1 / 30

CH 19: Thermodynamics

CH 19: Thermodynamics. What happens to particles as they undergo phase change?. Consider: Kinetic energy Enthalpy Entropy Reversible? Spontaneous?. 19.1 Spontaneous Processes.

masher
Download Presentation

CH 19: Thermodynamics

An Image/Link below is provided (as is) to download presentation Download Policy: Content on the Website is provided to you AS IS for your information and personal use and may not be sold / licensed / shared on other websites without getting consent from its author. Content is provided to you AS IS for your information and personal use only. Download presentation by click this link. While downloading, if for some reason you are not able to download a presentation, the publisher may have deleted the file from their server. During download, if you can't get a presentation, the file might be deleted by the publisher.

E N D

Presentation Transcript


  1. CH 19: Thermodynamics

  2. What happens to particles as they undergo phase change? Consider: • Kinetic energy • Enthalpy • Entropy • Reversible? • Spontaneous?

  3. 19.1 Spontaneous Processes – process that occurs without any outside intervention, the internal energy alone determines if a reaction will occur

  4. Reversible process • When a system and surroundings is changed in such a way that they can be restored by reversing the change exactly • Whenever a chemical system is in equilibrium, reactants and products can interconvert reversibly • H2O(s) H2O (l)

  5. Irreversible Process - A change to a system and surroundings that can be restored by taking a new path to get back and changing the surroundings

  6. 19.2 Entropy • disorder of a system • The more disorder of a system, the larger the entropy • DS = Sfinal-Sinitial

  7. Entropy • When DS > 0, the system is disordered • When DS < 0, the system is more ordered or less random

  8. Second Law of Thermodynamics • states the entropy of the universe increases in any spontaneous process • (entropy is not conserved)

  9. 19.3 The Molecular Interpretation of Entropy • Entropy changes are related to the way the particles in a system can be arranged • Particles change through translational, vibrational, and rotational motion • Entropy and movement decrease with decreasing T

  10. Third Law of Thermodynamics

  11. Third Law of Thermodynamics • entropy of a pure crystalline substance at absolute zero (0 Kelvin) is zero

  12. Entropy Increases when: • 1. Liquids or solutions are formed from solids • 2.Gases are formed from either solids or liquids • 3. The number of molecules of gas increases during a chemical rxn

  13. Predict whether ΔSis positive or negative for each of the following processes, assuming each occurs at constant temperature: Sample Exercise 19.3 Predicting the Sign of ΔS

  14. Sample Exercise 19.4 Predicting Which Sample of Matter Has the Higher Entropy Choose the sample of matter that has greater entropy in each pair, and explain your choice: • 1 mol of NaCl(s) or 1 mol of HCl(g) at 25 °C, • 2 mol of HCl(g) or 1 mol of HCl(g) at 25 °C, • 1 mol of HCl(g) or 1 mol of Ar(g) at 298 K.

  15. 19.4 Entropy Changes in Rxns DS=qrev/T (note: T must be in Kelvin)

  16. 19.4 Entropy Changes in Rxns Standard Molar Entropies (So) • - the molar entropy values of substances in their standard states, pure substance at 1 atm; found on appendix C

  17. Standard Molar Entropies (So) • Characteristics: • 1. Molar entropies of elements are not 0 • 2. So (g) > So(l) >So (s) • 3. So increases w/ increasing MM • 4. Increase w/ increasing atoms

  18. Entropy Change • DSo = SnSo(products) - SmSo(reactants) , where m and n are coefficients of the balanced chemical eq

  19. Sample Exercise 19.5 Calculating ΔS from Tabulated Entropies • Calculate ΔSº for the synthesis of ammonia from N2(g) and H2(g) at 298 K: • N2(g) + 3 H2(g) → 2 NH3(g)

  20. 19.5 Gibbs Free Energy • DG = DH-TDS at constant temperature

  21. Relationship between G and spontaneity • 1. If DG is negative, the rxn is spontaneous in the forward direction (thermodynamically favored) • 2. If DG is zero, the rxn is at equilibrium • 3. If DG is positive, the rxn in the forward direction is nonspontaneous; work must be supplied from the surroundings to make it occur. The reverse rxn is spontaneous.

  22. Sample Exercise 19.6 Calculating Free-Energy Change from ΔH°, T, ΔS° • Calculate the standard free energy change for the formation of NO(g) from N2(g) and O2(g) at 298 K: • N2(g) + O2(g) → 2 NO(g) • given that ΔH° = 180.7 kJ and ΔS° = 24.7 J/K. • Is the reaction spontaneous under these circumstances?

  23. Standard Free-Energy Changes • DGo = SnGfo(products) - SmGfo(reactants)

  24. Standard Free-Energy Changes • When DG>0 (nonspontaneous), it is the measure of the minimum amount of work that must be done to cause the process to occur.

  25. Sample Exercise 19.7 Calculating Standard Free-Energy Change from Free Energies of Formation • (a) Use data from Appendix C to calculate the standard free-energy change for the following reaction at • 298 K: • P4(g) + 6 Cl2(g) → 4 PCl3(g)

  26. Sample Exercise 19.8 Estimating and Calculating ΔG° • C3H8(g) + 5 O2(g) → 3 CO2(g) + 4 H2O(l) ΔH° = –2220 kJ • (a) Without using data from Appendix C, predict whether ΔG° for this reaction is more negative or less negative than ΔH°. • (b) Use data from Appendix C to calculate the standard free-energy change for the reaction at 298 K. Is your prediction from part (a) correct?

  27. 19.6 Free Energy and Temperature • The value of T plays a major role in determining DG

  28. The Haber process for the production of ammonia involves the equilibrium Assume that ΔH°(-92.38kJ) and ΔS°(-198.3J/K) for this reaction do not change with temperature. (a) Predict the direction in which ΔG° for this reaction changes with increasing temperature. (b) Calculate the values ΔG° for the reaction at 25 °C and 500 °C. Sample Exercise 19.9 Determining the Effect of Temperature on Spontaneity

  29. 19.7 Free Energy and the Equilibrium Constant DG at nonstandard conditions: • DG= DGo + RTlnQ, where R is the ideal gas constant 8.314J/mol-K, T is abs T, and Q is the reaction quotient At Equilibrium: DG=0 and Q = Keq • DGo = - RT lnKeq • Keq= e-DG/RT

  30. Sample Exercise 19.12 Calculating an Equilibrium Constant for ΔG° Use standard free energies of formation to calculate the equilibrium constant, Keq, at 25 °C for the reaction involved in the Haber process: • (recall 19.9 DGo=-33.3kJ)

More Related