1 / 22

Applied Partitioning and Scaling Your (OLTP) Database System

Applied Partitioning and Scaling Your (OLTP) Database System. Phil Hildebrand phil.hildebrand@gmail.com thePlatform for Media, Inc. Objectives . Review classic uses of database partitioning Applying partitioning to MySQL OLTP applications Hash partitioning with MySQL OLTP applications

Download Presentation

Applied Partitioning and Scaling Your (OLTP) Database System

An Image/Link below is provided (as is) to download presentation Download Policy: Content on the Website is provided to you AS IS for your information and personal use and may not be sold / licensed / shared on other websites without getting consent from its author. Content is provided to you AS IS for your information and personal use only. Download presentation by click this link. While downloading, if for some reason you are not able to download a presentation, the publisher may have deleted the file from their server. During download, if you can't get a presentation, the file might be deleted by the publisher.

E N D

Presentation Transcript


  1. Applied Partitioning and Scaling Your (OLTP) Database System • Phil Hildebrand • phil.hildebrand@gmail.com • thePlatform for Media, Inc.

  2. Objectives • Review classic uses of database partitioning • Applying partitioning to MySQL OLTP applications • Hash partitioning with MySQL OLTP applications • Implementation examples • Q&A

  3. Classic Partitioning • Old School – union in the archive tables • Auto partitioning and partition pruning • Lends itself to Data Warehouses • Archival and Date based partitioning • Predictable growth patterns • Benefits within Data Warehouses • Maintenance benefits • Query performance improved

  4. Applying Partitioning to OLTP • Design Issues • Often id driven access vs. date driven access • Difficulties in estimating partition ranges / sizes • Intelligent keys increase complexity in partitions • Operational Issues • Difficult to schedule downtime for DDL changes • General lack of use outside of data warehousing

  5. Applying Partitioning to OLTP • Understanding the Benefits • Reducing seek and scan set sizes • Limiting insert / update transaction durations • Creates additional options for Maint processes

  6. Reducing scan/seek set sizes mysql> explain partitions select my_store.city,my_employee_old.name from my_store, my_employee_old where my_store.id in (5,8,10) and my_store.id = my_employee_old.store_id and my_employee_old.id = (ROUND(RAND()*50000,0)); +---+-------------+-----------------+------------+-------+---------------+---------+---------+------+-------+--------------------------------+ |id | select_type | table | partitions | type | possible_keys | key | key_len | ref | rows | Extra | +---+-------------+-----------------+------------+-------+---------------+---------+---------+------+-------+--------------------------------+ | 1 | SIMPLE | my_store | p5,p8,p10 | range | PRIMARY | PRIMARY | 8 | NULL | 3 | Using where | | 1 | SIMPLE | my_employee_old | NULL | ALL | NULL | NULL | NULL | NULL | 47483 | Using where; Using join buffer | +_--+-------------+-----------------+------------+-------+---------------+---------+---------+------+-------+--------------------------------+ mysql> explain partitions select my_store.city,my_employee.name from my_store, my_employee where my_store.id in (5,8,10) and my_store.id = my_employee.store_id and my_employee.id = (ROUND(RAND()*50000,0)); +----+-------------+-------------+------------+-------+---------------+---------+---------+------+------+--------------------------------+ | id | select_type | table | partitions | type | possible_keys | key | key_len | ref | rows | Extra | +----+-------------+-------------+------------+-------+---------------+---------+---------+------+------+--------------------------------+ | 1 | SIMPLE | my_store | p5,p8,p10 | range | PRIMARY | PRIMARY | 8 | NULL | 3 | Using where | | 1 | SIMPLE | my_employee | p5,p8,p10 | ALL | NULL | NULL | NULL | NULL | 2979 | Using where; Using join buffer | +----+-------------+-------------+------------+-------+---------------+---------+---------+------+------+--------------------------------+

