1 / 31

Gases - PowerPoint PPT Presentation

  • Uploaded on

H 2. Gases. Gas Bag. Paris 1783. N 2. Chapter 10. Why gases are studied separately. Many common compounds exist as gases Gases transport matter and energy across the globe (i.e., weather) Compared with those of liquids and solids, the behavior of gases is easiest to model.

I am the owner, or an agent authorized to act on behalf of the owner, of the copyrighted work described.
Download Presentation

PowerPoint Slideshow about ' Gases' - lihua

An Image/Link below is provided (as is) to download presentation

Download Policy: Content on the Website is provided to you AS IS for your information and personal use and may not be sold / licensed / shared on other websites without getting consent from its author.While downloading, if for some reason you are not able to download a presentation, the publisher may have deleted the file from their server.

- - - - - - - - - - - - - - - - - - - - - - - - - - E N D - - - - - - - - - - - - - - - - - - - - - - - - - -
Presentation Transcript



Gas Bag

Paris 1783


Chapter 10

Why gases are studied separately
Why gases are studied separately

  • Many common compounds exist as gases

  • Gases transport matter and energy across the globe (i.e., weather)

  • Compared with those of liquids and solids, the behavior of gases is easiest to model.

Physical Characteristics of Gases

  • Gases assume the volume and shape of their containers.

  • Gases are the most compressible state of matter.

  • Gases will mix evenly and completely when confined to the same container. (No solubility rules!)

  • Gases have much lower densities than liquids and solids.

  • Density of a gas given in g/L (vice g/mL for liquids)





Fig. 10.2

760 mm Hg

Pressure =

(force = mass x acceleration)

Units of Pressure

1 pascal (Pa) = 1 N/m2

1 atm = 101,325 Pa = 101.325 kPa

1 atm = 760 mm Hg = 760 torr

Height of column ∝1/density

Pressure-Volume Relationship: Boyle’s Law

P1V1 = P2V2

  • Temperature-Volume Relationship: Charles’s Law

    V ∝ T

    Volume-Amount Relationship: Avogadro’s Law

    V ∝ n

    The Ideal Gas Law: PV = nRT

Add Hg

Add Hg

Add Hg

V decreases

As P (h) increases

Fig. 10.6

Boyle’s Law

Fig 10.7

Constant temperature

Constant amount of gas

P·V = constant

P1·V1 = P2·V2

(626 mm Hg) (500. mL)



355 mm Hg


A sample of argon gas occupies a volume of 500. mL at a pressure of 626 mm Hg. What is the volume of the gas (in mm Hg) if the pressure is reduced at constant temperature to 355 mm Hg?

P1 = 626 mm Hg

P2 = 356 mm Hg

V1 = 500. mL

V2 = ?

P1·V1 = P2·V2

V2 =

= 882 mL

As T increases

V increases

Variation of gas volume with temperature

at constant pressure: Charles’ Law

Fig 10.8

Temperature must be in Kelvin

T (K) = t (°C) + 273.15


V = constant ·T

Constant pressure

Constant amount of gas

6.60 L · 296.0 K



13.20 L


A sample of hydrogen gas occupies 13.20 L at 22.8 °C. At what temperature will the gas occupy half that volume if the pressure remains constant?

V1 = 13.20 L

V2 = 1.60 L

T1 = 296.0 K

T2 = ?

T1 = 22.8 (°C) + 273.15 (K) = 296.0 K

T2 =

= 148 K

148 K - 273.15 = -125 °C

Avogadro s law
Avogadro’s Law

Fig 10.10

V∝ number of moles (n)

V = constant ·n

Constant pressure

Constant temperature

Avogadro s hypothesis
Avogadro’s Hypothesis

Fig 10.11

Molar Volume

C3H8 + 5O2 3CO2 + 4H2O

1 mole C3H8 3 mole CO2

1 volume C3H8 3 volumes CO2

Propane burns in oxygen to form carbon dioxide and water vapor. How many volumes of carbon dioxide are obtained from one volume of propane at the same temperature and pressure?

At constant T and P

PV = nRT

The conditions 0 °C and 1 atm are called

standard temperature and pressure (STP).

