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# Motor/Drive Sizing Exercise PowerPoint PPT Presentation

Motor/Drive Sizing Exercise. Siemens Motion Control. Motor/Drive Sizing Exercise. 3 - Axis Conveyor. Calculation of the Travel gear (X-Axis). The Following Data is Given: ¨ Mass to be transportedm= 400 kg ¨ Diameter of drive wheel D= 0.14 m ¨ Max. speedV max = 1.6 m/s

Motor/Drive Sizing Exercise

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### Motor/Drive Sizing Exercise

Siemens Motion Control

### Motor/Drive Sizing Exercise

3 - Axis Conveyor

### Calculation of the Travel gear (X-Axis)

The Following Data is Given:

¨ Mass to be transportedm= 400 kg

¨ Diameter of drive wheel D= 0.14 m

¨ Max. speedV max= 1.6 m/s

¨ Max. acceleration and deceleration a max= 6.4 m/s2

¨ Distance traveleds= 2 m

¨ Cycle time T= 7 s

¨ Mech.. efficiency mech.= 0.9

¨ Specific travelling resistance w f= 0.1

¨ Mech.. accuracys mech.= ±0.1 mm

¨ Overall accuracy requireds tot= ±0.2 mm

### Calculation of the Time Segments (X-Axis)

• Since the travel is symmetrical, we only have to consider the forward movement!

• So the new cycle time is:

Now determine the remaining time values of the curve.

### Calculation of the Maximum Speed (X-Axis)

• Now we must calculate the Maximum speed under load at the drive wheel.

• Due to low rpm, a gearbox should be used to better match the motor speed to the load speed. In this case a gearbox with a transmission ratio of i=10 is chosen, giving a resulting rpm at the motor of:

• Why is a gearbox necessary? Why not just select a motor with a lower rpm?

• A smaller motor can be used - larger motor mean larger motor inertia

• Motor/ Gear box is more economical

### Calculation of the Maximum Torque (X-Axis)

• Now we must calculate the Maximum Resistance Torque of the load at the drive wheel.

• We also need to know the Maximum Acceleration and Deceleration Torque for the Load.

• Maximum Acceleration and Deceleration Torque for a Rotational motion is given by:

• Therefore:

### Calculation of the Maximum Torque (X-Axis) Cont.

• Now we can get the Maximum Torque on the output side of the gear.

• We also need to know the Maximum Acceleration and Deceleration Torque of the gear unit itself.

• The Technical Data of the gear unit is as follows:

• ¨ Gear Ratio i = 10

• ¨ Max, Torque G = 400 Nm

• ¨ Torsional PlayG = 3’

• ¨ Gear Unit Efficiency G.= 0.95

• - Inertia J G.= 0.001 Kgm2

• Therefore:

### Calculation of the Position Accuracy (X-Axis)

• Before we choose a motor, we should determine whether or not the position accuracy required is met.

• For the Gear Unit:

I.e. + 0.0305 mm

• For the Encoder:

With a 2-pole resolver

• Total:

Hence, the required accuracy it complied with.

### Calculation of the Position Accuracy of other Feedback Devices

• What would be the accuracy if a different feedback device had been chosen?

• For a Pulse encoder with 2048 PPR?

• For a Sin/Cos encoder or Absolute value (ERN/EQN)?

### Calculation of the Maximum Torque reflected to the Motor (X-Axis)

• Maximum Torque reflected to the motor is determined by adding all the individual torque values.

• Therefore:

Where:

• Hence, before we can figure out the Complete Torque a motor must be chosen. Since we know some of the torque required, an educated guess must be made in choosing an appropriate motor.

### Calculation of the Maximum Torque reflected to the Motor (X-Axis)

• Choose a Synchronous Servo motor (1FT6) based on the information known and the Dynamic Limit curves.

• The first 1FT6 motor with nn=3000 rpm, which satisfies the condition of the Dynamic Limit curve is 1FT6084-8AF7 with the following characteristics:

• - Pn = 4.6 kW

• - n = 14.7 Nm

• - Max = 65 Nm

• - Jmot = 0.0065 kgm2

• - kTn = 1.34 Nm/A

• - mot = 0.92

• - 0 = 20 Nm

• Explain why this motor was chosen over any other motor.

