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# Warm-up - PowerPoint PPT Presentation

Warm-up. Convert the following: 4.5 atm = _____ kPa 845.6 torr = _____ kPa 103.5 kPa = _____ mm Hg. Boyle’s Law: P and V. as one increases , the other decreases inversely proportional P 1 = P 2 V 2 V 1. Example: Boyle’s Law.

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Presentation Transcript

Convert the following:

4.5 atm = _____ kPa

845.6 torr = _____ kPa

103.5 kPa = _____ mm Hg

• as one increases,

• the other decreases

• inversely proportional

P1 = P2

V2 V1

Consider a 1.53-L sample of gaseous SO2 at a pressure of 5.6 x 103 Pa. If the pressure is changed to 1.5 x 104 Pa at constant temperature, what will be the new volume of the gas?

• if P is constant, gases expand when heated

• when T increases, gas molecules move faster and collide with the walls more often and with greater force

• to keep the P constant, the V must increase

• Charles’ Law: the V of fixed mass of gas at constant P varies directly with Kelvin T.

• V = kT

• k is a constant for a certain sample of gas that depends on the mass of gas and P

• What kind of graph is V vs. T?

• discovered by French physicist, Jacques Charles in 1787

• first person to fill balloon with hydrogen gas and make solo balloon flight

A sample of gas at 15°C and 1 atm has a volume of 2.58 L. What volume will this gas occupy at 38°C and 1 atm?

• Gay-Lussac’s Law: the P of fixed mass of gas at constant V varies directly with Kelvin T.

• What kind of graph is P vs. T?

The gas in an aerosol can is at a pressure of 3.00 atm at 25°C. Directions on the can warn the user not to keep the can in a place where temperature exceeds 52°C. What would the gas pressure be in the can at 52°C?

Boyle’s

P V

T

Gay-Lussac’s

Charles’

• P1V1 = P2V2

T1 T2