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It is Wednesday. The first homework is due. Place it on the bench in front. Acids and bases of varying strengths. Acids and bases of varying strengths. Strong acid = 100% ionization. Strong acid = 100% donation of acidic proton.

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It is wednesday the first homework is due place it on the bench in front

It is Wednesday.

The first homework is due.

Place it on the bench in front.


It is wednesday the first homework is due place it on the bench in front

Acids and bases of varying strengths.


It is wednesday the first homework is due place it on the bench in front

Acids and bases of varying strengths.

Strong acid = 100% ionization

Strong acid = 100% donation of acidic

proton.


It is wednesday the first homework is due place it on the bench in front

HCl(aq) + H2O(l) H3O+(aq) + Cl-(aq)


It is wednesday the first homework is due place it on the bench in front

HCl(aq) + H2O(l) H3O+(aq) + Cl-(aq)

[H3O+][Cl-]

K =

[HCl]


It is wednesday the first homework is due place it on the bench in front

HCl(aq) + H2O(l) H3O+(aq) + Cl-(aq)

[H3O+][Cl-]

large

K =

=

[HCl]


It is wednesday the first homework is due place it on the bench in front

Generic acid

HA(aq) + H2O(l) H3O+(aq) + A-(aq)


It is wednesday the first homework is due place it on the bench in front

Generic acid

HA(aq) + H2O(l) H3O+(aq) + A-(aq)

[H3O+][A-]

= acidity

constant

= Ka

[HA]


It is wednesday the first homework is due place it on the bench in front

Generic acid

HA(aq) + H2O(l) H3O+(aq) + A-(aq)

[H3O+][A-]

= acidity

constant

= Ka

[HA]

-log10 Ka = pKa


It is wednesday the first homework is due place it on the bench in front

Acid Ka pKa

HI  1011-11

HCl  107  -7

H2SO4  102  -2

CH3COOH 1.8 x 10-5 4.74

Table page 332


It is wednesday the first homework is due place it on the bench in front

Base strength


It is wednesday the first homework is due place it on the bench in front

Base strength

Inversely related to strength of

conjugate acid.


It is wednesday the first homework is due place it on the bench in front

Base strength

Inversely related to strength of

conjugate acid.

H2O(l) + B(aq) HB+(aq) + OH-(aq)

conjugate acid


It is wednesday the first homework is due place it on the bench in front

H2O(l) + B(aq) HB+(aq) + OH-(aq)

[HB+][OH-]

= Kb

= basicity

constant

[B]


It is wednesday the first homework is due place it on the bench in front

[HB+][OH-]

= Kb

= basicity

constant

[B]

[H3O+][B]

= acidity

constant

= Ka

[HB+]

[H3O+][OH-] = Kw


It is wednesday the first homework is due place it on the bench in front

[HB+][OH-]

= Kb

= basicity

constant

[B]

[H3O+][B]

= acidity

constant

= Ka

[HB+]

Conjugate acid

[H3O+][OH-] = Kw

KbKa = Kw


It is wednesday the first homework is due place it on the bench in front

[HB+][OH-]

= Kb

= basicity

constant

[B]

[H3O+][B]

= acidity

constant

= Ka

[HB+]

[H3O+][OH-] = Kw

KbKa = Kw

pKb + pKa = pKw


It is wednesday the first homework is due place it on the bench in front

KbKa = Kw

pKb + pKa = pKw

Expressions can be used for any

conjugate acid-base pair in water.


It is wednesday the first homework is due place it on the bench in front

Indicators :

Usually a weak organic acid that has a

color different from its conjugate base.


It is wednesday the first homework is due place it on the bench in front

Indicators :

Usually a weak organic acid that has a

color different from its conjugate base.

HA + H2O H3O+ + A-


It is wednesday the first homework is due place it on the bench in front

phenolphthalein


It is wednesday the first homework is due place it on the bench in front

Indicators :

Usually a weak organic acid that has a

color different from its conjugate base.

+ H2O H3O+ + A-


It is wednesday the first homework is due place it on the bench in front

phenolphthalein


It is wednesday the first homework is due place it on the bench in front

Equilibria with weak acids

and weak bases.


