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# Do Now 10/2/09 - PowerPoint PPT Presentation

Do Now 10/2/09. Take out HW from last night. Text p.81, #10-21 all, #33-35 all Copy HW in your planner. Text p.74, #12-48 evens Quiz sections 2.1-2.3 Thursday In your journal, find the perimeter of the figure. (Hint: The answer will be a variable expression). 3x. x + 2. x + 2. 5x.

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• Take out HW from last night.

• Text p.81, #10-21 all, #33-35 all

• Copy HW in your planner.

• Text p.74, #12-48 evens

• Quiz sections 2.1-2.3 Thursday

• In your journal, find the perimeter of the figure. (Hint: The answer will be a variable expression).

3x

x + 2

x + 2

5x

• What is the perimeter of the trapezoid?

Perimeter is the

distance around a figure.

3x

Add together each of the sides.

1x + 2

1x + 2

1x + 2 + 3x + 1x + 2 + 5x

(reorder terms)

1x + 3x + 1x + 5x + 2 + 2

(combine like terms)

5x

10x + 4

10) terms: 10x, 7, 3x; like terms: 10x & 3x; coefficients: 10 & 3; constant terms: 7; simplified: 13x +7

11) terms: 4y, 23, -1y, -6; like terms: 4y & -1y; 23 & -6; coefficients: 4 & -1; constant terms: 23 & -6; simplified: 3y + 17

12) terms: -19, -11a, 1a, 16; like terms: -11a & 1a, -19 & 16; coefficients: -11 & 1; constant terms: -19 & 16; simplified: -10a – 3

13) terms: 2b, -8, 4b, -6b; like terms: 2b, 4b, & -6b; coefficients: 2, 4, & -6; constant terms: -8; simplified: -8

14) terms: 9, 1n, -1, -7n; like terms: 1n & -7n, 9 & -1; coefficients: 1 & -7; constant terms: 9 & -1; simplified: -6n +8

15) terms: 8p, -5p, 5, -1p, -2; like terms: 8p, -5p & -1p; 5 & -2; coefficients: 8, -5, & -1; constant terms: 5 & -2; simplified: 2p + 3

Homework Text p.81, #10-21 all, #33-35 all

Homework coefficients: 10 & 3; constant terms: 7; simplified: 13x +7 Text p.81, #10-21 all, #33-35 all

• 16) 6x

• 17) 7a

• 18) -8b

• 19) 6x

• 20) 7c²

• 21) 21y

• 33) x + x + 5 + 2x + 1; 4x + 6

• 34) a + 2a + (10 – 3a); 10

• 35) 7y – 5 + 2y + 7y – 5 + 2y; 18y – 10

Objective coefficients: 10 & 3; constant terms: 7; simplified: 13x +7

• SWBAT apply the distributive property to solve problems

Evaluate. coefficients: 10 & 3; constant terms: 7; simplified: 13x +7

5(11 + 2)

5(11) + 5(2)

65

This means to multiply

65

Section 2.2, “The Distributive Property” coefficients: 10 & 3; constant terms: 7; simplified: 13x +7

DISTRIBUTIVE PROPERTY-

a(b + c) = ab + ac

a(b - c) = ab - ac

Both of these expressions are

EQUIVALENT EXPRESSIONS-

meaning they have the same value.

The Distributive Property coefficients: 10 & 3; constant terms: 7; simplified: 13x +7Order doesn’t matter…

DISTRIBUTIVE PROPERTY-

(b + c)a = ba + ca

(b - c)a = ba - ca

Both of these expressions are

EQUIVALENT EXPRESSIONS-

meaning they have the same value.

Distributive Property coefficients: 10 & 3; constant terms: 7; simplified: 13x +7

Multiply across Parentheses

3(2 + 4) = 3(2) + 3(4)

3(6) = 6 + 12

18 = 18

Think of it as looking to DISTRIBUTE something

3(x + 7) coefficients: 10 & 3; constant terms: 7; simplified: 13x +7

-2(a + b)

(8 – 7)(-9)

10(x + 2y - z)

A). 3(x) + 3(7)

3x + 21

Evaluate

B). -2(a) + -2(b)

-2a + (-2b) or -2a – 2b

C). (8)(-9) + (-7)(-9)

-72 + 63 = -9

D). 10(x) + 10(2y) - 10(z)

10x + 20y - 10z

Find the Area of the Figures coefficients: 10 & 3; constant terms: 7; simplified: 13x +7

8 – 12w

8 – 3y

9

12

Area = length x width

Area = (½)bh

Area = (9)(8 – 12w)

Area = (½)(12)(8 – 3y)

Area = 72 – 108w units²

Area = 6(8 – 3y)

Area = 48 – 18y units²

3x – (x + 7) coefficients: 10 & 3; constant terms: 7; simplified: 13x +7

3x + (-1)(x + 7)

3x + (-1x) + (-7)

2x + (-7)

Challenge

Homework coefficients: 10 & 3; constant terms: 7; simplified: 13x +7

Guided Practice

Text p. 81, #22-30 evens

-Text p.74, #12-48 evens

Distributive Property coefficients: 10 & 3; constant terms: 7; simplified: 13x +7Using Algebra Tiles

Write an expression for the area model.

=x

Use the distributive property

to simplify

=1

=

(x+2)

2x+4

2

=