  7. Simple join with out partitions $ time mysqlslap -u root --create-schema=conf --query=sel_store_employee_old.sql -c 5 -i 1000 -F ";" Benchmark Average number of seconds to run all queries: 0.141 seconds Minimum number of seconds to run all queries: 0.101 seconds Maximum number of seconds to run all queries: 0.213 seconds Number of clients running queries: 5 Average number of queries per client: 1 real 2m22.018s user 0m0.217s sys 0m0.445s

  8. Simple join with partitions $ time mysqlslap -u root --create-schema=conf --query=sel_store_employee.sql -c 5 -i 1000 -F ";" • Benchmark • Average number of seconds to run all queries: 0.006 seconds • Minimum number of seconds to run all queries: 0.005 seconds • Maximum number of seconds to run all queries: 0.025 seconds • Number of clients running queries: 5 • Average number of queries per client: 1 • real 0m6.660s • user 0m0.133s • sys 0m0.306s

  9. Rebuilding by partition • mysql> optimize table my_employee_old; • +----------------------+----------+----------+----------+ • | Table | Op | Msg_type | Msg_text | • +----------------------+----------+----------+----------+ • | conf.my_employee_old | optimize | status | OK | • +----------------------+----------+----------+----------+ • 1 row in set (1.14 sec) • mysql> alter table my_employee rebuild partition p1; • Query OK, 0 rows affected (0.03 sec) • Records: 0 Duplicates: 0 Warnings: 0 • mysql> alter table my_employee rebuild partition p1,p2,p3,p4,p5,p6,p7,p8,p9,p10; • Query OK, 0 rows affected (0.27 sec) • Records: 0 Duplicates: 0 Warnings: 0

  10. Applying Partitioning to OLTP • Design Considerations • Table sizes and predicted growth patterns • Access patterns • Keys and indexes • Availability and Scalability requirements • Manageability considerations • Reuse considerations

  11. Choosing a Partitioning Method • Range Partitioning • Data usually accessed by date • Limited number of (primary) partitions needed • Ordered Intelligent keys • Supports Sub Partitions • List Partitioning • Grouping data in partitions out of order (1,5,7 in partition x) • Limited number of (primary) partitions needed • Intelligent keys • Supports Sub Partitions • Hash Partitioning • Low maintenance • Works with limited or large number of partitions • Non-intelligent keys (can work with some cases of intelligent keys) • Key Partitioning • Non-integer based partitioned keys (md5 hash) • Low maintenance

  12. Hash Partitioning and OLTP • Applying a hash to the partitioning key • Hash Partitions • Key Partitions • Fixed number of partitions • Number of partitions determined by hash (mod%num_partitions)

  13. My Retail Store App mysql> show columns from my_inventory; +----------+-------------+------+-----+---------+ | Field | Type | Null | Key | Default | +----------+-------------+------+-----+---------+ | id | bigint(20) | NO | PRI | NULL | | store_id | bigint(20) | NO | PRI | NULL | | name | varchar(56) | YES | | NULL | | in_stock | bit(1) | YES | | NULL | | on_order | bit(1) | YES | | NULL | | item_cnt | bigint(20) | YES | | NULL | | cost | float | YES | | NULL | +----------+-------------+------+-----+---------+ mysql> show columns from my_store; +---------+--------------+------+-----+---------+ | Field | Type | Null | Key | Default | +---------+--------------+------+-----+---------+ | id | bigint(20) | NO | PRI | NULL | | city | varchar(128) | YES | | NULL | | country | varchar(128) | YES | | NULL | +---------+--------------+------+-----+---------+ mysql> show columns from my_employee; +----------+-------------+------+-----+---------+ | Field | Type | Null | Key | Default | +----------+-------------+------+-----+---------+ | id | bigint(20) | NO | PRI | NULL | | store_id | bigint(20) | NO | PRI | NULL | | name | varchar(56) | YES | | NULL | +----------+-------------+------+-----+---------+