It is wednesday the first homework is due place it on the bench in front

Equilibria with weak acids

and weak bases.

Weak acid:


It is wednesday the first homework is due place it on the bench in front

Equilibria with weak acids

and weak bases.

Weak acid: Ka < 1


It is wednesday the first homework is due place it on the bench in front

Equilibria with weak acids

and weak bases.

Weak acid: Ka < 1

[H3O+][A-]

Ka =

[HA]


It is wednesday the first homework is due place it on the bench in front

Equilibria with weak acids

and weak bases.

Weak acid: Ka < 1

Ka (H3O+) = 1


It is wednesday the first homework is due place it on the bench in front

Equilibria with weak acids

and weak bases.

Weak acid: Ka < 1

Ka (H3O+) = 1

Why is a weak acid weak?


It is wednesday the first homework is due place it on the bench in front

HCl Ka 107 strong

HF Ka = 6.6 x 10-4 weak


It is wednesday the first homework is due place it on the bench in front

HCl Ka 107 strong

HF Ka = 6.6 x 10-4 weak

HF more ionic than HCl


It is wednesday the first homework is due place it on the bench in front

HCl Ka 107 strong

HF Ka = 6.6 x 10-4 weak

HF more ionic than HCl

Relative Kas show that HF holds

proton more strongly than HCl


It is wednesday the first homework is due place it on the bench in front

HCl Ka 107 strong

HF Ka = 6.6 x 10-4 weak

HF more ionic than HCl

Relative Kas show that HF holds

proton more strongly than HCl

Electrostatic attraction for H+ stronger

for F- than for Cl-.


It is wednesday the first homework is due place it on the bench in front

Organic acids

Ka

CH3COOH 1.8 x 10-5

CH3CH2COOH 1.3 x 10-5

CCl3COOH 2 x 10-1


It is wednesday the first homework is due place it on the bench in front

Organic acids

Ka

CH3COOH 1.8 x 10-5

CH3CH2COOH 1.3 x 10-5

CCl3COOH 2 x 10-1


It is wednesday the first homework is due place it on the bench in front

Ka

CH3COOH 1.8 x 10-5

CH3CH2COOH 1.3 x 10-5

CCl3COOH 2 x 10-1

The more stable the conjugate base,

the stronger the acid.


It is wednesday the first homework is due place it on the bench in front

Ka

CH3COOH 1.8 x 10-5

CH3CH2COOH 1.3 x 10-5

CCl3COOH 2 x 10-1


It is wednesday the first homework is due place it on the bench in front

Ka

CH3COOH 1.8 x 10-5

CH3CH2COOH 1.3 x 10-5

CCl3COOH 2 x 10-1


It is wednesday the first homework is due place it on the bench in front

Ka

CH3COOH 1.8 x 10-5

CH3CH2COOH 1.3 x 10-5

CCl3COOH 2 x 10-1


It is wednesday the first homework is due place it on the bench in front

Ka

CH3COOH 1.8 x 10-5

CH3CH2COOH 1.3 x 10-5

CCl3COOH 2 x 10-1


It is wednesday the first homework is due place it on the bench in front

Ka

CH3COOH 1.8 x 10-5

CH3CH2COOH 1.3 x 10-5

CCl3COOH 2 x 10-1


It is wednesday the first homework is due place it on the bench in front

Equilibria with weak acids

and weak bases.

HA(aq) + H2O(l) H3O+(aq) + A-(aq)

[H3O+][A-]

= Ka

[HA]


It is wednesday the first homework is due place it on the bench in front

HA(aq) + H2O(l) H3O+(aq) + A-(aq)

[H3O+][A-]

= Ka

[HA]


It is wednesday the first homework is due place it on the bench in front

HA(aq) + H2O(l) H3O+(aq) + A-(aq)

[H3O+][A-]

= Ka

[HA]

CH3COOH(aq) + H2O(l)

H3O+(aq) + CH3COO-(aq)


It is wednesday the first homework is due place it on the bench in front

HA(aq) + H2O(l) H3O+(aq) + A-(aq)

[H3O+][A-]

= Ka

[HA]

CH3COOH(aq) + H2O(l)

H3O+(aq) + CH3COO-(aq)

