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### Ch 4

### 4.1 Exploring Nets

### 4.8 Volume of a Right Cylinder lateral surface, or label, would be a rectangle. The height of the label is the same height as the can. The length of the label is the diameter of the base of the can because the label wraps all the way around the can.

Measuring Prisms and Cylinders

Area of a Rectangle

- To find the area of a rectangle, multiply its length by its width.
- A = l x w

How do you find the area

- So, the area is 8.36 cm2.

Area of a Triangle

- To find the area of a triangle, multiply its base by its height, then divide by 2.
- Remember the height of a triangle is perpendicular to its base.
- The formula for the area of a triangle can be written:

Watch Brainpop: Area of Polygons

- http://www.brainpop.com/math/geometryandmeasurement/areaofpolygons/preview.weml

Area of a Circle Recall that is a non-terminating and a non-repeating decimal number. So, any calculations involving are approximate. You need to use the function on your calculator to be more accurate – 3.14 is not accurate enough.

- To find the area of a circle, use the formula:
- A = r 2
- where r represents the radius of the circle

Circumference of a Circle

- The perimeter of a circle is named the circumference.The circumference is given by: C = d or C = 2r (Recall: d = 2r)

Find the circumference of the circle.

The circumference of the circle is about 22 cm.

Find the radius of the circle.

- The circumference of a circle is 12.57 cm
- To find the radius of the circle, divide the circumference by 2.

The radius of the circle is about 2 cm.

Watch Brainpop: Circles

- http://www.brainpop.com/math/geometryandmeasurement/circles/preview.weml
- http://www.youtube.com/watch?v=lWDha0wqbcI

Try It

- Workbook pg 74 – 75
- Puzzle Package

Watch Brainpop: Review

- http://www.brainpop.com/math/numbersandoperations/pi/preview.weml
- http://www.brainpop.com/math/geometryandmeasurement/polygons/preview.weml
- http://www.brainpop.com/math/geometryandmeasurement/polyhedrons/preview.weml
- http://www.brainpop.com/math/geometryandmeasurement/typesoftriangles/preview.weml

http://www.youtube.com/watch?v=y0IDttNW1Wo&feature=related

A Prism

- A prism has 2 congruent bases and is named for its bases.
- When all its faces, other than the bases, are rectangles and they are perpendicular to the bases, the prism is a right prism.
- A regular prism has regular polygons as bases.

Pyramid

- A regular pyramid has a regular polygon as its base. Its other faces are triangles. They are named after its base.

Regular OctagonalPyramid

Regular Pentagonal Pyramid

Regular Square Pyramid

Describe the faces of:

- ACube
- 6 congruent squares

- A Right Square Pyramid
- 1 square, 4 congruent isosceles triangles

- A Right Pentagonal Prism
- 2 regular pentagons, 5 congruent rectangles

Nets

- A net is a diagram that can be folded to make an object. A net shows all the faces of an object
- http://www.senteacher.org/wk/3dshape.php

Nets

- A net is a two-dimensional shape that, when folded, encloses a three-dimensional object. http://www.youtube.com/watch?v=9KXuaT18Jyw&feature=related (quick)
- The same 3-D object can be created by folding different nets.
- You can draw a net for an object by visualizing what it would look like if you cut along the edges and flattened it out.
- http://www.youtube.com/watch?v=rMNa9wICWbo&feature=related

Turn to p. 178 of Textbook

This diagram is not a rectangular prism!

Here is the net being put together

p. 178 of TextbookExample #1c

This net has 2 congruent equilateral triangles and 3 congruent rectangles.

The diagram is a net of a right triangular prism. It has equilateral triangular bases.

p. 178 of TextbookExample #1d

This is not a net. The two triangular faces will overlap when folded, and the opposite face is missing.

Move one triangular face from the top right to the top left. It will now make a net of an octagonal pyramid.

p. 179 of TextbookExample #2

What is Surface Area?