  14. Applying Hash Partitioning • Partition on Store ID • mysql> ALTER TABLE MY_STORE PARTITION BY HASH (id) PARTITIONS 50 ; • Query OK, 50 rows affected (0.76 sec) • Records: 50 Duplicates: 0 Warnings: 0 • mysql> ALTER TABLE MY_EMPLOYEE PARTITION BY HASH (store_id) PARTITIONS 50 ; • Query OK, 50000 rows affected (25.28 sec) • Records: 50000 Duplicates: 0 Warnings: 0 • mysql> ALTER TABLE MY_INVENTORY PARTITION BY HASH (store_id) PARTITIONS 50 ; • Query OK, 250000 rows affected (2 min 8.32 sec) • Records: 250000 Duplicates: 0 Warnings: 0

  15. Splitting Partitions • Expanding into Australia with 2 new stores: • mysql> ALTER TABLE MY_STORE ADD PARTITION PARTITIONS 2; • Query OK, 0 rows affected (0.86 sec) • Records: 0 Duplicates: 0 Warnings: 0 • mysql> ALTER TABLE MY_EMPLOYEE ADD PARTITION PARTITIONS 2; • Query OK, 0 rows affected (2.43 sec) • Records: 0 Duplicates: 0 Warnings: 0 • mysql> ALTER TABLE MY_INVENTORY ADD PARTITION PARTITIONS 2; • Query OK, 0 rows affected (7.60 sec) • Records: 0 Duplicates: 0 Warnings: 0

  16. Splitting Partitions mysql> select table_name,partition_name,table_rows -> from information_schema.partitions -> where table_schema = 'conf' -> and table_name in ('MY_STORE','MY_INVENTORY','MY_EMPLOYEE') -> and table_rows < 1; +--------------+----------------+------------+ | table_name | partition_name | table_rows | +--------------+----------------+------------+ | my_employee | p0 | 0 | | my_employee | p51 | 0 | | my_inventory | p0 | 0 | | my_inventory | p51 | 0 | | my_store | p0 | 0 | | my_store | p51 | 0 | +--------------+----------------+------------+

  17. Merging Partitions • Closing All Stores in China (4 stores) : • mysql> ALTER TABLE MY_STORE COALESCE PARTITION 4; • Query OK, 0 rows affected (0.40 sec) • Records: 0 Duplicates: 0 Warnings: 0 • mysql> ALTER TABLE MY_EMPLOYEE COALESCE PARTITION 4; • Query OK, 0 rows affected (2.71 sec) • Records: 0 Duplicates: 0 Warnings: 0 • mysql> ALTER TABLE MY_INVENTORY COALESCE PARTITION 4; • Query OK, 0 rows affected (7.81 sec) • Records: 0 Duplicates: 0 Warnings: 0

  18. Merging Partitions • Closing All Stores in China (4 stores) : • mysql> select table_name,count(*) • -> from information_schema.partitions • -> where table_schema = 'conf' • -> and table_name in ('MY_STORE','MY_INVENTORY','MY_EMPLOYEE') • -> group by table_name; • +--------------+----------+ • | table_name | count(*) | • +--------------+----------+ • | my_employee | 48 | • | my_inventory | 48 | • | my_store | 48 | • +--------------+----------+