Ka = 1.8 x 10-5


It is wednesday the first homework is due place it on the bench in front

CH3COOH(aq) + H2O(l)

H3O+(aq) + CH3COO-(aq)

Ka = 1.8 x 10-5

1 mol CH3COOH

1 L water solution


It is wednesday the first homework is due place it on the bench in front

CH3COOH(aq) + H2O(l)

H3O+(aq) + CH3COO-(aq)

Ka = 1.8 x 10-5

1 mol CH3COOH

Calculate pH

1 L water solution


It is wednesday the first homework is due place it on the bench in front

[CH3COOH] [H3O+] [CH3COO-]

[M]

1.0 0 0

initial

change

Eq.


It is wednesday the first homework is due place it on the bench in front

[CH3COOH] [H3O+] [CH3COO-]

[M]

1.0 0 0

initial

change

-y +y +y

Eq.


It is wednesday the first homework is due place it on the bench in front

[CH3COOH] [H3O+] [CH3COO-]

[M]

1.0 0 0

initial

change

-y +y +y

Eq.

1.0 -y y y


It is wednesday the first homework is due place it on the bench in front

[CH3COOH] [H3O+] [CH3COO-]

[M]

1.0 0 0

initial

change

-y +y +y

Eq.

1.0 -y y y

[H3O+][A-]

= Ka

[HA]


It is wednesday the first homework is due place it on the bench in front

[CH3COOH] [H3O+] [CH3COO-]

[M]

1.0 0 0

initial

change

-y +y +y

Eq.

1.0 -y y y

[H3O+][CH3COO-]

[H3O+][A-]

= Ka

[HA]

[CH3COOH]


It is wednesday the first homework is due place it on the bench in front

[CH3COOH] [H3O+] [CH3COO-]

[M]

1.0 0 0

initial

change

-y +y +y

Eq.

1.0 -y y y

[H3O+][CH3COO-]

= 1.8 x 10-5

[CH3COOH]


It is wednesday the first homework is due place it on the bench in front

[CH3COOH] [H3O+] [CH3COO-]

[M]

1.0 0 0

initial

change

-y +y +y

Eq.

1.0 -y y y

(y)(y)

[H3O+][CH3COO-]

=

= 1.8 x 10-5

(1-y)

[CH3COOH]


It is wednesday the first homework is due place it on the bench in front

[CH3COOH] [H3O+] [CH3COO-]

[M]

1.0 0 0

initial

change

-y +y +y

Eq.

1.0 -y y y

(y)(y)

(y2)

=

=

1.8 x 10-5

(1-y)

(1-y)


It is wednesday the first homework is due place it on the bench in front

[CH3COOH] [H3O+] [CH3COO-]

[M]

1.0 0 0

initial

change

-y +y +y

Eq.

1.0 -y y y

(y)(y)

(y2)

=

=

1.8 x 10-5

(1-y)

(1-y)

y << 1


It is wednesday the first homework is due place it on the bench in front

[CH3COOH] [H3O+] [CH3COO-]

[M]

1.0 0 0

initial

change

-y +y +y

Eq.

1.0 -y y y

(y)(y)

(y2)

=

=

1.8 x 10-5

(1-y)

(1-y)

1-y  1

y << 1


It is wednesday the first homework is due place it on the bench in front

[CH3COOH] [H3O+] [CH3COO-]

[M]

1.0 0 0

initial

change

-y +y +y

Eq.

1.0 -y y y

(y)(y)

(y2)

=

=

= y2

1.8 x 10-5

(1-y)

(1-y)

1-y  1

y << 1


It is wednesday the first homework is due place it on the bench in front

[CH3COOH] [H3O+] [CH3COO-]

[M]

1.0 0 0

initial

change

-y +y +y

Eq.

1.0 -y y y

=

1.8 x 10-5

y2

y = 4.24 x 10-3


It is wednesday the first homework is due place it on the bench in front

[CH3COOH] [H3O+] [CH3COO-]

[M]

1.0 0 0

initial

change

-y +y +y

Eq.

1.0 -y y y

=

1.8 x 10-5

y2

y = 4.24 x 10-3

-log10 4.24 x 10-3 =


It is wednesday the first homework is due place it on the bench in front

[CH3COOH] [H3O+] [CH3COO-]

[M]

1.0 0 0

initial

change

-y +y +y

Eq.

