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FISIKA. TERMODINAMIKA. POLITEKNIK UNIVERSITAS ANDALAS. HUKUM TERMODINAMIKA. Energi Dalam ∆U = C v x ∆T Kalor ∆Q = C p x ∆T. Kalor. Energi Dalam. Kapasitas Kalor pada Tekanan Tetap. Kapasitas Kalor pada Volum Tetap. Perubahan Suhu. Perubahan Suhu. HUKUM TERMODINAMIKA. Usaha

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TERMODINAMIKA

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Fisika

FISIKA

TERMODINAMIKA

POLITEKNIK

UNIVERSITAS ANDALAS


Hukum termodinamika

HUKUM TERMODINAMIKA

EnergiDalam

∆U = Cv x ∆T

Kalor

∆Q = Cp x ∆T

Kalor

EnergiDalam

KapasitasKalorpadaTekananTetap

KapasitasKalorpadaVolumTetap

PerubahanSuhu

PerubahanSuhu


Hukum termodinamika1

HUKUM TERMODINAMIKA

Usaha

∆W = P x ∆V

HukumTermodinamika

∆Q = ∆U + ∆W

Usaha

Tekanan

PerubahanVolum


Gas ideal

GAS IDEAL

Pada gas ideal, berlaku :

P  tekanan (atm)

V  volum (liter)

n  mol

R  konstanta (8,314)

T  temperatur (Kelvin)


Gas ideal1

GAS IDEAL

Pada gas ideal monoatomik :

Pada gas ideal diatomik :


Proses dalam termodinamika

PROSES DALAM TERMODINAMIKA

  • ProsesIsokhorik

     Volumtetap

  • ProsesIsobarik

     Tekanantetap

  • ProsesIsotermik

     Temperaturtetap


Proses isokhorik

PROSES ISOKHORIK

Grafik dan persamaan pada proses isokhorik :

∆W = P . ∆V

∆V = 0

∆W = 0

∆Q = ∆U + ∆W

∆Q = ∆U

∆U = Cv. ∆T

∆U = Cv. (T2-T1)


Proses isobarik

PROSES ISOBARIK

Grafik dan persamaan pada proses isobarik :

∆W = P . ∆V

∆W = P.(V2-V1)

∆Q = Cp.(T2-T1)

∆Q = ∆U + ∆W

∆U = ∆Q – ∆W


Proses isotermik

PROSES ISOTERMIK

Grafik dan persamaan pada proses isotermik :

∆U = 0

∆Q = ∆U + ∆W

∆Q = ∆W


Siklus

siklus

Siklus  gabungan dari beberapa proses

Keterangan :

Proses a  b : Isobarik

Proses b  c : Isokhorik

Proses c  a : Isotermik


Contoh soal

CONTOH SOAL

Suatu gas ideal monotomik sebanyak 1 mol mengalami proses–proses seperti pada grafik berikut :

Tentukan :

Pcdan Ta

Wabca


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