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第 6 章参考习题答案 PowerPoint PPT Presentation


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第 6 章参考习题答案. 6-1 6-2 6-3 6-4 6-5 6-6 6-7 6-8 6-9 6-10 6-11 6-12 6-13 6-14 6-15 6-16 6-17 6-18 6-19 6-20 6-21 6-22 6-23 6-24 6-25 6-26 6-27 6-28 6-29 6-30. 6 - 1 已知载波电压 u c =U C sinω C t ,调制信号如图所示, f C >>1/T Ω 。分别画出 m=0.5 及 m=1 两种情况下所对应的 AM 波波形以及 DSB 波波形。. 题 6—l 图. 解 6-1 ,各波形图如下.

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第 6 章参考习题答案

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6

6-16-26-36-46-5

6-66-76-86-96-10

6-116-126-136-146-15

6-166-176-186-196-20

6-216-226-236-246-25

6-266-276-286-296-30


61 uc=UCsinCtfC>>1/Tm=0.5m=1AMDSB

6l


6-1


62 RL=100u0(t)=4(1-0.5cost)cosct VPavPcP

6-2

AMm=0.5,


X

+

+

X

X

X

63 1AM2 DSB3SSB

6-3


64 u(t)=U costuC=UCcosctc>>,UC>>UVD1VD2gD12

64


6-4


bcDSB

bcc

ccc


65Cb uC=UCcosct, u=Ucost1UCUi=a0+a1u2+a2u2. uo(t) 2UC>>U,uo(t) 1

65


6-5

1


2



66 R(T=13TC, TCT)

6-6

gD,1:1.RR=R1+R2ucRDR1R2uucuc:

66


C


R


67 gDu2RL>>RD(RD=1/gD)u1u2uo

6-7

u2

u2


AMu1u2.

DSBu1u2.

u1u2


68 (a)u=UcostgdUCTC=2/CUC>>U(b)

68


6-8


69 1C=107rad/SCRL=5k,Ee=Ec=10V,Re=5k,uC=156cosCt mV, u=5.63cos104t Vuo(t) 2


6-9

(1)

(2)

DSBDSB26Mv


610 u=cos103t V uC=50cos107tmV1uo(t)2m

610


6-101


uCAMm=0.5.


611 ABCD

611


6-11



612 RC

612

6-12

RCRC


(a)AM

(b)

(c)

(d)


613 uS()RCCgRg

-13

6-13


614us=0.8(1+0.5cost)cosCtV,F=5kHz,fC=465kHz,rD=125.RiKd

6-14

6-14


615 f0=106Hz,R0=20k, ,10k,C1=0.01F,rD=100.1is=0.5cos2106t mA,us(t)uo(t) 2is=0.5(1+0.5cos2103t)cos2106t mA, uo(t).


6-151

2


616 C1=C2=0.01F,R1=1kR2=5kF=1kHzfC=1MHz1ADBD2C22F BD

616


6-16

1

F<fH<fC,


2C22F

fH<<F,BDAM


617 us=Uscos(C+)t,ur=Urcosrt,Ur>>Us

6-17

.Kd

617



cotn00


618 (a)(b)u1u2u3u4C>>

618


6-18


2



619 iC=a0+a2u2+a3u3,u=UScosSt+ULcosLt,UL>>US,(L-S)(2L-S)

6-19


620 aUL=E0gC1E0 2E0/2 3 4-E0/2

6-20

EQ,uS=UScosSt,UL>>US,

620


621 iD=IDSS(1-uGS/VP)2IDSS=3mA,VP=-3V.465kHzQ0=100RL=1kC=600pFn=1/7C1C2C3Rs1UL2gC

621


1



622 NIDSS=4mAVp=-4VUL=1.8V,Re=2k (1gmQgC (2lmVsLI (3

622


6-21


2

3LS2S2LL+S


623

1

2

3


623


6-23

1u1u2


2AMu1u2AM


3u1u2


624 AMDSBSSBu1u2f0B

624

6-24

f0Fmax.

U2>>U1iL=2gDK(2t)u1,


1u1,u2,AMf0=fC,2,B0.7=2Fmax

2u1,u2,DSBSSBDSBf0=fCB0.7=2Fmax.SSBB0.7=Fmax.- Fmin.Fmax,,

f0=fC+0.5( Fmax+ Fmin)

3u1,u2,fH> Fmax.


4u1,u2

5u1,u2,f0=fI=fL-fC2,B0.7=2Fmax.


625 3003000 HZ

625


6-25


626 fI= 500 kHzfL<fsfs =1.501 MHz

6-26

fL=fs-fI=1501-500=1001kHz


p=2,q=132fL-fS=2002-1501=501kHz

p=4,q=373fS-4fL=4503-4004=503kHz

p=5,q=385fL-3fS=5005-4503=502kHz

p=7,q=5125fS-7fL=7505-7007=498kHz

3


627 (1 1090 kHz 1323 kHz (2) 1080 kHz 540 kHz (3 930 kHz 690 kHz 810 kHz()

6-27

(1)

1090 kHz 1323 kHz1323kHzfL=1090+465=1555kHz,pfL-qfJ=fIp=2,q=22fL-2fJ=3110-2646=464fI4


(2)

1080 kHz540 kHzfL=1080+465=1545kHz,p=1,q=2 fL-2fJ=1545-1080=465=fI3

(3)

fS-fJ1=fJ1-fJ2930-810=810-690=120kHZ,433


628 0.5525 MHzfI=455 kHZfLfs6

6-28



629 6.5 MHz7.25 MHz7.5 MHZ 7.5 MHZfI=0.5 MHZfL>fs.

6-29

17.5MHz7.5MHz6.5 MHz7.25 MHz7.5MHz

26.5 MHz

fS=6.5 MHzfL=fS+fI=6.5+0.5=7MHz,fJ=7.5MHzfJ-fL=7.5-7=0.5 MHz = fI,7.5MHz6.5 MHz


37.25 MHz

fS=7.25 MHz,fL=fS+fI=7.25+0.5=7.75MHz, fJ=7.5MHz 2fL-2fJ=15.5-15=0.5 MHz= fI,4


630 fS=20 MHzfJ1=19.6 MHzfJ2=19.2 MHzfI=3 MHz

6-30

fS- fJ1=20-19.6=0.4MHz, fJ1- fJ2=19.6=19.2=0.4MHz,fS- fJ1= fJ1- fJ23


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