1.0 -y y y

=

1.8 x 10-5

y2

y = 4.24 x 10-3

-log10 4.24 x 10-3 = 2.37 = pH


It is wednesday the first homework is due place it on the bench in front

[CH3COOH] [H3O+] [CH3COO-]

[M]

1.0 0 0

initial

change

-y +y +y

Eq.

1.0 -y y y

y = 4.24 x 10-3

What is the fraction of acid ionized?


It is wednesday the first homework is due place it on the bench in front

[CH3COOH] [H3O+] [CH3COO-]

[M]

1.0 0 0

initial

change

-y +y +y

Eq.

1.0 -y y y

y = 4.24 x 10-3

What is the fraction of acid ionized?

[A-]

[HA]


It is wednesday the first homework is due place it on the bench in front

[CH3COOH] [H3O+] [CH3COO-]

[M]

1.0 0 0

initial

change

-y +y +y

Eq.

1.0 -y y y

y = 4.24 x 10-3

What is the fraction of acid ionized?

[A-]

4.24 x 10-3

=

[HA]

1.0


It is wednesday the first homework is due place it on the bench in front

[CH3COOH] [H3O+] [CH3COO-]

[M]

1.0 0 0

initial

change

-y +y +y

Eq.

1.0 -y y y

y = 4.24 x 10-3

What is the percent of acid ionized?

[A-]

4.24 x 10-3

X 100% = 0.42%

=

[HA]

1.0


It is wednesday the first homework is due place it on the bench in front

[CH3COOH] [H3O+] [CH3COO-]

[M]

0.000100 0

initial

change

-y +y +y

Eq.

0.00010 -y y y

Calculate % ionization for 0.00010 M


It is wednesday the first homework is due place it on the bench in front

[CH3COOH] [H3O+] [CH3COO-]

[M]

0.000100 0

initial

change

-y +y +y

Eq.

0.00010 -y y y

(y2)

(y)(y)

=

=

1.8 x 10-5

(0.0001-y)

(0.0001-y)

[A-]

[HA]


It is wednesday the first homework is due place it on the bench in front

[CH3COOH] [H3O+] [CH3COO-]

[M]

0.000100 0

initial

change

-y +y +y

Eq.

0.00010 -y y y

(y2)

(y)(y)

=

=

1.8 x 10-5

(0.0001)

(0.0001)

[A-]

[HA]


It is wednesday the first homework is due place it on the bench in front

[CH3COOH] [H3O+] [CH3COO-]

[M]

0.000100 0

initial

change

-y +y +y

Eq.

0.00010 -y y y

(y2)

(y)(y)

=

=

1.8 x 10-5

(0.0001)

(0.0001)

[A-]

y2 = 1.8 x 10-9

[HA]


It is wednesday the first homework is due place it on the bench in front

[CH3COOH] [H3O+] [CH3COO-]

[M]

0.000100 0

initial

change

-y +y +y

Eq.

0.00010 -y y y

(y2)

(y)(y)

=

=

1.8 x 10-5

(0.0001)

(0.0001)

[A-]

y2 = 1.8 x 10-9

[HA]

y = 4.2 x 10-5


It is wednesday the first homework is due place it on the bench in front

[CH3COOH] [H3O+] [CH3COO-]

[M]

0.000100 0

initial

change

-y +y +y

Eq.

0.00010 -y y y

(y2)

(y)(y)

=

=

1.8 x 10-5

(0.0001)

(0.0001)

[A-]

4.2 x 10-5

y = 4.2 x 10-5

=

1 x 10-4

42%

[HA]


It is wednesday the first homework is due place it on the bench in front

1 x 10-4 and 4.2 x 10-5

do not differ enough to

ignore y.


It is wednesday the first homework is due place it on the bench in front

[CH3COOH] [H3O+] [CH3COO-]

[M]

0.000100 0

initial

change

-y +y +y

Eq.

