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Simple Linear Regression 1. the least squares procedure 2. inference for least squares lines

Simple Linear Regression 1. the least squares procedure 2. inference for least squares lines. Chapter 12. Introduction. We will examine the relationship between quantitative variables x and y via a mathematical equation. The motivation for using the technique:

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Simple Linear Regression 1. the least squares procedure 2. inference for least squares lines

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  1. Simple Linear Regression1. the least squares procedure2. inference for least squares lines Chapter 12

  2. Introduction • We will examine the relationship between quantitative variables x and y via a mathematical equation. • The motivation for using the technique: • Forecast the value of a resposne variable (y) from the value of explanatory variables (x1, x2,…xk.). • Analyze the specific relationship between the explanatory variable and the dependent variable.

  3. The Model The model has a deterministic and a probabilistic component House Cost Building a house costs about $75 per square foot. House cost = 25000 + 75(Size) Most lots sell for $25,000 House size

  4. The Model However, house costs vary even among same size houses! Since cost behave unpredictably, we add a random component. House Cost Most lots sell for $25,000 + e House cost = 25000 + 75(Size) House size

  5. The Model • The first order linear model y = response variable x = explanatory variable b0 = y-intercept b1 = slope of the line e = error variable b0 and b1 are unknown populationparameters, therefore are estimated from the data. y Rise b1 = Rise/Run Run b0 x

  6. Estimating the Coefficients • The estimates are determined by • drawing a sample from the population of interest, • calculating sample statistics. • producing a straight line that cuts into the data. y w Question: What should be considered a good line? w w w w w w w w w w w w w w x

  7. The Least Squares (Regression) Line A good line is one that minimizes the sum of squared differences between the points and the line.

  8. Sum of squared differences = (2 -2.5)2 + (4 - 2.5)2 + (1.5 - 2.5)2 + (3.2 - 2.5)2 = 3.99 1 1 The Least Squares (Regression) Line Sum of squared differences = (2 - 1)2 + (4 - 2)2 + (1.5 - 3)2 + (3.2 - 4)2 = 6.89 Let us compare two lines (2,4) 4 The second line is horizontal w (4,3.2) w 3 2.5 2 w (1,2) (3,1.5) w The smaller the sum of squared differences the better the fit of the line to the data. 2 3 4

  9. The Estimated Coefficients To calculate the estimates of the slope and intercept of the least squares line , use the formulas: The least squares prediction equation that estimates the mean value of y for a particular value of x is:

  10. Example: The Simple Linear Regression Line • A car dealer wants to find the relationship between the odometer reading and the selling price of used cars. • A random sample of 100 cars is selected, and the data recorded. • Find the regression line. Independent variable x Dependent variable y

  11. The Simple Linear Regression Line • Solution • Solving by hand: Calculate a number of statistics where n = 100.

  12. The Simple Linear Regression Line • Solution – continued • Using the computer 1. Scatterplot 2. Trend function 3. Data tab > Data Analysis > Regression

  13. The Simple Linear Regression Line

  14. Interpreting the Linear Regression -Equation 17248.73 No data 0 The intercept is b0 = $17248.73. This is the slope of the line. For each additional mile on the odometer, the price decreases by an average of $0.0669 Do not interpret the intercept as the “Price of cars that have not been driven”

  15. Error Variable: Required Conditions • The error e is a critical part of the regression model. • Four requirements involving the distribution of e must be satisfied. • The probability distribution of e is normal. • The mean of e is zero: E(e) = 0. • The standard deviation of e is sefor all values of x. • The set of errors associated with different values of y are all independent.

  16. E(y|x3) b0 + b1x3 E(y|x2) b0 + b1x2 E(y|x1) b0 + b1x1 The Normality of e The standard deviation remains constant, m3 m2 but the mean value changes with x m1 From the first three assumptions we have: y is normally distributed with mean E(y) = b0 + b1x, and a constant standard deviation se x1 x2 x3

  17. Assessing the Model • The least squares method will produces a regression line whether or not there is a linear relationship between x and y. • Consequently, it is important to assess how well the linear model fits the data. • Several methods are used to assess the model. All are based on the sum of squares for errors, SSE.

  18. A shortcut formula Sum of Squares for Errors • This is the sum of differences between the points and the regression line. • It can serve as a measure of how well the line fits the data. SSE is defined by

  19. Standard Error of Estimate • The mean error is equal to zero. • If se is small the errors tend to be close to zero (close to the mean error). Then, the model fits the data well. • Therefore, we can, use se as a measure of the suitability of using a linear model. • An estimator of se is given by se

  20. It is hard to assess the model based on seeven when compared with the mean value of y. Standard Error of Estimate,Example • Example: • Calculate the standard error of estimate for the previous example and describe what it tells you about the model fit. • Solution

  21. q q q q q q q q q q q q q q q q q q q q q q q q q q q q q q q q q q q q q q q q q q q q q q q q q q q q q q q q q q q q q q q q q q q q q q q q q q q q q q q q q q q q q q q q q q q q q q q q q q q q q q q q q q q q q q Testing the slope • When no linear relationship exists between two variables, the regression line should be horizontal. q q Linear relationship. Linear relationship. Linear relationship. Linear relationship. No linear relationship. Different inputs (x) yield the same output (y). Different inputs (x) yield different outputs (y). The slope is not equal to zero The slope is equal to zero

  22. The standard error of b1. Testing the Slope • We can draw inference about b1 from b1 by testing H0: b1 = 0 H1: b1 = 0 (or < 0,or > 0) • The test statistic is • If the error variable is normally distributed, the statistic is Student t distribution with d.f. = n-2. where

  23. Testing the Slope,Example • Example • Test to determine whether there is enough evidence to infer that there is a linear relationship between the car auction price and the odometer reading for all three-year-old Tauruses in the previous example . Use a = 5%.