Experiments show that at STP,

1 mole of an ideal gas

occupies 22.414 L:

Fig 10.13 Comparison of Molar Volumes at STP

  • One mole of an ideal gas occupies 22.41 L STP

  • One mole of various real gases at STP occupy:

(1 mol HCl)

V =

n = (49.8 g)

= 1.37 mol

(36.45 g HCl)

(1.37 mol)(0.08216 ) (273.15 K)

V =

1 atm





What is the volume (in liters) occupied by 49.8 g of HCl at STP?

T = 0 °C = 273.15 K

P = 1 atm

PV = nRT

V = 30.6 L

PV = nRT useful when P, V, n, and T do not change

Modify equation when P, V, and/or T change:

  • Initial state (1) of gas:

Combined Gas Law

  • Final state (2) of gas:

Eqn [10.8]








Density (d) Calculations

m is the mass of the gas in g

d =

MM is the molar mass of the gas

Molar Mass (MM) of a Gaseous Substance

d is the density of the gas in g/L

MM =

  • What happens to the density of a gas if:

  • it is heated at constant volume?

  • It is compressed at constant temperature?

  • Additional gas is added at constant volume?

What is the volume of CO2 produced at 37.0°C and 1.00 atm when 5.60 g of glucose are used up in the reaction:

C6H12O6 (s) + 6O2 (g) 6CO2 (g) + 6H2O (l)

6 mol CO2

g C6H12O6 mol C6H12O6 mol CO2V CO2


1 mol C6H12O6

1 mol C6H12O6


180 g C6H12O6




(0.1867 mol) (0.0821 ) (310.15 K)



1.00 atm

Volumes of Gases in Chemical Reations

= 0.1867 mol CO2

5.60 g C6H12O6

V =

= 4.75 L

Gas Mixtures and Partial Pressures

V and T are constant



Ptotal= P1 + P2

Dalton’s Law of Partial Pressures

PA =





PB =



nA + nB

nA + nB

XB =

XA =


mole fraction (Xi) =


Consider a case in which two gases, A and B, are in a container of volume V.

nA is the number of moles of A

nB is the number of moles of B

PT = PA + PB



Pi = Xi PT

Dalton’s Law of Partial Pressures

2KClO3 (s) 2KCl (s) + 3O2 (g)

PT = PO + PH O



Fig. 10.16 Collecting a water-insoluble gas over water

Bottle full of oxygen gas and water vapor

2KClO3 (s) 2KCl (s) + 3O2 (g)

PT = PO + PH O



Sample Exercise 10.12 p 413

A 0.811 g sample of KClO3 is partially decomposed to produce

oxygen gas over water. The volume of gas collected is 0.250 L

at 26 °C and 765 torr total pressure. How many grams of O2

are collected?


PO = - PH O



PV = nRT

Pressure of water vapor

vs temperature

App B p 1111

Kinetic Molecular Theory of Gases

  • A gas is composed of widely-separated molecules. The molecules can be considered to be points; that is, they possess mass but have negligible volume.

  • Gas molecules are in constant random motion.

  • Collisions among molecules are perfectly elastic.

  • The average kinetic energy of the molecules is proportional to the temperature of the gas in kelvins.

  • KE ∝ T

Fig 10.18 The Effect of Temperature on Molecular Speeds




Hot molecules are fast, cold molecules are slow.

The distribution of speeds

of three different gases

at the same temperature


urms =


Fig 10.19 The Effect of Molecular Mass on Molecular Speeds

R = 8.314 J/(mol K)

Heavy molecules are slow, light molecules are fast.

An ideal gas
An “Ideal Gas”

  • An ideal gas “obeys” PV = nRT

  • i.e., calculated value ≈ experimental value


  • Gas molecules do not exert any force (attractive or repulsive) on each other

    • i.e., collisions are perfectly elastic

  • Volume of molecules themselves is negligible compared to volume of container

    • i.e., the molecules are considered to be points

  • Deviations from ideal behavior
    Deviations from Ideal Behavior

    • Assumptions made in the kinetic-molecular model:

      • negligible volume of gas molecules themselves

      • no attractive forces between gas molecules

        These breakdown at high pressure and/or low temperature.