  19. A Few More Stats… (No Partitions) mysql> explain partitions select my_store_no_part.city,my_employee_no_part.name,count(*) from my_store_no_part, my_employee_no_part, my_inventory_no_part where my_store_no_part.id in (5,8,10,23,80) and my_store_no_part.id = my_employee_no_part.store_id and my_store_no_part.id = my_inventory_no_part.store_id and my_employee_no_part.id < 2000 and my_inventory_no_part.in_stock = (ROUND(RAND(),0)) group by my_store_no_part.city,my_employee_no_part.name; +---+-------------+----------------------+------------+--------+---------------+---------+---------+-----------------------------------+--------+----------------------------------------------+ |id | select_type | table | partitions | type | possible_keys | key | ref | rows | Extra | +---+-------------+----------------------+------------+--------+---------------+---------+---------+-----------------------------------+--------+----------------------------------------------+ | 1 | SIMPLE | my_employee_no_part | NULL | range | PRIMARY | PRIMARY | NULL | 3962 | Using where; Using temporary; Using filesort | | 1 | SIMPLE | my_store_no_part | NULL | eq_ref | PRIMARY | PRIMARY | conf.my_employee_no_part.store_id | 1 | | | 1 | SIMPLE | my_inventory_no_part | NULL | ALL | NULL | NULL | NULL | 508243 | Using where; Using join buffer | +----+-------------+----------------------+------------+--------+---------------+---------+---------+-----------------------------------+--------+----------------------------------------------+ mysql> select my_store_no_part.city,my_employee_no_part.name,count(*) from my_store_no_part, my_employee_no_part, my_inventory_no_part where my_store_no_part.id in (5,8,10,23,80) and my_store_no_part.id = my_employee_no_part.store_id and my_store_no_part.id = my_inventory_no_part.store_id and my_employee_no_part.id < 2000 and my_inventory_no_part.in_stock = (ROUND(RAND(),0)) group by my_store_no_part.city,my_employee_no_part.name; +----------+-------------+----------+ | city | name | count(*) | +----------+-------------+----------+ | Delhi | Employee #0 | 60453 | | Istanbul | Employee #0 | 79707 | | Karachi | Employee #0 | 59872 | | Seoul | Employee #0 | 37432 | +----------+-------------+----------+ 4 rows in set (16.45 sec)

  20. A Few More Stats… (Partitions) mysql> explain partitions select my_store_lrg.city,my_employee_lrg.name,count(*) from my_store_lrg, my_employee_lrg, my_inventory_lrg where my_store_lrg.id in (5,8,10,23,80) and my_store_lrg.id = my_employee_lrg.store_id and my_store_lrg.id = my_inventory_lrg.store_id and my_employee_lrg.id < 2000 and my_inventory_lrg.in_stock = (ROUND(RAND(),0)) group by my_store_lrg.city,my_employee_lrg.name; +---+-------------+------------------+-------------------+--------+---------------+---------+---------+-------------------------------+-------+----------------------------------------------+ |id | select_type | table | partitions | type | possible_keys | key | ref | rows | Extra | +---+-------------+------------------+-------------------+--------+---------------+---------+---------+-------------------------------+-------+----------------------------------------------+ |1 | SIMPLE | my_employee_lrg | p5,p8,p10,p23,p80 | range | PRIMARY | PRIMARY | NULL | 94 | Using where; Using temporary; Using filesort | |1 | SIMPLE | my_store_lrg | p5,p8,p10,p23,p80 | eq_ref | PRIMARY | PRIMARY | conf.my_employee_lrg.store_id | 1 | | |1 | SIMPLE | my_inventory_lrg | p5,p8,p10,p23,p80 | ALL | NULL | NULL | NULL | 47938 | Using where; Using join buffer | +----+-------------+------------------+-------------------+--------+---------------+---------+---------+-------------------------------+-------+----------------------------------------------+ mysql> select my_store_lrg.city,my_employee_lrg.name,count(*) from my_store_lrg, my_employee_lrg, my_inventory_lrg where my_store_lrg.id in (5,8,10,23,80) and my_store_lrg.id = my_employee_lrg.store_id and my_store_lrg.id = my_inventory_lrg.store_id and my_employee_lrg.id < 2000 and my_inventory_lrg.in_stock = (ROUND(RAND(),0)) group by my_store_lrg.city,my_employee_lrg.name; +----------+-------------+----------+ | city | name | count(*) | +----------+-------------+----------+ | Delhi | Employee #0 | 60041 | | Istanbul | Employee #0 | 77721 | | Karachi | Employee #0 | 59786 | | Seoul | Employee #0 | 36237 | +----------+-------------+----------+ 4 rows in set (1.89 sec)

  21. Summing it Up • Partitioning provides an easy way to scale within a database • Partitioning has a place in OLTP • Remember access methods and maintenance • Use Range/List for intelligent partitioning • Use Hash/Key for low maintenance, many partitions

  22. Questions Anyone?

More Related