- Surface area is the number of square units needed to cover a 3D object
- It is the sum of the areas of allthe faces of an object

Finding SA of a Rectangular Prism

- The SA of a rectangular prism is the sum of the areas of its rectangular faces. To determine the surface area of a rectangular prism, identify each side with a letter.
- Rectangle A has an area of
- A = l x w
- A = 4 x 5
- A = 20

- Rectangle B has an area of
- A = l x w
- A = 7 x 5
- A = 35

- Rectangle C has an area of
- A = l x w
- A = 7 x 4
- A = 28

- Rectangle A has an area of

C

B

A

Finding SA of a Rectangular Prism

- To calculate surface area we will need 2 of each side and add them together
- SA = 2(A) + 2(B) + 2(C)
- SA = 2(l x w) + 2(l x w) + 2(l x w)
- SA= 2(4 x 5) + 2(7 x 5) + 2(4 x 7)
- SA = 2(20) + 2(35) + 2(28)
- SA = 40 + 70 + 56
- SA = 166 in2

C

B

A

Finding SA of a Rectangular Prism

- Another Example
- SA = 2(A) + 2(B) + 2(C)
- SA = 2(l x w) + 2(l x w) + 2(l x w)
- SA= 2(8 x 10) + 2(7 x 8) + 2(10 x 7)
- SA = 2(80) + 2(56) + 2(70)
- SA = 160 + 112 + 140
- SA = 412 units2

C

B

A

Finding SA of a Rectangular Prism

- You Try
- SA = 2(A) + 2(B) + 2(C)
- SA = 2 (l x w) + 2(l x w) + 2 (l x w)
- SA= 2(15 x 6) + 2(10 x 6) + 2(10 x 15)
- SA = 2(90) + 2(60) + 2(150)
- SA = 180 + 120 + 300
- SA = 600 cm2

C

B

A

Some Video Reminders

- http://www.youtube.com/watch?v=oR1ukNC1pvA
- http://www.youtube.com/watch?v=agIV623B3nc&feature=related

Practice

- Pg p.186
- #4, 6,7,10,12,13,15

Surface area of a Right Triangular Prism

- To calculate the surface area of right triangular prism, draw out the net and calculate the surface area of each face and add them together.

Surface area of a Right Triangular Prism

- Draw and label the net

20cm

16cm

D

16cm

20cm

12cm

10cm

B

10cm

C

10cm

A

D

16cm

20cm

Surface area of a Right Triangular Prism

- SA = A area + B area + C area + 2 D area
- SA = A(l x w) +B(l x w) + C(l x w) + 2 * D[(b x h) ∕ 2)]
- SA = A(16 x 10) + B(10 x 12) + C(20 x 10) + 2 * D[(16 x 12) ∕ 2]
- SA = 160 + 120 + 200 + (2 * 96)
- SA = 160 + 120 + 200 + 192
- SA = 672 cm2

20cm

16cm

D

16cm

20cm

12cm

10cm

B

10cm

C

10cm

A

D

16cm

20cm

Surface area of a Right Triangular Prism

- Draw and label the net

10cm

6cm

D

6cm

10cm

8cm

15cm

B

15cm

C

15cm

A

D

6cm

10cm

Surface area of a Right Triangular Prism

- SA = A area + B area + C area + 2 D area
- SA = A(l x w) + B(l x w) + C(l x w) + 2 * D[(b x h) ∕ 2)]
- SA = A(15 x 6) + B(15 x 8) + C(15 x 10) + 2 * D[(6 x 8) ∕ 2]
- SA = 90 + 120 + 150 + (2 * 18)
- SA = 90 + 120 + 150 + 36
- SA = 396 cm2

10cm

6cm

D

6cm

10cm

8cm

15cm

B

15cm

C

15cm

A

D

6cm

10cm

Surface area of a Right Triangular Prism

- Draw and label the net

2.7m

1.4m

D

1.4m

2.7m

2.3m

0.7m

B

0.7m

C

0.7m

A

D

1.4m

2.7m

Surface area of a Right Triangular Prism

- SA = A area + B area + C area + 2 D area
- SA = (la x wa) + (lb x wb) + (lc x wc) + 2[(ld x wd) ∕ 2)]
- SA = (1.4 x 0.7) + (0.7 x 2.3) + (2.7 x 0.7) + 2 [(1.4 x 2.7) ∕ 2]
- SA = 0.98 + 1.61 + 1.89 + 2(1.89)
- SA = 8.26m2

