Arithmetic
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Arithmetic. Sequences & Series By: Jeffrey Bivin Lake Zurich High School [email protected] Last Updated: April 28, 2006. Arithmetic Sequences. 5, 8, 11, 14, 17, 20, … 3n+2, … -4, 1, 6, 11, 16, … 5n – 9, . . . 11, 7, 3, -1, -5, … -4n + 15,. Jeff Bivin -- LZHS.

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Arithmetic

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Arithmetic

Arithmetic

Sequences & Series

By: Jeffrey Bivin

Lake Zurich High School

[email protected]

Last Updated: April 28, 2006


Arithmetic sequences

Arithmetic Sequences

5, 8, 11, 14, 17, 20, … 3n+2, …

-4, 1, 6, 11, 16, … 5n – 9, . . .

11, 7, 3, -1, -5, … -4n + 15, . . .

Jeff Bivin -- LZHS


N th term of arithmetic sequence

nth term of arithmetic sequence

an = a1 + d(n – 1)

Jeff Bivin -- LZHS


Find the n th term of an arithmetic sequence

Find the nth term of an arithmetic sequence

First term is 8

Common difference is 3

an = a1 + d(n – 1)

an = 8 + 3(n – 1)

an = 8 + 3n – 3

an = 3n + 5

Jeff Bivin -- LZHS


Finding the n th term

Finding the nth term

First term is -6

common difference is 7

an = a1 + d(n – 1)

an = -6 + 7(n – 1)

an = -6 + 7n – 7

an = 7n - 13

Jeff Bivin -- LZHS


Finding the n th term1

Finding the nth term

First term is 23

common difference is -4

an = a1 + d(n – 1)

an = 23 + -4(n – 1)

an = 23 -4n +4

an = -4n + 27

Jeff Bivin -- LZHS


Finding the 100 th term

Finding the 100th term

a1 = 5

d = 6

n = 100

5, 11, 17, 23, 29, . . .

an = a1 + d(n – 1)

a100 = 5 + 6(100 – 1)

a100 = 5 + 6(99)

a100 = 5 + 594

a100 = 599

Jeff Bivin -- LZHS


Finding the 956 th term

Finding the 956th term

a1 = 156

d = -16

n = 956

156, 140, 124, 108, . . .

an = a1 + d(n – 1)

a956 = 156 + -16(956 – 1)

a956 = 156 - 16(955)

a956 = 156 - 15280

a956 = -15124

Jeff Bivin -- LZHS


Find the sum of the integers from 1 to 100

Find the Sum of the integers from 1 to 100

S100 = 1 + 2 + 3 +…+ 49 + 50 + 51 + 52 +…+ 98 + 99 + 100

S100 = 100 + 99 + 98 +…+ 52+51 + 50 + 49 +…+ 3 + 2 + 1

2S100 = 101+101+101+…+101+101+101+101+…+101+101+101

2S100 = 100 (101)

Jeff Bivin -- LZHS


Summing it up

Summing it up

Sn = a1 + (a1 + d) + (a1 + 2d) + …+ an

Sn = an + (an - d) + (an - 2d) + …+ a1

Jeff Bivin -- LZHS


1 4 7 10 13 16 19

1 + 4 + 7 + 10 + 13 + 16 + 19

a1 = 1

an = 19

n = 7

Jeff Bivin -- LZHS


4 6 8 10 12 14 16 18 20 22 24

4 + 6 + 8 + 10 + 12 + 14 + 16 + 18 + 20 + 22 + 24

a1 = 4

an = 24

n = 11

Jeff Bivin -- LZHS


Find the sum of the integers from 1 to 1001

Find the sum of the integers from 1 to 100

a1 = 1

an = 100

n = 100

Jeff Bivin -- LZHS


Find the sum of the multiples of 3 between 9 and 1344

Find the sum of the multiples of 3 between 9 and 1344

Sn = 9 + 12 + 15 + . . . + 1344

a1 = 9

an = 1344

d = 3

Jeff Bivin -- LZHS


Find the sum of the multiples of 7 between 25 and 989

Find the sum of the multiples of 7 between 25 and 989

Sn = 28 + 35 + 42 + . . . + 987

a1 = 28

an = 987

d = 7

Jeff Bivin -- LZHS


Evaluate

Evaluate

Sn = 16 + 19 + 22 + . . . + 82

a1 = 16

an = 82

d = 3

n = 23

Jeff Bivin -- LZHS


Evaluate1

Evaluate

Sn = -29 - 31 - 33 + . . . - 199

a1 = -29

an = -199

d = -2

n = 86

Jeff Bivin -- LZHS


Find the sum of the multiples of 11 that are 4 digits in length

Find the sum of the multiples of 11 that are 4 digits in length

Sn = 10 01+ 1012 + 1023 + ... + 9999

a1 = 1001

an = 9999

d = 11

Jeff Bivin -- LZHS


Review arithmetic

Review -- Arithmetic

Sum of n terms

nth term

Jeff Bivin -- LZHS


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