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# Drill: Calculate the pH of 0.10 M H 2 Z in 0.50 M KHZ. K a1 = 2.0 x 10 -5 K a2 = 5.0 x 10 -9 - PowerPoint PPT Presentation

Drill: Calculate the pH of 0.10 M H 2 Z in 0.50 M KHZ. K a1 = 2.0 x 10 -5 K a2 = 5.0 x 10 -9. Salt or Hydrolysis Reactions. Hydrolysis. Any reaction in which water is decomposed with all or part of its decomposition portions combining with the products. Hydrolysis.

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Drill: Calculate the pH of 0.10 M H 2 Z in 0.50 M KHZ. K a1 = 2.0 x 10 -5 K a2 = 5.0 x 10 -9

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### Hydrolysis

Any reaction in which water is decomposed with all or part of its decomposition portions combining with the products

Hydrolysis

Water is added to decompose something

Hydrolysis

MX + HOH

HX + MOH

### Salts

• Ionic compounds that dissolve ~ 100 % in water

Salts of Acids

• Salts of acids are negative

• (A-)

Salts of Bases

• Salts of bases are Positive

• (M+ or B+)

Salt Solutions

• When salts dissolve, their ions can recombine with water

### Salt Solutions

• The salts of weak acids can recombine with water producing basic solutions

Salt Solutions

• The salts of weak bases can recombine with water producing acidic solutions

Salt Solutions

• A- + H2O HA + OH-

• B+ + H2O H+ + BOH

### Drill: Calculate the salt/acid ratio of a solution of benzoic acid & sodium benzoate at a pH of 5.00.KaHBz = 6.4 x 10-5

Salt or Hydrolysis Problems

Salt Problem

• Calculate the pH of a 0.20 M solution of NaBz

• Ka HBz = 6.4 x 10-5

Drill: Calculate the pH of a solution of 0.10 M NH3 in 0.20 NH4Cl.Kb NH3 = 1.8 x 10-5

Salt or Hydrolysis Problems

Salt Problem

• Calculate the pH of a 0.20 M solution of KNO2

• Ka HNO2 = 7.1 x 10-4

Salt Problem

• Calculate the pH of a 0.10 M solution of R-NH3Cl

• Kb R-NH2 = 2.5 x 10-5

• Calculate the pH of a 0.18 M solution of KC2H3O2

• Ka = 1.8 x 10-5

### Drill: Calculate the salt to acid ratio required to make a buffer solution with a pH of 4.495 using benzoic acid.KaHBz = 6.4 x 10-5

Salt Applications

• Salts of strong acids & weak bases make acidic solutions

Salt Applications

• Salts of strong bases & weak acids make basic solutions

Salt Applications

• Salts of strong acids & strong bases make neutral solutions

Predict Relative pH

• NaAcMnCl2

• KNO3NH4Br

• KHSO4NH4Ac

Predict Relative pH

• KAcNaCl

• KClO2NH4Cl

• K2SO4NaI

Anhydrides

• Compounds without water; that when added to water, form other compounds

Acid Anhydrides

• Non-metal oxides that form acids when added to water

Basic Anhydrides

• Metal oxides that form bases when added to water

Predict Relative pH

• Na2OSO2

• NO2CO2

• CaOAl2O3

• Calculate the pH of a 0.16 M solution of KC7H5O2

• Ka = 6.4 x 10-5

• Calculate the pH of a solution of 0.0030 M KQ.

• KaHQ = 3.0 x 10-5

### Drill: Calculate the pH of a 0.72 M NH4NO3 solution.KbNH3 = 1.8 x 10-5

Are there any questions on previous material?

### A/B eq, Buffer & Salt Hydrolysis Problem

Calculate [H3PO4], [H2PO4-1], [HPO4-2], [PO4-3], [K+], [H+], & pH of 1.0 M KH2PO4 in 0.50 M K2HPO4. Ka1 = 7.5 x 10-3Ka2 = 6.2 x 10-8Ka3 = 4.2 x 10-13

You need to make a buffer solution with its greatest buffering capacity at pH ~ 5.4. In general terms, describe what acid or base you would chose, & how you would make the buffer.

11.2 g of KOH was added to 2.0 L of 0.075 M H2CO3. Calculate the molarity of all ions present in the solution.Ka1 = 4.4 x 10-7Ka2 = 4.8 x 10-11

Drill: Calculate the pH of

0.10 M HF. Ka HF = 6.5 x 10-4

### Expect a straight acid/base problem like the drill

Calculate the pH of 0.10 M HF in 0.20 M KF. Ka HF = 6.5 x 10-4

Calculate the pH of 0.10 M KF. Ka HF = 6.5 x 10-4

Predict Relative pH

K2OMgO

ClO2(NH4)2O

SO3N2O3

Predict Relative pH

• KAcNaCl

• KClO2NH4Cl

• K2SO4NaI

Calculate the pH of 5.0 M KCN. KaHCN= 5.0 x 10-10

Calculate pH of:

0.20 M MOHin

0.50 M MCl

Kb = 5.0 x 10-5

Calculate pH of:

0.20 M MCl

Kb = 5.0 x 10-5

### Drill: Calculate the pH of0.20 M KQ. KaHQ = 8.0 x 10-5

Calculate pH of:

• 0.20 M HNO2

• Ka = 2.0 x 10-4

Calculate pH of:

• 3.0 M HZin

• 2.0 M KZ

• Ka HZ = 3.0 x 10-5

Calculate pH of:

• 0.20 M KR

• Ka HR = 2.0 x 10-5

Calculate pH of:

• 2.0 M HQ

• Ka = 2.0 x 10-6

Calculate pH of:

• 0.60 M HZin

• 0.90 M KZ

• Ka HZ = 3.0 x 10-5

Calculate pH of:

• 0.20 M KQ

• Ka HQ = 2.0 x 10-7

1.5 L of 0.25 M Ba(OH)2 was added to 1.0 L of 0.60 M H2SO3. Calculate [H2SO3], [HSO3-], [SO3-2], [H+], [OH-], & pH of the solution.Ka1 = 1.7 x 10-2Ka2 = 6.0 x 10-8

### Review of Acid/Base descriptions and Acid/Base, Buffer, & Salt Equilibria

Arhenius, Bronsted-Lowry, & Lewis Acids & Bases

Strong Acids

Strong Bases

Acid rxns

Base rxns

A/B Equilibrium Constants

KW, KA, KB, & pH

### Calculate pH of:

• 0.025 M HNO3

• 0.020 M KOH

150 mL of 0.10 M KOH was added to 100.0 mL of 0.10 M H2CO3. Calculate [H2CO3], [HCO3-], [CO3-2], [H+], [OH-], & pH of the solution.Ka1 = 4.4 x 10-7Ka2 = 4.7 x 10-11

Calculate [H3A], [H2A-1], [HA-2], [A-3], [K+], [H+],[OH-], & pH of 2.0 M KH2A. Ka1 = 4.0 x 10-3Ka2 = 5.0 x 10-8Ka3 = 2.5 x 10-13