2.7m

1.4m

D

1.4m

2.7m

2.3m

0.7m

B

0.7m

C

0.7m

A

D

1.4m

2.7m

Surface area of a Right Triangular Prism

- Draw and label the net

? m

3m

D

3m

?m

8cm

7 m

B

7 m

7 m

C

7 m

A

D

3cm

?m

Surface area of a Right Triangular Prism

- Before you can solve, you need to find the missing side using Pythagorean Theorem!

? m

3m

D

3m

?m

8cm

7 m

B

7 m

C

7 m

A

D

3cm

?m

Surface area of a Right Triangular Prism

- Pythagorean Theorem
- a2 + b2 = h2
- 32 + 82 = h2
- 9 + 64 = h2
- 73 = h2
- √73 = √ h2
- 8.54 = h

8.54m

3m

8.54m

3m

8m

7 m

7 m

7 m

3m

?m

Surface area of a Right Triangular Prism

- SA = A area + B area + C area + 2 D area
- SA = A(l x w) + B(l x w) + C(l x w) + 2 * D[(l x w) ∕ 2)]
- SA = A(3 x 7) + B(7 x 8) + C(8.54 x 7) + 2 * D[(3x 8) ∕ 2]
- SA = 21 + 56 + 59.78 + (2 * 12)
- SA = 21 + 56 + 59.78 + 24
- SA = 160.78 m2

8.54m

3m

D

8.54m

3m

8m

7 m

B

C

7 m

7 m

A

D

3m

?m

Some Review Videos

- http://www.youtube.com/watch?v=9pQknZ9fRTA
- http://www.youtube.com/watch?v=mL7E_NBhyIw&feature=related

Practice

- P. 191

Videos

- VIDEO Volume of a right rectangle
- http://www.youtube.com/watch?v=HYyBP4K65TI

The Formula

- V = Ah
- Volume equals the area of the base of the rectangle times its height – this applies to all right cylinders or prisms
- http://www.youtube.com/watch?v=QR22Zvpj3L4&feature=relmfu

Example 1

- V = Ah
- V = (l x w) x h
- V = (13.5 x 5) x 18.5
- V = 67.5 x 18.5 (not really needed)
- V = 1248.75 cm3

Example 2

Jack’s family opened a full carton of frozen yogurt for dessert. After they ate, there was ¾ left. Jack wants to know what volume of frozen yogurt they ate. He measured the carton to be to have a length of 12cm, a width or 9 cm and a height of 18cm.

- V = Ah
- V = (l x w) x h
- V = (12 x 9) x 18
- V = 1944 cm3 (Volume of entire container – we want ¾ of the container )
- V = 1944 x ¾
- V = 1458 cm3

Workbook

- Read “Quick Review” on pg. 85
- Complete pg 85-86

Video Clip

- Relationship of a right triangular prism with right rectangular prism
- http://www.youtube.com/watch?v=NqlyyVrHnp8

Formula

- Volume is equal to the area of the base of the triangle times the length
- V = Al

Example 2

- A glass vase in the shape of a right triangular prism is filled with colouredsand as a decoration. What is the volume of the vase. It measured 15cm by 8cm by 80cm
- V = Al
- V = (b * h /2) x l
- V = (15 x 8 /2) x 80
- V = 60 x 80
- V = 4800 cm3

Watch Brainpop: Volume of Prisms

- http://www.brainpop.com/math/geometryandmeasurement/volumeofprisms/preview.weml

Workbook

- Complete pg. 87 - 89

Formula

- http://www.youtube.com/watch?v=GpHhvuRbB-8

- Imagine a can. If you unwrap the label off the can, the lateral surface, or label, would be a rectangle. The height of the label is the same height as the can. The length of the label is the diameter of the base of the can because the label wraps all the way around the can.