Mot max

Mot max

### Calculation of the Maximum Torque of the Motor (X-Axis)

• The Acceleration Torque of the motor itself is thus:

• Now the Maximum motor torque can be determined.

• Next a check must be done to ensure that the thermal limits of the motor are not exceeded. This is accomplished by determining the motor torques at every point of the travel curve.

• We already have determined the acceleration torque. 31.03 Nm

### Calculation of the Travel Curve Torques (X-Axis)

• We already have determined the acceleration torque.

• The Torque during constant travel now needs to be calculated.

• Finally the torque during deceleration is required.

### Checking the Validity of the selected Motor (X-Axis)

• To verify it the motor we selected from the Dynamic Curve Profile is valid, the effective(rms) torque and speed must be determined.

• The Effective Torque is calculated as follows:

• By using the Travel Curve, the Effective Speed is calculated as follows:

• By using the S1 Curve for the given motor, a determination can be made whether or not the motor selected is satisfactory.

### Checking the Validity of the selected Motor (X-Axis)

Since the operating point

is well below the S1 Curve,

the motor selected is suitable.

### Selecting the Inverter (X-Axis)

• The Inverter is selected according to the maximum motor current and mean motor current.

• Therefore the Max current is given by:

• The Mean motor current is calculated as follows:

• For overload calculations, the motor current during constant travel is calculated:

### Selecting the Inverter (X-Axis)

• Since the Accelerating and Decelerating times are < 250 ms and the time between is > 750 ms, a check should be made to see if the 300% overload capability of the Compact Plus unit can be utilized.

• From the data calculated select the drive that best fits.

• Drive Selected: 6SE7021-0TP50 with an Iun = 10.2 A

• Thus, checking:

• Since the above criteria are met, a correct selection has been made.

### Determination of DC link Currents (X-Axis)

• The Max DC link current and the mean DC link current must be determined for later rating of the rectifier unit. This is done by first determining all of the motor power levels within the travel curve.

• Maximum power output during acceleration, calculation:

• Power output during constant travel, calculation:

• Maximum power output during deceleration, calculation:

### Determination of DC link Currents (X-Axis)

• Now that we have the Power Characteristic curve, the maximum power can be determined and the Maximum DC Link current can be calculated.

• Maximum DC Link current during acceleration is given by:

• Now we need to determine the Mean value of DC current, but before we can do this we need the Mean Power.

• The Mean Power output during motor operation is given by:

### Determination of DC link Currents (X-Axis)

• Now that we have the Mean Power the mean DC Link currents can be calculated.

• The Mean DC Link current is given by:

• The next step involves determining the Braking Power.

### Determination of Braking Power (X-Axis)

• The Braking Power and the Mean Braking Power are calculated for later sizing of the braking resistor.

• The Maximum Braking Power is given by:

• The Mean Braking Power is obtained from the negative characteristic of the motor output. The calculation is as follows:

### Calculation of the Travel Gear (Y-Axis)

• Since the Y-Axis is the same as the X-Axis, you will now proceed with all of the same calculations for the Y-Axis on your own and present the results.

Ha Ha - Just Kidding!

### Calculation of the Lifting Drive (Z-Axis)

• Since the Z-Axis is slightly different than the X-Axis and Y-Axis, we will now go over the major differences and dispense with the entire calculation.

• What are the differences?

• Travel Distance is represented in Height.

• The entire Travel Curve must be taken into consideration because of the different torque values for Lifting and Lowering even if it is Symmetrical.

• Rotational Force is translated to Linear Force via a Rack and Pinion.

### Calculation of the Torque of the Lifting Drive (Z-Axis)

• Since the Z-Axis is a lifting drive the, the Resistance Torque Calculation is now called the Lifting Torque.

• Since the Z-Axis is a lifting drive the, ALL Torque cases must be evaluated.

• Lifting the load, motor torque during constant travel

• Lowering the load, motor torque during constant travel

• Lifting the load, motor torque during acceleration

• Lifting the load, motor torque during deceleration

• Lowering the load, motor torque during acceleration

• Lowering the load, motor torque during deceleration

### Selection of the Inverter for the Lifting Drive (Z-Axis)

• The same calculations used for the X & Y - Axis are followed here, too, with one major consideration change.

• What is it?

• The acceleration and Deceleration times are > 250ms, so only the 160% overload rating can be applied!

