Areas volumes of similar solids 10 4 11 7
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WU: TEI/SOL Questions checkpoint G.10. *hw/hw log/Storybook- “Similar Solids”. Areas & Volumes of similar Solids (10.4/11.7). HW (day 66) : TEI packet & similar solids worksheet Quiz next block pearsonsuccess.net (due Friday).

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Areas volumes of similar solids 10 4 11 7

WU: TEI/SOL Questions checkpoint G.10

*hw/hw log/Storybook- “Similar Solids”

Areas & Volumes of similar Solids (10.4/11.7)

HW (day 66):

TEI packet & similar solids worksheet

Quiz next block

pearsonsuccess.net (due Friday)

Obj: SWBAT find the areas/volumes of similar solids (G.14a)


Areas volumes of similar solids 10 4 11 7

Copy into your SOL Binder (day 71)


Areas volumes of similar solids 10 4 11 7

Copy into your SOL Binder (day 71)


Copy into your sol binder g 14

Copy into your SOL binder (G.)14

Two similar rectangular prisms have side lengths with a ratio of 1:3.

What is the ratio of their surface areas?1:9

What is the ratio of their volumes?1:27


Copy into your sol binder g 141

Copy into your sol binder (G.14)

The dimensions of a triangular prism with a

surface area of 51.46 cm² are multiplied by a scale

factor of 2.5 to create a similar triangular prism.

1) What is the surface area of the new triangular

Prism?

2) What is the relationship between the volume of the original prism and the volume of the new prism?

The new volume is 15.625 times the volume of the original prism.


Copy into your sol binder g 142

Copy into your sol binder (G.14)

Cathy has two cylinders that are the same height, but the volume of the second cylinder is 16 times the volume of the first cylinder. The radius of the second cylinder is –

  • 2 times the radius of the first cylinder.

  • 4 times the radius of the first cylinder.

  • 8 times the radius of the first cylinder.

  • 16 times the radius of the first cylinder.

    The correct answer is D


Copy into your sol binder g 143

Copy into your sol binder (G.14)

Cathy has two cylinders with radii the same length,

but the volume of the second cylinder is 16 times

the volume of the first cylinder. The height of the

second cylinder is –

  • 2 times the height of the first cylinder.

  • 4 times the height of the first cylinder.

  • 8 times the height of the first cylinder.

  • 16 times the height of the first cylinder.

    The answer is B


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