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## PowerPoint Slideshow about 'Using Set Theory ' - meadow

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Using Set Theory

- A ~ Set of Students Studying Math
- B ~ Set of Students Studying History
- A∩B ~ The intersection of sets A and B.
- (Students who study Math and History)

S

2 Sets are disjoint if their intersection is the empty set Ø

- Disjoint Sets

e.g. if C is the set of students studying grade 10 history and A is the set of students studying grade 12 math there are no grade 10 history students who study grade 12 math.

- A U B ~ The union of sets A and B, The set of all the elements in either A or B or both

- n(A) = the number of elements in set A elements in either A or B or both
- A’ = the set of elements not in A (called A’s compliment)

Union of Sets elements in either A or B or both

- A U B = {set of element in A or B (or both)}
- If n(A UB) = n(A) + n(B) the sets are disjoint.

The Union of Sets Generally elements in either A or B or both

- n( A UB) = n( A) + n( B) – n( A∩B )
- The number of members of set A or B

n( A UB) = n( A) + n( B) – n( A elements in either A or B or both∩B )

- e.g. A = set of DM Students
B = set of P.E. Students

There are 28 DM students and 25 PE students. 12 are in both. How many students in total are in DM or PE (or both)?

n(A)=28, n(B)=25, n( A∩B )=12

n( A UB) = n( A) + n( B) – n( A∩B )

=28 + 25 – 12

= 41

Example 2 elements in either A or B or both

Of the 120 students in a class, 30 speak Chinese, 50 speak Spanish, 75 speak French, 12 speak Spanish and Chinese, 30 speak Spanish and French, and 15 speak Chinese and French. Seven students speak all three languages. How many students speaks none of these languages?

7 speak all 3 elements in either A or B or both

15 speak Chinese and French

15

30 speak Spanish and French

12 speak Spanish and Chinese

23

5

50 speak Spanish

7

10

30 speak Chinese

37

8

75 Speak French

120 – 105 = 15 don’t speak any.

Homework elements in either A or B or both

- Page 270
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