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Jeffrey Santos. AP Calculus FRQ Year 2008 #5. The Question?. A.) Find the Area of R. Using the graphing calculator, we find the intersection points of y=lnx and y=x-2. The intersection points of the graph are when x=.15859 and 3.14619. (Let A=.15859 and B=3.14619). Which then equals to:.

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Jeffrey santos

Jeffrey Santos

AP Calculus FRQ

Year 2008

#5


The question

The Question?


A find the area of r

A.) Find the Area of R

  • Using the graphingcalculator, we find the intersection points of y=lnx and y=x-2

The intersection points of the graph are when x=.15859 and 3.14619. (Let A=.15859 and B=3.14619)

Which then equals to:

To find the area of R, we do:

1.949

Plug in the formula to get:


B find the volume of the solid generated when r is rotated about the horizontal line y 3

B.) Find the volume of the solid generated when R isrotated about the horizontal line y=-3

  • Using the washer method, (since there two functions) from point A to B we get:

Use graphing calculator and you get:

34.199


Jeffrey santos

C.) Write, but do not evaluate, and integral expression that can be used to find the volume of the solid generated when R is rotated about the y-axis.

  • Since it is rotated over the y-axis, we set both functions equal to X in terms of Y.

  • Y=ln(x) becomes

  • Y=X-2 becomes

The new graph has two new intersection points, which are:

Where

x=1.1461

Where

X= -1.8414


Part c continued

Part C. Continued

We plug it back into the

Washer Method formula.

  • With the new intersection points:

    x=1.1461(D) and -1.8414 (C).

    And the new functions:

We then get the formula:

and


Any questions

Any Questions?!


Citations

Citations:

  • http://apcentral.collegeboard.com/apc/public/repository/_ap06_frq_calculusab_51707.pdf for the problem.


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