0.00010 -y y y

(y2)

(y)(y)

=

=

1.8 x 10-5

(0.0001-y)

(0.0001-y)

34%

Full solution: pg 342


It is wednesday the first homework is due place it on the bench in front

1.0 M CH3COOH 0.42% ionized

0.0001 M CH3COOH 34% ionized


It is wednesday the first homework is due place it on the bench in front

1.0 M CH3COOH 0.42% ionized

0.0001 M CH3COOH 34% ionized

[A-]

=

[HA]


It is wednesday the first homework is due place it on the bench in front

1.0 M CH3COOH 0.42% ionized

[A-] = 4.2 x 10-3 M

0.0001 M CH3COOH 34% ionized

[A-] = 3.4 x 10-5 M

[A-]

=

[HA]


It is wednesday the first homework is due place it on the bench in front

1.0 M CH3COOH 0.42% ionized

[A-] = 4.2 x 10-3 M

0.0001 M CH3COOH 34% ionized

[A-] = 3.4 x 10-5 M

[A-]

[A-]  10-2

=

[HA]

[HA]  10-4


It is wednesday the first homework is due place it on the bench in front

Problem 29:

Calculate pH of 0.35 M solution of propionic

acid.


It is wednesday the first homework is due place it on the bench in front

Problem 29:

Calculate pH of 0.35 M solution of propionic

acid.

Ka = 1.3 x 10-5

Table 8-2


It is wednesday the first homework is due place it on the bench in front

Problem 29:

Calculate pH of 0.35 M solution of propionic

acid.

Ka = 1.3 x 10-5

Table 8-2

HA(aq) + H2O(l) H3O+(aq) + A-(aq)


It is wednesday the first homework is due place it on the bench in front

Problem 29:

Calculate pH of 0.35 M solution of propionic

acid.

Ka = 1.3 x 10-5

Table 8-2

HA(aq) + H2O(l) H3O+(aq) + A-(aq)

[HA] = 0.35 M


It is wednesday the first homework is due place it on the bench in front

Calculate pH of 0.35 M solution of propionic

acid.

Ka = 1.3 x 10-5

Table 8-2

HA(aq) + H2O(l) H3O+(aq) + A-(aq)

[HA] = 0.35 M

[H3O+][A-]

= Ka

[HA]


It is wednesday the first homework is due place it on the bench in front

Calculate pH of 0.35 M solution of propionic

acid.

Ka = 1.3 x 10-5

Table 8-2

HA(aq) + H2O(l) H3O+(aq) + A-(aq)

[HA] = 0.35 M

[H3O+][A-]

(x2)

= Ka

=

[HA]

[HA]


It is wednesday the first homework is due place it on the bench in front

Calculate pH of 0.35 M solution of propionic

acid.

Ka = 1.3 x 10-5

Table 8-2

HA(aq) + H2O(l) H3O+(aq) + A-(aq)

[HA] = 0.35 M

x2 = [HA] Ka


It is wednesday the first homework is due place it on the bench in front

Calculate pH of 0.35 M solution of propionic

acid.

Ka = 1.3 x 10-5

Table 8-2

HA(aq) + H2O(l) H3O+(aq) + A-(aq)

[HA] = 0.35 M

x2 = [HA] Ka

= 0.35 x 1.3 x 10-5

=


It is wednesday the first homework is due place it on the bench in front

Calculate pH of 0.35 M solution of propionic

acid.

Ka = 1.3 x 10-5

Table 8-2

HA(aq) + H2O(l) H3O+(aq) + A-(aq)

[HA] = 0.35 M

x2 = [HA] Ka

= 0.35 x 1.3 x 10-5

=

4.55 x 10-4


It is wednesday the first homework is due place it on the bench in front

Calculate pH of 0.35 M solution of propionic

acid.

Ka = 1.3 x 10-5

Table 8-2

HA(aq) + H2O(l) H3O+(aq) + A-(aq)

x2 = [HA] Ka

= 0.35 x 1.3 x 10-5

=

4.55 x 10-4

4.55 x 10-4

x =


It is wednesday the first homework is due place it on the bench in front

Calculate pH of 0.35 M solution of propionic

acid.

Ka = 1.3 x 10-5

Table 8-2

HA(aq) + H2O(l) H3O+(aq) + A-(aq)

x2 = [HA] Ka

= 0.35 x 1.3 x 10-5

=

4.55 x 10-4

= 2.13 x 10-3

4.55 x 10-4

x =


It is wednesday the first homework is due place it on the bench in front

Calculate pH of 0.35 M solution of propionic

acid.

