labelled Pictures – Graphs – Symbols – Notation Conventions – Explains & Justifies

  27. Effectiveness – Look Fors • Rubric – got this at PD Session • Look at Level 3 … (meeting expectations) • Multiple Strands • For now means overall expectations • For summative means – Analytic Geometry, Quadratics, Trigonometry

  28. Reflecting • Next time … will give at start (reflect as you go!) • For summative 50/50 for time – Task and Reflecting • Don’t want a regurgitation of what you said in the task … Thinking … • What if … • How could you have done it differently … • Is there another way to think about the image … • Most … If I had more time I would have calculated, calculated, calculated … what about summative?! • Does not specify grade 10 in reflection?! • Sample!

More Related