Notes lateral surface, or label, would be a rectangle. The height of the label is the same height as the can. The length of the label is the diameter of the base of the can because the label wraps all the way around the can.

- To find the surface area of a cylinder – sketch the net
- Remember that the width of the rectangle will be equal to the circumference of the circle (2πr)
- SA = 2(area of a circle) + area of the rectangle

Example 1 lateral surface, or label, would be a rectangle. The height of the label is the same height as the can. The length of the label is the diameter of the base of the can because the label wraps all the way around the can.

SA = 2πr2 + (2πr)(h)

SA = 2π(3.1)2 + (2π(3.1))(12)

SA = 2π(9.61)+ (2π(3.1))(12)

SA = 120.762822 + 230.734493

SA = 354.50inches2

Example 2 lateral surface, or label, would be a rectangle. The height of the label is the same height as the can. The length of the label is the diameter of the base of the can because the label wraps all the way around the can.

SA = 2πr2 + (2πr)(h)

SA = 2π(9)2 + (2π(9))(11)

SA = 2π(81)+ (2π(9))(11)

SA = 508.938010 + 622.035345

SA = 1130.97m2

11m

9m

Example 3 lateral surface, or label, would be a rectangle. The height of the label is the same height as the can. The length of the label is the diameter of the base of the can because the label wraps all the way around the can.

- Calculate the outside surface area of the cylinder. The cylinder is open on one end.
SA = πr2 + (2πr)(h)

SA = π(3)2 + (2π(3))(11)

SA = π(9)+ (2π(3))(11)

SA = 28.274333 + 207.345115

SA = 235.62m2

8m

3m

Review Video lateral surface, or label, would be a rectangle. The height of the label is the same height as the can. The length of the label is the diameter of the base of the can because the label wraps all the way around the can.

- http://www.youtube.com/watch?v=5GODwuQxYNo&feature=related

Workbook lateral surface, or label, would be a rectangle. The height of the label is the same height as the can. The length of the label is the diameter of the base of the can because the label wraps all the way around the can.

- Complete pg 90 - 92

The Formula lateral surface, or label, would be a rectangle. The height of the label is the same height as the can. The length of the label is the diameter of the base of the can because the label wraps all the way around the can.

- Cylinders follow the same properties as prisms for volume
- V = area of the base x height
- V = πr2 x h

Example 1 lateral surface, or label, would be a rectangle. The height of the label is the same height as the can. The length of the label is the diameter of the base of the can because the label wraps all the way around the can.

V = πr2 x h

V = π(22)x 6

V = π(4) x 6

V = 12.6 x 6

V = 75.6 m3

6m

2m

Example 2 lateral surface, or label, would be a rectangle. The height of the label is the same height as the can. The length of the label is the diameter of the base of the can because the label wraps all the way around the can.

- Martha has a choice of two different popcorn containers at a movie. Both containers are the same price. Which container should Martha buy is she wants more popcorn for her money.
- Container 1: has a diameter of 20cm and height of 40cm.
- Container 2 has a diameter of 30cm and a height of 20cm.

Container 1 lateral surface, or label, would be a rectangle. The height of the label is the same height as the can. The length of the label is the diameter of the base of the can because the label wraps all the way around the can.

Container 2

Radius is half the diameter so r = 15cm

V = πr2 x h

V = π(152)x 20

V = π(225) x 20

V = 706.9 x 20

V = 14138 cm3

- Radius is half the diameter so r = 10cm
V = πr2 x h

V = π(102)x 40

V = π(100) x 40

V = 314.2 x 40

V = 12568 cm3

Watch lateral surface, or label, would be a rectangle. The height of the label is the same height as the can. The length of the label is the diameter of the base of the can because the label wraps all the way around the can.Brainpop: Volume of Cylinders

- http://www.brainpop.com/math/geometryandmeasurement/volumeofcylinders/preview.weml

Workbook lateral surface, or label, would be a rectangle. The height of the label is the same height as the can. The length of the label is the diameter of the base of the can because the label wraps all the way around the can.

- Complete pg 93 - 94

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