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A New Connection Between the Triangles of Stirling and Pascal

A New Connection Between the Triangles of Stirling and Pascal. Craig Bauer York College of PA. Pascal’s Triangle. Triangular Numbers. Tetrahedral Numbers. Pentatop Numbers. Row Sums – Powers of 2. Fibonacci Numbers. Hockey Stick Patterns. Picture from http://ptri1.tripod.com/.

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A New Connection Between the Triangles of Stirling and Pascal

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  1. A New Connection Between the Triangles of Stirling and Pascal Craig Bauer York College of PA

  2. Pascal’s Triangle

  3. Triangular Numbers

  4. Tetrahedral Numbers

  5. Pentatop Numbers

  6. Row Sums – Powers of 2

  7. Fibonacci Numbers

  8. Hockey Stick Patterns Picture from http://ptri1.tripod.com/

  9. Generating Function (x+1)n

  10. Shaded Modulo 2 Image from http://wyvern-community.school.hants.gov.uk/sierpinski.htm

  11. Mod 2 with More Rows Images from http://www.pittstate.edu/math/Cynthia/pascal.html

  12. Mod 3

  13. Mod 4

  14. Mod 5

  15. Mod 6

  16. Mod 7

  17. Investigate for Yourself! http://binomial.csuhayward.edu/applets /appletGasket.html

  18. Perfect Numbers

  19. Disclaimer But the sequence of the number of elements in each white triangle began with 1 and this isn’t a perfect number! That’s true, Pascal’s triangle doesn’t always yield perfect numbers in this manner, but every even perfect number does appear somewhere in this sequence. This is because the number of elements in each white triangle is given by 2n –1(2n – 1). With n = 1, we get 1. Making n = 2 or 3 gives 6 and 28, respectively. Every even perfect number is of this form, but not every number of this form is perfect. What about odd perfect numbers? Are there any? Nobody knows!

  20. A Simple Pattern For just one point, we cannot draw any lines, so have 1 region. For two points, we may draw a line to get 2 regions.

  21. A Simple Pattern For three points, we get 4 regions. For four points, we get 8 regions. For five points, we get 16 regions.

  22. Make a Prediction! We have the sequence 1, 2, 4, 8, 16, … What will the next term be?

  23. WRONG! References *I first saw the problem described above in The (Fabulous) Fibonacci Numbers by Alfred S. Posamentier and Ingmar Lehmann, Prometheus Books, June 2007. *A000127

  24. Partial Row Sums

  25. Some Formulas Recursive Non-recursive

  26. George Lilley, Pascal’s Arithmetic Triangle, American Mathematical Monthly, Vol. 1, No. 12, Dec., 1894, p.426. (Well over 200 years after Pascal’s death!)

  27. “This representation comes from China. It dates from a book of 1303 CE written by Chu Shï-kié. The earliest known use of the pattern was by Yang Hui, whose books date from 1261 & 1275 CE. Chu Shï-kié refers to the triangle as already being old. Jamshid Al-Kashi, who died around 1436 CE, was an astronomer at the court of Ulugh Beg in Samarkand in the 15th Century. Al-Kashi was the first known Arabic author to consider 'Pascal's' Triangle.” picture and text from: http://www.bbc.co.uk/education/asguru/maths/14statistics/03binomialdistribution/8binomialdistribution/index.shtml

  28. Stirling’s Triangle

  29. Where Does it Come From? • Answer #1 – In how many ways can a set of n distinct objects be split into k nonempty disjoint subsets? • Example: n=4 k=1 k=2 k=3 k=4

  30. Where Does it Come From? • Answer #2 – How can we express the nth power of x as a sum of “factorials”? • Example: x4 • x4 = 1x(x – 1)(x – 2)(x – 3) • +6x(x – 1)(x – 2) • +7x(x – 1) • +1x • Coefficients are: 1 6 7 1

  31. Row Sums – Bell Numbers

  32. Exponential Generating Function

  33. Some Formulas Recursive Non-recursive

  34. Stirling’s Triangle mod 2

  35. Stirling’s Triangle mod 3

  36. Stirling’s Triangle mod 3 Eighty rows of Stirling Numbers of the second kind mod 3 From http://www.cecm.sfu.ca/~loki/Papers/Numbers/node7.html Note: This illustration starts with n heap 0 = 0 for each row.

  37. Stirling’s Triangle mod 4

  38. Stirling’s Triangle mod 5

  39. And now for something completely different…

  40. Upper TriangularPartial PermutationMatrices At most a single 1 in any row or column. No 1s below the main diagonal.

  41. Examples 1 by 1 only 2 possibilities

  42. Examples 2 by 2 only 5 possibilities

  43. Examples • 3 by 3 • only 15 possibilities

  44. Sorted by Dimension & Rank

  45. A New Twist k=1 k=2 k=3 Insist on k extra diagonals of 0s above the main diagonal.

  46. Counting by Rank (k=1)

  47. A Simple Rule P(n,k) = P(n – 1,k) +(n – k)P(n – 1,k – 1) +P(n – 2,k – 2)

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