### Selection of the Inverter for the Lifting Drive (Z-Axis)

• Once again, since the Z-Axis is a lifting drive the, ALL Power cases must be evaluated for future determination of DC Link current needed for rectifier selection.

• Lifting the load, Power output during constant travel

• Lowering the load, Power output during constant travel

• Lifting the load, Power output during acceleration

• Lifting the load, Power output during deceleration

• Lowering the load, Power output during acceleration

• Lowering the load, Power output during deceleration

### Selection of the Rectifier Unit for the 3-Axis Conveyer

• Now that all of the Inverters have been chosen, a rectifier needs to be selected.

• Recall that the X and Z -Axis operate simultaneously.

• Also, recall that the Y-Axis is much smaller than any of the other axis’ and, thus, it does not need to be considered in the calculation of the rectifier.

• First calculate the maximum DC Link current as follows:

### Selection of the Rectifier Unit for the 3-Axis Conveyer

• Next, calculate the Mean value of the DC Link current as follows:

• Now base on this calculated information, choose a Rectifier.

• To maintain a uniform design, a Compact Plus Rectifier should be chosen.

• Therefore we should choose:

• 6SE7024 - 1EP85-0AA0 with IDCn = 41 A

### Selection of the Rectifier Unit for the 3-Axis Conveyer

• Confirmation of this choice is given by:

### Selection of the Braking Resistor for the 3-Axis Conveyer

• What components are needed?

• Just the Braking Resistor! Why?

• The Chopper is integrated into the Compact Plus Rectifier!

• What assumptions can be made?

• Since the X & Z-Axis travel simultaneously, both may brake at the same time.

• So, first we need to calculate the maximum Braking Power Level as follows:

### Selection of the Braking Resistor for the 3-Axis Conveyer

• Next, we need to determine the Mean Braking Power as follows:

• Now that all the calculation have been made a suitable resistor needs to be chosen.

• Therefore, we should choose:

• 6SE7018 - 0ES87 - 2DC0, with P20 = 5 kW, & R = 80

### Selection of the Braking Resistor for the 3-Axis Conveyer

• Checking our selection:

• Since the above conditions have been met, our choice is valid.

### Other requirements for the 3-Axis Conveyer

• What other components/options are needed?

• Given:

• Positioning to be carried out non-centrally.

• Need Technology Option, Order # 6SW1700-5AD00-1XX0

• All three motions are synchronized.

• Need SIMOLINK board, Order # 6SX7010-0FJ00

• PROFIBUS communication to PLC.

• Need CBP board, Order # 6SX7010-0FF00

• A Resolver is used.

• Need SBR1/2 board, Order # 6SX7010-0FC00 or 6SX7010-0FC00

### Other requirements for the 3-Axis Conveyer

• What other components/options are needed that are not mentioned?

• Motor Power Cables - assembled.

• Order # 6FX2002-5DA31-???0, ??? = Cable Length

• Feed Back Cables - assembled.

• Order # 6FX2002-2cf01-???0, ??? = Cable Length

• Other Miscellaneous options?

• I/O Expansion Boards

• RFI Filter

• Line Reactor

• Capacitor Module

• OP1S

### Other requirements for the 3-Axis Conveyer Cont.

• Other Miscellaneous options?

• -Z +K80, Safety Off - Special Order with extended Lead Time

• -Z +C91, 24 VDC Power Supply for Rect. - Special Order with extended Lead Time

• There will be some other Option Codes Available, but they all bring extended Lead times with them.

### Ability of Drive to actually do the 3-Axis Conveyer

• Now that everything has been calculated and all the options and accessories have been chosen, can the drive do the application????

• What is the limiting factor?

• The Acceleration and Deceleration times and how they relate to the Drive Process time for the Position Loop.

• Lets Look at the Function Diagram for the Operating Mode MDI [823]

### Ability of Drive to actually do the 3-Axis Conveyer

• Typically the Position Loop should be calculated at least 10 times!

### Ability of Drive to actually do the 3-Axis Conveyer

• This gives you a value of 32 ms for accurate positioning.

• Lets check this value with the Acceleration and Deceleration time required by the application.

• Since the Positioning Time of the Position Loop is less than the required Acceleration and Deceleration time, “WE CAN DO THAT”.

END