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Be 8 Decay

Be 8 Decay. Mass Be 8 = 8.005305 u. Excess mass = 9.9x10 -5 u. Mass He 4 = 4.002603 u. E released = D mc2 = (9.9x10 -5 u) c 2 (931.5 MeV/c 2 / u) = .0922 MeV. p 1. p 2. Momentum conservation:. Energy conservation:. Constituent equations:. Be 8 Decay (continued).

melvin-schmidt
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Be 8 Decay

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  1. Be8 Decay Mass Be8 = 8.005305 u Excess mass = 9.9x10-5 u Mass He4 = 4.002603 u Ereleased = Dmc2 = (9.9x10-5 u) c2 (931.5 MeV/c2 / u) = .0922 MeV p1 p2 Momentum conservation: Energy conservation: Constituent equations:

  2. Be8 Decay (continued) Energy Be8 = (8.005305 u) c2 (931.5 MeV/c2 / u) = 7456.94 MeV Energy He4 = 7456.94 MeV/2 = 3728.47 MeV Rest energy He4 = (4.002603 u) c2 (931.5 MeV/c2 / u) = 3728.42 MeV Kinetic energy He4 = 3728.47 - 3728.42 MeV = .05 MeV Momentum = Sqrt[E2/c2 –m2c2] = 19.3 MeV/c Classical kinetic energy = p2c2/(2 mc2) = .05 MeV g = 1.000013 b = .0052

  3. C14 Decay N14+ pe pn Mass C14 = 14.003242 u = 13044.020 MeV Mass N14 = 14.003074 u = 13043.863 MeV Mass e- = .511 MeV Mass N14+ = Mass N14 - Mass e- = 13043.352 MeV Excess Energy = .668 MeV Momentum conservation: Energy conservation: Constituent equations:

  4. C14 Decay (continued)

  5. C14 Decay – Fastest Electron n pe pN Momentum conservation: Energy conservation: Constituent equations:

  6. L Decay L pp pp Mass L = 1115.6 MeV Center of mass Mass p- = 139.6 MeV Mass p = 938.6 MeV Momentum conservation: Energy conservation: Constituent equations:

  7. L Decay Solved in Lab pp L pp Mass p = 938 MeV Mass p- = 139.6 MeV Momentum conservation: Energy conservation: Constituent equations: Mathematica solution

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