Ka = 1.3 x 10-5

Table 8-2

HA(aq) + H2O(l) H3O+(aq) + A-(aq)

x2 = [HA] Ka

= 0.35 x 1.3 x 10-5

=

4.55 x 10-4

= 2.13 x 10-3

4.55 x 10-4

x =

-log10 2.13 x 10-3

=


It is wednesday the first homework is due place it on the bench in front

Calculate pH of 0.35 M solution of propionic

acid.

Ka = 1.3 x 10-5

Table 8-2

HA(aq) + H2O(l) H3O+(aq) + A-(aq)

x2 = [HA] Ka

= 0.35 x 1.3 x 10-5

=

4.55 x 10-4

= 2.13 x 10-3

4.55 x 10-4

x =

-log10 2.13 x 10-3

= 2.67


It is wednesday the first homework is due place it on the bench in front

Equilibria involving weak bases


It is wednesday the first homework is due place it on the bench in front

Equilibria involving weak bases

H2O(l) + B(aq) OH-(aq) + HB+(aq)


It is wednesday the first homework is due place it on the bench in front

Equilibria involving weak bases

H2O(l) + B(aq) OH-(aq) + HB+(aq)

Acid1 base2 base1 acid2


It is wednesday the first homework is due place it on the bench in front

Equilibria involving weak bases

H2O(l) + B(aq) OH-(aq) + HB+(aq)

Acid1 base2 base1 acid2

[OH-][HB+]

= Kb

[B]


It is wednesday the first homework is due place it on the bench in front

Equilibria involving weak bases

H2O(l) + B(aq) OH-(aq) + HB+(aq)

Acid1 base2 base1 acid2

[OH-][HB+]

= Kb

[B]

Weak base: Kb < 1


It is wednesday the first homework is due place it on the bench in front

Equilibria involving weak bases

H2O(l) + NH3(aq) OH-(aq) + NH4+(aq)

Acid1 base2 base1 acid2

Kb = ?


It is wednesday the first homework is due place it on the bench in front

Equilibria involving weak bases

H2O(l) + NH3(aq) OH-(aq) + NH4+(aq)

Acid1 base2 base1 acid2

Kb = ?

KaKb = Kw


It is wednesday the first homework is due place it on the bench in front

Equilibria involving weak bases

H2O(l) + NH3(aq) OH-(aq) + NH4+(aq)

Acid1 base2 base1 acid2

Kw

Kb =

Ka


It is wednesday the first homework is due place it on the bench in front

Equilibria involving weak bases

H2O(l) + NH3(aq) OH-(aq) + NH4+(aq)

Acid1 base2 base1 acid2

Kw

Kb =

Ka


It is wednesday the first homework is due place it on the bench in front

Equilibria involving weak bases

H2O(l) + NH3(aq) OH-(aq) + NH4+(aq)

Acid1 base2 base1 acid2

Kw

Kb =

Ka

Table page 332: Ka = 5.6 x 10-10


It is wednesday the first homework is due place it on the bench in front

Equilibria involving weak bases

H2O(l) + NH3(aq) OH-(aq) + NH4+(aq)

Acid1 base2 base1 acid2

1 x 10-14

Kw

=

Kb =

5.6 x 10-10

Ka


It is wednesday the first homework is due place it on the bench in front

Equilibria involving weak bases

H2O(l) + NH3(aq) OH-(aq) + NH4+(aq)

Acid1 base2 base1 acid2

1 x 10-14

Kw

=

= 1.8 x 10-5

Kb =

5.6 x 10-10

Ka


It is wednesday the first homework is due place it on the bench in front

Hydrolysis


It is wednesday the first homework is due place it on the bench in front

Hydrolysis

The reaction of water with an ion

resulting in a change in the [H3O+]-

[OH-] balance.


It is wednesday the first homework is due place it on the bench in front

Hydrolysis

The reaction of water with an ion

resulting in a change in the [H3O+]-

[OH-] balance.

Hydrolysis of anions raises pH.