  24. Testing the Slope,Example • Solving by hand • To compute “t” we need the values of b1 and sb1. • The rejection region is t > t.025 or t < -t.025 with n = n-2 = 98, t.025 = 1.9845

  25. Testing the Slope (Example) • Using the computer There is overwhelming evidence to infer that the odometer reading affects the auction selling price.

  26. Coefficient of determination Reduction in prediction error when use x: TSS-SSE = SSR

  27. Explained in part by Remains, in part, unexplained Coefficient of determination Reduction in prediction error when use x: TSS-SSE = SSR or TSS = SSR + SSE The regression model SSR Overall variability in y TSS The error SSE

  28. y Coefficient of determination: graphically y2 Two data points (x1,y1) and (x2,y2) of a certain sample are shown. Variation in y = SSR + SSE (TSS) y1 x1 x2 + Unexplained variation (error) Total variation in y = Variation explained by the regression line

  29. Coefficient of determination • R2 (=r2 ) measures the proportion of the variation in y that is explained by the variation in x. • r2 takes on any value between zero and one (-1r 1). • r2 = 1: Perfect match between the line and the data points. • r2 = 0: There are no linear relationship between x and y.

  30. Coefficient of determination,Example • Example • Find the coefficient of determination for the used car price –odometer example.what does this statistic tell you about the model? • Solution • Solving by hand;

  31. Coefficient of determination • Using the computerFrom the regression output we have 64.8% of the variation in the auction selling price is explained by the variation in odometer reading. The rest (35.2%) remains unexplained by this model.

  32. Using the Regression Equation • Before using the regression model, we need to assess how well it fits the data. • If we are satisfied with how well the model fits the data, we can use it to predict the values of y. • To make a prediction we use • Point prediction, and • Interval prediction

  33. A point prediction Point Prediction • Example • Predict the selling price of a three-year-old Taurus with 40,000 miles on the odometer. • It is predicted that a 40,000 miles car would sell for $14,574. • How close is this prediction to the real price?

  34. The prediction interval Interval Estimates • Two intervals can be used to discover how closely the predicted value will match the true value of y. • Prediction interval – predicts y for a given value of x, • Confidence interval – estimates the average y for a given x. • The confidence interval

  35. Interval Estimates,Example • Example - continued • Provide an interval estimate for the bidding price on a Ford Taurus with 40,000 miles on the odometer. • Two types of predictions are required: • A prediction for a specific car • An estimate for the average price per car

  36. Interval Estimates,Example • Solution • A prediction interval provides the price estimate for a single car: t.025,98

  37. Interval Estimates,Example • Solution – continued • A confidence interval provides the estimate of the mean price per car for a Ford Taurus with 40,000 miles reading on the odometer. • The confidence interval (95%) =

  38. The effect of the given x on the length of the interval • As xmoves away from x the interval becomes longer. That is, the shortest interval is found at x.

  39. The effect of the given x on the length of the interval • As xmoves away from x the interval becomes longer. That is, the shortest interval is found at x.

  40. The effect of the given x on the length of the interval • As xmoves away from x the interval becomes longer. That is, the shortest interval is found at x.

  41. Regression Diagnostics - I • The three conditions required for the validity of the regression analysis are: • the error variable is normally distributed. • the error variance is constant for all values of x. • The errors are independent of each other. • How can we diagnose violations of these conditions?

  42. Residual Analysis • Examining the residuals (or standardized residuals), help detect violations of the required conditions. • Example – continued: • Nonnormality. • Use Excel to obtain the standardized residual histogram. • Examine the histogram and look for a bell shaped. diagram with a mean close to zero.

  43. Standardized residual ‘i’ = Residual ‘i’ Standard deviation Residual Analysis A Partial list of Standard residuals For each residual we calculate the standard deviation as follows:

  44. Residual Analysis It seems the residual are normally distributed with mean zero

  45. ^ y + + + + + + + + + + + + + + + + + + + + + + + ^ The spread increases with y Heteroscedasticity • When the requirement of a constant variance is violated we have a condition of heteroscedasticity. • Diagnose heteroscedasticity by plotting the residual against the predicted y. Residual + + + + + + + + + + + + + ^ + + + y + + + + + + + +

  46. Homoscedasticity • When the requirement of a constant variance is not violated we have a condition of homoscedasticity. • Example - continued

  47. Non Independence of Error Variables • A time series is constituted if data were collected over time. • Examining the residuals over time, no pattern should be observed if the errors are independent. • When a pattern is detected, the errors are said to be autocorrelated. • Autocorrelation can be detected by graphing the residuals against time.

  48. Non Independence of Error Variables Patterns in the appearance of the residuals over time indicates that autocorrelation exists. Residual Residual + + + + + + + + + + + + + + 0 0 + Time Time + + + + + + + + + + + + + Note the runs of positive residuals, replaced by runs of negative residuals Note the oscillating behavior of the residuals around zero.

  49. Outliers • An outlier is an observation that is unusually small or large. • Several possibilities need to be investigated when an outlier is observed: • There was an error in recording the value. • The point does not belong in the sample. • The observation is valid. • Identify outliers from the scatter diagram. • It is customaryto suspect an observation is an outlier if its |standard residual| > 2

  50. + + + + + + + + + + + An influential observation An outlier + + … but, some outliers may be very influential + + + + + + + + + + + + + + The outlier causes a shift in the regression line

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