CORKSCREW. QUESTION: The roller coaster is at the top of the hill 20m high and moving at a speed of 10m/sec. a ) (assume no friction) How fast will the coaster be moving at the bottom of the hill before going into the loop?.
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c) (in a perfect physics world) If the wind starts up after going out of the loop; a drag force is created to stop the coaster. Find the deceleration of the coaster if the coaster is running on a flat track.
Since gravitational potential energy is 0 at the bottom; PE and mass cancels out.
½v2 = ½v2
250 = ½v2
2 x 250 = v2
√500 = v
22.36 = v
PE + KE = PE + KE
Mgh + 1/2mv2 = mgh + 1/2mv2
(9.8)(20) + ½(10)2 = (9.8)(15) + ½ v2
196 + 50 = 147 + ½ v2
2(246-147) = v2
√198 = v
14.07 = v
CFd = ma½pv2CdA = ma ½(1.75)(22.36)2(0.8)(4) = 400a1399.91488 = 400a1399.91488/400 = a3.50 m/s2 = a