It is wednesday the first homework is due place it on the bench in front

Hydrolysis

The reaction of water with an ion

resulting in a change in the [H3O+]-

[OH-] balance.

Hydrolysis of anions raises pH.

Hydrolysis of cations lowers pH.


It is wednesday the first homework is due place it on the bench in front

Hydrolysis

H2O(l) + F-(aq) HF(aq) + OH-(aq)


It is wednesday the first homework is due place it on the bench in front

Hydrolysis

H2O(l) + F-(aq) HF(aq) + OH-(aq)

Ka (HF) = 6.6 x 10-4


It is wednesday the first homework is due place it on the bench in front

Hydrolysis

H2O(l) + F-(aq) HF(aq) + OH-(aq)

Ka (HF) = 6.6 x 10-4

[HF][OH-]

Kb =

[F-]


It is wednesday the first homework is due place it on the bench in front

Hydrolysis

H2O(l) + F-(aq) HF(aq) + OH-(aq)

Ka (HF) = 6.6 x 10-4

[HF][OH-]

Kb =

[F-]

pH 0.095 M NaF


It is wednesday the first homework is due place it on the bench in front

Hydrolysis

H2O(l) + F-(aq) HF(aq) + OH-(aq)

Ka (HF) = 6.6 x 10-4

Kw

[HF][OH-]

=

Kb =

Ka

[F-]

pH 0.095 M NaF


It is wednesday the first homework is due place it on the bench in front

Hydrolysis

H2O(l) + F-(aq) HF(aq) + OH-(aq)

Ka (HF) = 6.6 x 10-4

[F-]Kw

Kw

[HF][OH-]

=

=

[OH-]2

Ka

[F-]

Ka

pH 0.095 M NaF


It is wednesday the first homework is due place it on the bench in front

Hydrolysis

H2O(l) + F-(aq) HF(aq) + OH-(aq)

Ka (HF) = 6.6 x 10-4

(0.095)(1 x 10-14)

[F-]Kw

=

=

[OH-]2

(6.6 x 10-4)

Ka

pH 0.095 M NaF


It is wednesday the first homework is due place it on the bench in front

Hydrolysis

H2O(l) + F-(aq) HF(aq) + OH-(aq)

(0.095)(1 x 10-14)

[F-]Kw

=

=

=

[OH-]2

(6.6 x 10-4)

Ka


It is wednesday the first homework is due place it on the bench in front

Hydrolysis

H2O(l) + F-(aq) HF(aq) + OH-(aq)

(0.095)(1 x 10-14)

[F-]Kw

=

=

=

[OH-]2

(6.6 x 10-4)

Ka

1.44 x 10-12

=

[OH-]2


It is wednesday the first homework is due place it on the bench in front

Hydrolysis

H2O(l) + F-(aq) HF(aq) + OH-(aq)

(0.095)(1 x 10-14)

[F-]Kw

=

=

=

[OH-]2

(6.6 x 10-4)

Ka

1.44 x 10-12

=

[OH-] = 1.2 x 10-6

[OH-]2


It is wednesday the first homework is due place it on the bench in front

Hydrolysis

H2O(l) + F-(aq) HF(aq) + OH-(aq)

[OH-] = 1.2 x 10-6

1 x 10-14

=

[H3O+] =

1.2 x 10-6


It is wednesday the first homework is due place it on the bench in front

Hydrolysis

H2O(l) + F-(aq) HF(aq) + OH-(aq)

[OH-] = 1.2 x 10-6

1 x 10-14

8.34 x 10-9

=

[H3O+] =

1.2 x 10-6


It is wednesday the first homework is due place it on the bench in front

Hydrolysis

H2O(l) + F-(aq) HF(aq) + OH-(aq)

[OH-] = 1.2 x 10-6

1 x 10-14

8.34 x 10-9

=

[H3O+] =

1.2 x 10-6

-log10

(8.34 x 10-9) = 8.08


It is wednesday the first homework is due place it on the bench in front

Hydrolysis

H2O(l) + F-(aq) HF(aq) + OH-(aq)

pH = 8.08


It is wednesday the first homework is due place it on the bench in front

It is Wednesday.

The first homework is due.

Place it on the bench in front.


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